Problem 8
Question
Suppose we want to dissolve a gaseous solute in water. Would you expect \(\Delta E_{\text {solute separation }}\) to be larger for the gaseous solute or for a solid ionic solute? Explain.
Step-by-Step Solution
Verified Answer
We would expect ΔE (solute separation) to be larger for a solid ionic solute than for a gaseous solute. This is because the particles in a gaseous solute are held together by weak intermolecular forces (van der Waals forces), while solid ionic solutes are held together by strong electrostatic forces (ionic bonds). Dissolving a solid ionic solute requires breaking these strong bonds, leading to a higher energy change compared to the relatively small energy change needed for separating the weakly bound particles in a gaseous solute.
1Step 1: Understand the concept of solute separation
Before moving on to the comparisons, we need to understand solute separation. Solute separation happens when a solute dissolves in a solvent, breaking the intermolecular forces holding its particles together. During this process, energy is either absorbed or released.
2Step 2: Gaseous solute
For a gaseous solute, the intermolecular forces between the particles are weak (van der Waals forces or dispersion forces). When a gas dissolves in a solvent like water, it forms weak interactions with the water molecules, which are primarily the London dispersion forces. As a result, the energy change (ΔE) required for solute separation will generally be small for gaseous solutes.
3Step 3: Solid ionic solute
In the case of a solid ionic solute, the particles are held together by strong electrostatic forces (ionic bonds). When an ionic solid is dissolved in water, the water molecules will need to break these strong bonds to separate the ions. This process requires a significant amount of energy to be absorbed for solute separation, making the change in energy (ΔE) larger.
4Step 4: Comparing the energy change
When comparing the gaseous solute and the solid ionic solute, we must consider the intermolecular forces holding their particles together. As previously mentioned, gaseous solutes have weak intermolecular forces (van der Waals forces), whereas solid ionic solutes have strong electrostatic forces (ionic bonds).
In the dissolving process, a gaseous solute will require less energy to separate its particles due to weak forces. On the other hand, a significant amount of energy is needed to break the strong bonds in a solid ionic solute, leading to a higher energy change. Consequently, we would expect ΔE (solute separation) to be larger for a solid ionic solute compared to a gaseous solute.
Key Concepts
Intermolecular ForcesGaseous SoluteSolid Ionic SoluteEnergy Change
Intermolecular Forces
Intermolecular forces are the forces that hold particles together within a substance. These forces can be strong or weak based on the nature of the solute. Understanding these forces is crucial in predicting how substances behave when dissolved.
For gaseous solutes, the intermolecular forces are typically weak. They might be in the form of van der Waals forces or specifically, London dispersion forces. These are temporary attractions that occur between atoms or molecules.
In contrast, solid ionic solutes have much stronger forces, known as ionic bonds. Ionic bonds are electrostatic forces that occur between positively and negatively charged ions. They are significantly stronger than the forces between gaseous particles.
Recognizing these differences helps us understand why various amounts of energy are required to dissolve different types of solutes.
For gaseous solutes, the intermolecular forces are typically weak. They might be in the form of van der Waals forces or specifically, London dispersion forces. These are temporary attractions that occur between atoms or molecules.
In contrast, solid ionic solutes have much stronger forces, known as ionic bonds. Ionic bonds are electrostatic forces that occur between positively and negatively charged ions. They are significantly stronger than the forces between gaseous particles.
Recognizing these differences helps us understand why various amounts of energy are required to dissolve different types of solutes.
Gaseous Solute
A gaseous solute, when dissolved, needs to separate its particles from each other due to their initial weak attractions. Gases already have particles that are far apart compared to solids, which makes them easier to separate.
Generally, the process of dissolving a gas involves minimal energy input. This is because the weak intermolecular forces, like dispersion forces, are easier to overcome. As a result, the energy change (\( \Delta E \)) for a gaseous solute during dissolution is small.
This can make gaseous solutes easier to manage in solutions, especially when comparing them to solid solutes that require much more energy to dissolve.
Generally, the process of dissolving a gas involves minimal energy input. This is because the weak intermolecular forces, like dispersion forces, are easier to overcome. As a result, the energy change (\( \Delta E \)) for a gaseous solute during dissolution is small.
This can make gaseous solutes easier to manage in solutions, especially when comparing them to solid solutes that require much more energy to dissolve.
Solid Ionic Solute
When dealing with a solid ionic solute, dissolution involves separating ions that are initially held tightly together by ionic bonds. These bonds form due to the strong attraction between oppositely charged ions.
The dissolution of a solid ionic compound requires considerable energy to overcome these strong interactions. Water or another solvent must break these bonds to integrate the ions into the solution.
Because of this, the energy change (\( \Delta E \)) during the dissolution of a solid ionic solute is much larger than for gases. The requirement for higher energy input comes from needing to overcome the strong ionic bonds.
The dissolution of a solid ionic compound requires considerable energy to overcome these strong interactions. Water or another solvent must break these bonds to integrate the ions into the solution.
Because of this, the energy change (\( \Delta E \)) during the dissolution of a solid ionic solute is much larger than for gases. The requirement for higher energy input comes from needing to overcome the strong ionic bonds.
Energy Change
Energy change during the dissolution process is an essential factor for understanding solubility. When a substance dissolves, energy is either absorbed or released, known as enthalpy change (\( \Delta H \)).
For gaseous solutes, the energy change is minimal due to weak intermolecular forces. Consequently, the solute easily integrates into the solution without the need for much energy consumption.
Solid ionic solutes, however, require a lot more energy to dissolve, given their robust ionic bonds. The large energy change indicates the substantial energy input required to break these bonds before the ions can disperse into the solvent.
Understanding energy changes provides insight into the feasibility and spontaneity of solute dissolution in different solvents.
For gaseous solutes, the energy change is minimal due to weak intermolecular forces. Consequently, the solute easily integrates into the solution without the need for much energy consumption.
Solid ionic solutes, however, require a lot more energy to dissolve, given their robust ionic bonds. The large energy change indicates the substantial energy input required to break these bonds before the ions can disperse into the solvent.
Understanding energy changes provides insight into the feasibility and spontaneity of solute dissolution in different solvents.
Other exercises in this chapter
Problem 6
Based on the answer to Practice Problem \(12.4\), is the energy required for solute separation greater for \(\mathrm{NaCl}\) or \(\mathrm{MgCl}_{2}\) ? Explain.
View solution Problem 7
For a given solute in water, the energy changes are \(\Delta E_{\text {solute separation }}=835 \mathrm{~kJ}\), \(\Delta E_{\text {solvent separation }}=98 \mat
View solution Problem 9
The more negative \(\Delta E_{\text {solvation }}\) is, the more likely a solute will dissolve. Explain.
View solution Problem 10
Suppose you want to dissolve some \(\mathrm{MgCl}_{2}\) in water. (a) How do we know that magnesium cations have a \(+2\) charge? (b) \(\Delta E_{\text {solute
View solution