Problem 8
Question
Solve each equation. Be sure to check each solution. $$ -3 a-6=9 $$
Step-by-Step Solution
Verified Answer
The solution is \(a = -5\).
1Step 1: Add 6 to Both Sides
The equation given is \(-3a - 6 = 9\). To isolate the term with \(a\), first add 6 to both sides of the equation. By doing this, we get: \(-3a - 6 + 6 = 9 + 6\), which simplifies to \(-3a = 15\).
2Step 2: Divide by -3
Now that we have \(-3a = 15\), divide both sides by -3 to solve for \(a\). This gives us: \(a = \frac{15}{-3}\), which simplifies to \(a = -5\). So, \(a = -5\) is our solution.
3Step 3: Check the Solution
To ensure the solution is correct, substitute \(a = -5\) back into the original equation \(-3a - 6 = 9\). Substitute \(-5\) for \(a\): \(-3(-5) - 6\). This simplifies to \(15 - 6\), which equals 9. Since both sides of the equation are equal after substitution, the solution \(a = -5\) is verified to be correct.
Key Concepts
Checking SolutionsIsolation of VariablesEquation SimplificationDivision in Algebra
Checking Solutions
Once you've found a possible solution to an equation, it's crucial to confirm that it’s correct. This process is known as "checking solutions." It ensures you haven't made any errors during the solving steps.
To check a solution:
It gives you peace of mind knowing that your answer is accurate.
To check a solution:
- Substitute the solution back into the original equation.
- Simplify both sides to see if they are equal.
- If both sides match, the solution is correct. If not, re-evaluate your steps.
It gives you peace of mind knowing that your answer is accurate.
Isolation of Variables
Isolating the variable is a key step in solving linear equations. It means getting the unknown variable, often represented as 'x', 'y', or another letter, by itself on one side of the equation.
To isolate a variable effectively:
Tackling each term one at a time makes the process manageable and less prone to mistakes.
To isolate a variable effectively:
- Perform operations to both sides of the equation that help you clean up terms not attached to the variable.
- Use addition, subtraction, multiplication, or division strategically to move terms across the equals sign.
Tackling each term one at a time makes the process manageable and less prone to mistakes.
Equation Simplification
Equation simplification is about making equations easier to solve by taking them down to their simplest form. This involves combining like terms and reducing equations so that solving them becomes straightforward.
In the given exercise:
In the given exercise:
- After adding 6 to both sides, the equation \(-3a = 15\) is much simpler to work with than the original.
- Always perform the same operation on both sides to maintain the equation's balance.
- Simplification may involve several steps, so proceed methodically.
Division in Algebra
Division in algebra comes in handy when you’re down to the final step of isolating a variable. When a variable is multiplied by a coefficient, division allows you to solve that multiplication by finding the reciprocal operation.
For instance, in the equation \(-3a = 15\), dividing both sides by \(-3\) gives you the solution for \('a'\).
Here's how:
Practicing these steps regularly will improve your proficiency in handling and solving linear equations with skill.
For instance, in the equation \(-3a = 15\), dividing both sides by \(-3\) gives you the solution for \('a'\).
Here's how:
- Divide each term by the coefficient of the variable (in this case, -3).
- Simplify the fraction if possible to get your final answer.
Practicing these steps regularly will improve your proficiency in handling and solving linear equations with skill.
Other exercises in this chapter
Problem 8
If five more than three times a number is thirty-two, what is the number?
View solution Problem 8
Find the value of each expression. $$ -a^{2}+3 a+4, \text { if } a=4. $$
View solution Problem 8
$$-1+7=x+3$$
View solution Problem 8
Simplify each expression by combining like terms. $$6 h-2 h$$
View solution