Problem 8
Question
Rewrite the logarithm as a ratio of (a) common logarithms and (b) natural logarithms. $$\log _{3} 47$$
Step-by-Step Solution
Verified Answer
So, the logarithm \(\log _{3} 47\) can be rewritten as \(\frac{\log_{10} 47}{\log_{10} 3}\) in terms of common logarithms and as \(\frac{\ln 47}{\ln 3}\) in terms of natural logarithms.
1Step 1: Apply the change of base formula with base 10
We apply the change of base formula to rewrite \(\log _{3} 47\) in terms of common logarithms (base 10). We follow the formula \(\log_b a = \frac{\log_c a}{\log_c b}\) with \(a = 47\), \(b = 3\) and \(c = 10\). Therefore, \(\log _{3} 47\) becomes \(\frac{\log_{10} 47}{\log_{10} 3}\).
2Step 2: Simplify the ratio of logarithms
We cannot simplify the expression further because logarithms of 47 and 3 are irrational numbers. Therefore, \(\frac{\log_{10} 47}{\log_{10} 3}\) is the simplified ratio of common logarithms.
3Step 3: Apply the change of base formula with base e
Now, we rewrite \(\log _{3} 47\) in terms of natural logarithms (base \(e\)). We apply the change of base formula, this time letting \(c = e\). Thus, \(\log _{3} 47\) becomes \(\frac{\ln 47}{\ln 3}\).
4Step 4: Simplify the ratio of natural logarithms
We cannot simplify the expression further because natural logarithms of 47 and 3 are irrational numbers. Therefore, \(\frac{\ln 47}{\ln 3}\) is the simplified form of natural logarithms.
Key Concepts
Change of Base FormulaCommon LogarithmsNatural Logarithms
Change of Base Formula
Logarithms can often be tricky to work with, especially when dealing with different bases. Luckily, the change of base formula is a handy tool that helps to convert logarithms from one base to another. This can make calculations simpler and more manageable. The formula is written as follows:
- \( \log_b a = \frac{\log_c a}{\log_c b} \)
- \( \log_3 47 = \frac{\log_{10} 47}{\log_{10} 3} \)
Common Logarithms
Common logarithms are logarithms that use base 10. They are widely used in scientific calculations. The notation is quite straightforward: \( \log_{10} a \) can simply be written as \( \log a \). Simply using \( \log \) to imply base 10 is a common mathematical shorthand.One reason for the pervasive use of common logarithms is their simplicity and the fact that they are easily programmable into calculators. In real-world applications, many systems and phenomena scale by powers of 10, making the common logarithm very useful.Let's look at an example:
- To rewrite \( \log_3 47 \) using common logarithms, apply the formula: \( \log_3 47 = \frac{\log_{10} 47}{\log_{10} 3} \).
Natural Logarithms
Natural logarithms are based on the mathematical constant \( e \), which is approximately equal to 2.71828. The symbol for natural logarithms is \( \ln \). Natural logarithms are important in mathematics, especially in calculus and scientific contexts because they relate directly to exponential growth processes.The change of base formula can also be applied to convert logarithms to a natural base:
- For example, \( \log_3 47 \) becomes \( \frac{\ln 47}{\ln 3} \).
Other exercises in this chapter
Problem 7
Evaluate the function at the indicated value of \(x\). Round your result to three decimal places. $$ \begin{aligned} &\text { Function } \quad \text { Valu }\\\
View solution Problem 8
Determine whether each \(x\) -value is a solution (or an approximate solution) of the equation. \(4 e^{x-1}=60\) (a) \(x=1+\ln 15\) (b) \(x \approx 3.7081\) (c)
View solution Problem 8
Write the logarithmic equation in exponential form. For example, the exponential form of \(\log _{5} 25=2\) is \(5^{2}=25\). $$\log _{7} 343=3$$
View solution Problem 8
Evaluate the function at the indicated value of \(x\). Round your result to three decimal places. $$ \begin{aligned} &\text { Function } \quad \text { Valu }\\\
View solution