Problem 8
Question
Match each equation in Column I with the appropriate description in Column II. Do not use a calculator. A. Hyperbola; center \((2,4)\) B. Ellipse; foci \((\pm 2 \sqrt{3}, 0)\) C. Hyperbola; foci \((0, \pm 2 \sqrt{5})\) D. Hyperbola; center \((-2,4)\) E. Ellipse; center \((-2,4)\) F. Center \((0,0) ;\) horizontal transverse axis G. Ellipse; foci \((0, \pm 2 \sqrt{3})\) H. Vertical major axis; center \((2,-4)\) $$\frac{(x-2)^{2}}{9}-\frac{(y-4)^{2}}{25}=1$$
Step-by-Step Solution
Verified Answer
A: Hyperbola; center \((2,4)\).
1Step 1: Identify the Conic Section
The given equation is \( \frac{(x-2)^{2}}{9} - \frac{(y-4)^{2}}{25} = 1 \). The standard form of a hyperbola is \( \frac{(x-h)^{2}}{a^{2}} - \frac{(y-k)^{2}}{b^{2}} = 1 \) or \( \frac{(y-k)^{2}}{a^{2}} - \frac{(x-h)^{2}}{b^{2}} = 1 \). Since the equation has the subtraction sign in between, it is a hyperbola.
2Step 2: Determine the Center
The center \((h, k)\) of the hyperbola can be identified from the equation \( \frac{(x-2)^{2}}{9} - \frac{(y-4)^{2}}{25} = 1 \) as \((2, 4)\).
3Step 3: Confirm Orientation
For the given hyperbola \( \frac{(x-2)^{2}}{9} - \frac{(y-4)^{2}}{25} = 1 \), as the \(x\) term is positive, this hyperbola opens left and right, confirming a horizontal transverse axis.
4Step 4: Match with Given Descriptions
The hyperbola has a center at \((2, 4)\), and it opens horizontally, as calculated. This matches description A: Hyperbola; center \((2,4)\).
Key Concepts
HyperbolaCenter of HyperbolaEquation of Conic Sections
Hyperbola
Hyperbolas are fascinating and highly useful shapes found within the broader study of conic sections. A hyperbola is defined as the set of all points in the plane where the absolute difference of the distances from two foci is constant. This distinct path creates a set of curves that open outward, away from each other, in two distinct branches.
These curves are often seen in various real-world applications, such as in navigation and radio signals, where the properties of hyperbolas have practical uses.A hyperbola contains two axes:
These curves are often seen in various real-world applications, such as in navigation and radio signals, where the properties of hyperbolas have practical uses.A hyperbola contains two axes:
- The transverse axis – the line segment connecting the vertices of the hyperbola, determined by the positioning and orientation of the hyperbola.
- The conjugate axis – perpendicular to the transverse axis and helps in defining the complete shape.
- \[ \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \] – here, the transverse axis is horizontal.
- \[ \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 \] – here, the transverse axis is vertical.
Center of Hyperbola
The center of a hyperbola is a significant starting point that guides the formation of the hyperbola's curves. This center is mathematically denoted as \(h, k\) and can be identified from the standard form of the hyperbola equation. By analyzing where the equation's variables are shifted, one can pinpoint this essential center.
For example, in the equation \[ \frac{(x-2)^2}{9} - \frac{(y-4)^2}{25} = 1 \], the center is located at \(2, 4\). These coordinates act as a balance point from which the hyperbola opens symmetrically in opposite directions.To determine the center:
For example, in the equation \[ \frac{(x-2)^2}{9} - \frac{(y-4)^2}{25} = 1 \], the center is located at \(2, 4\). These coordinates act as a balance point from which the hyperbola opens symmetrically in opposite directions.To determine the center:
- Identify the constants \(h\) and \(k\) in the equation \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \).
- These values represent horizontal and vertical shifts from the origin (0,0).
- The center guides the intersection of the transverse and conjugate axes.
Equation of Conic Sections
Conic sections comprise important geometric shapes, including circles, ellipses, parabolas, and hyperbolas. Each type has its characteristic equation, determined by slicing cones at varying angles. These equations not only define the shapes but also unlock a world of analytical geometry useful in multiple fields like astronomy and engineering.
Common characteristics of conic section equations:
Common characteristics of conic section equations:
- Circles: The simplest form, where the distance from the center to any point on the perimeter is constant, given by \((x-h)^2 + (y-k)^2 = r^2\).
- Ellipses: Defined by the sum of distances to two foci being constant, represented by \[ \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \].
- Parabolas: Characterized by a single focal point, leading to the equation form \((x-h)^2 = 4p(y-k)\) or \((y-k)^2 = 4p(x-h)\).
- Hyperbolas: As previously conveyed, recognizable by the equation \[ \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \] with distinguishing subtraction.
Other exercises in this chapter
Problem 8
For each plane curve, use a graphing calculator to generate the curve over the interval for the parameter \(t\), in the window specified. Then, find a rectangul
View solution Problem 8
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summ
View solution Problem 8
Skills Match each equation in Column I with the appropriate description in Column II. Do not use a calculator. A. Circle; center \((3,-4) ;\) radius 5 B. Parabo
View solution Problem 9
Explain how a circle can be interpreted as a special case of an ellipse.
View solution