Problem 8
Question
Suppose \(X\) is a random variable with mean \(-5\) and variance \(2 .\) What can you say about the probability that \(X\) deviates from its mean by at least \(4 ?\)
Step-by-Step Solution
Verified Answer
The probability is at most \(\frac{1}{8}\).
1Step 1: Identify the Given Parameters
We are given that the mean of the random variable \(X\) is \(-5\) and the variance is \(2\). The standard deviation \(\sigma\) is the square root of the variance, so it is \(\sqrt{2}\).
2Step 2: Express the Deviation Condition
We need to find the probability that the absolute deviation \(|X + 5|\) is greater than or equal to 4. This is equivalent to calculating \(P(|X - (-5)| \geq 4)\).
3Step 3: Apply Chebyshev's Inequality
Chebyshev's inequality states that for any random variable \(X\) with mean \(\mu\) and standard deviation \(\sigma\), \(P(|X - \mu| \geq k\sigma) \leq \frac{1}{k^2}\) for \(k > 0\).
4Step 4: Calculate the Bound Using Chebyshev's Inequality
In this context, \(k\) can be calculated as \(\frac{4}{\sqrt{2}} = 2\sqrt{2}\). According to Chebyshev's inequality, \(P(|X - (-5)| \geq 4) \leq \frac{1}{(2\sqrt{2})^2} = \frac{1}{8}\).
5Step 5: Interpret the Result
The probability that \(X\) will deviate from its mean by at least 4 is at most \(\frac{1}{8}\), or 0.125.
Key Concepts
Understanding Random VariablesExploring Mean and VarianceGrasping Standard Deviation
Understanding Random Variables
A random variable is a foundational concept in probability and statistics that helps us quantify outcomes of a random phenomenon. Imagine rolling a dice. The result—whether it's a 1, 2, or up to 6—is what we call a random variable. This result can vary every time you roll. Random variables are crucial because they connect real-life random situations to mathematical expressions.
There are two types of random variables you might encounter:
There are two types of random variables you might encounter:
- Discrete Random Variables: These have a countable number of possible values. For example, the number of heads when flipping a coin multiple times.
- Continuous Random Variables: These can take any value within a given range. For instance, the exact time it takes to complete a 100-meter race.
Exploring Mean and Variance
The mean and variance are critical statistical elements that offer insights into a random variable's behavior.
- Mean: Often called the average, the mean is a measure of the central tendency of a random variable. It gives a sense of where most of the data points fall. In the provided exercise, the mean of the random variable X is -5. This implies that, on average, the outcomes tend to cluster around this value.
- Variance: While the mean gives a central location, the variance tells us how spread out the values are from the mean. A larger variance indicates that the data points are more spread out. In our case, the variance is 2, indicating moderate spread around the mean of -5.
Grasping Standard Deviation
The standard deviation is a statistical measure that builds on the variance to provide a clear, interpretable measure of spread or dispersion of a dataset or random variable. Simply put, while variance is informative, standard deviation gives this information in the same units as the data, making it easier to understand.
- Calculation: The standard deviation is the square root of the variance. In our example, the variance is 2, so the standard deviation is \( \sqrt{2} \), simplifying to about 1.41.
- Interpretation: This value tells us that, on average, the values of the random variable X deviate from the mean (-5) by approximately 1.41 units. Standard deviation thus quantifies variability and helps in comparing different datasets.
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