Problem 8
Question
Match the equation in Column I with its solution(s) in Column II. Do not use a calculator. (II) A. \(\pm 2 i\), B. \(\pm 2 \sqrt{2}\), C. \(\pm i \sqrt{2}\), D. 2, E. \(\pm \sqrt{2}\), F. \(-2\), G. \(\pm 2\), H. \(\pm 2 i \sqrt{2}\) (I) $$x+2=0$$
Step-by-Step Solution
Verified Answer
The solution to \(x + 2 = 0\) is F: \(-2\).
1Step 1: Understand the Equation
The equation given is \( x + 2 = 0 \). This is a simple linear equation with one variable. Our goal is to isolate \( x \) on one side of the equation to find its value.
2Step 2: Solve the Equation
To solve \( x + 2 = 0 \), we need to isolate \( x \) by subtracting 2 from both sides of the equation. This gives us \( x = 0 - 2 \), which simplifies to \( x = -2 \).
3Step 3: Match the Solution with Column II
Now that we have found \( x = -2 \), we look for \(-2\) in Column II. We see that option F in Column II matches \(-2\).
Key Concepts
Linear EquationsMatching SolutionsEducational Exercises
Linear Equations
Linear equations, like the one from our example (\( x + 2 = 0 \)), are basic mathematical expressions that involve variables with no exponents or powers higher than one. They capture the essence of balancing two sides by performing operations that impact both sides equally.
Understanding linear equations is crucial as it develops the student's capability to solve real-world problems where relationships are linear. Consider it as finding the weight of an unknown item to achieve balance; our mission is to isolate the unknown variable, in this case, \( x \), to find its value. This involves straightforward techniques such as addition, subtraction, multiplication, or division.
Here's how to solve one:
Understanding linear equations is crucial as it develops the student's capability to solve real-world problems where relationships are linear. Consider it as finding the weight of an unknown item to achieve balance; our mission is to isolate the unknown variable, in this case, \( x \), to find its value. This involves straightforward techniques such as addition, subtraction, multiplication, or division.
Here's how to solve one:
- Identify the equation and locate the variable. In our case, it’s \( x \).
- Eliminate any constants on the side of the variable by performing the opposite mathematical operation. For \( x + 2 = 0 \), we subtract 2 from both sides.
- Solve for the variable. We end up with \( x = -2 \).
Matching Solutions
Matching solutions involves not only solving an equation but also correctly identifying the result within a set of possible answers. This exercise is important for practicing solution recognition as it ensures better understanding and accuracy in math.
Once you solve an equation, the next step is to compare the solution against a list of potential results, as provided in exercises like this one. For the equation \( x + 2 = 0 \), we found that \( x = -2 \).
In the list provided in the original exercise (Column II), you would look for \( -2 \). This kind of matching can strengthen your ability to quickly recognize correct answers. Here’s a simple approach:
Once you solve an equation, the next step is to compare the solution against a list of potential results, as provided in exercises like this one. For the equation \( x + 2 = 0 \), we found that \( x = -2 \).
In the list provided in the original exercise (Column II), you would look for \( -2 \). This kind of matching can strengthen your ability to quickly recognize correct answers. Here’s a simple approach:
- Solve the equation confidently, like how we isolated \( x = -2 \).
- Skim through the possible answers presented, searching for your solution.
- Mark the matching option, which in our exercise was \( -2 \) or "F" from Column II.
Educational Exercises
Educational exercises, particularly in mathematics, are more than just problems to be solved—they are dynamic learning tools. They build critical-thinking skills, improve problem-solving capabilities, and promote retention of knowledge through practice and application.
These types of exercises, such as solving and matching solutions for linear equations, provide a structured way for learners to engage with the content actively. They compel students to process information step-by-step, reinforcing each concept as it appears.
Here's how such exercises benefit learners:
These types of exercises, such as solving and matching solutions for linear equations, provide a structured way for learners to engage with the content actively. They compel students to process information step-by-step, reinforcing each concept as it appears.
Here's how such exercises benefit learners:
- Reinforcement through practice: Frequent exposure helps internalize mathematical processes.
- Confidence building: Successfully matching solutions enhances self-assurance in mathematical tasks.
- Skill improvement: Continuous practice develops better problem-solving skills.
Other exercises in this chapter
Problem 8
Find a polynomial function \(P(x)\) of degree 3 with real coefficients that satisfies the given conditions. Do not use a calculator. Zeros of \(1,-1,\) and \(0
View solution Problem 8
Each expression. Apply the property \(\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}\) if necessary. Do not use a calculator. $$\frac{7 x^{8}-6 x^{3}}{6 x^{2}}$$
View solution Problem 8
Solve each problem. Do not use a calculator. $$\text { Solve } \frac{1}{4} x^{2}+x=1$$
View solution Problem 8
For each quadratic function defined , (a) write the function in the form \(P(x)=a(x-h)^{2}+k,\) (b) give the vertex of the parabola, and (c) graph the function.
View solution