Problem 8
Question
Label each statement true or false. The sum of two pure imaginary numbers is always a pure imaginary number.
Step-by-Step Solution
Verified Answer
True.
1Step 1: Understanding Pure Imaginary Numbers
A pure imaginary number is of the form \( bi \), where \( b \) is a non-zero real number, and \( i \) is the imaginary unit, such that \( i^2 = -1 \). In this context, examples include \( 3i, -7i, \) and so on.
2Step 2: Setting Up the Problem
Suppose we have two pure imaginary numbers \( a = bi \) and \( c = di \), where \( b \) and \( d \) are real numbers. Their sum is \( a + c = bi + di \).
3Step 3: Adding Pure Imaginary Numbers
The sum \( a + c = bi + di = (b+d)i \) can still be expressed in the pure imaginary form \( ei \), where \( e = b + d \). Since \( b \) and \( d \) are real numbers, \( e \) is also real.
4Step 4: Conclusion Based on Calculation
Because \( (b+d)i \) is a pure imaginary number as long as \( e = b + d eq 0 \) (though it includes zero, which is often treated as not being pure imaginary for strict definitions), the sum is typically still considered a pure imaginary number. Therefore, the statement is true.
Key Concepts
Imaginary UnitComplex NumbersAddition of Imaginary Numbers
Imaginary Unit
The imaginary unit, represented by the symbol \( i \), is a fundamental concept in mathematics, especially useful when dealing with complex numbers. In essence, the imaginary unit \( i \) is defined such that \( i^2 = -1 \). This might seem peculiar at first, since we are accustomed to the idea that squaring a real number always yields a non-negative value. However, the brilliance of \( i \) is exactly in this defiance of conventional algebraic rules, making it possible to solve equations that otherwise would have no real solutions, such as \( x^2 + 1 = 0 \).
Using \( i \), mathematicians unlocked a whole new number system that extends our comprehension of numbers beyond the real line. This allows us to perform various calculations that rely on this imaginary aspect, serving as a building block for the broader concept of complex numbers.
Using \( i \), mathematicians unlocked a whole new number system that extends our comprehension of numbers beyond the real line. This allows us to perform various calculations that rely on this imaginary aspect, serving as a building block for the broader concept of complex numbers.
Complex Numbers
Complex numbers are numbers that have both a real part and an imaginary part, typically expressed in the form \( a + bi \), where \( a \) and \( b \) are real numbers and \( i \) is the imaginary unit. This form elegantly captures numbers on a different plane known as the complex plane, where the horizontal axis represents the real part and the vertical axis represents the imaginary part.
- The number \( a \) is called the real part.
- The number \( b \) is called the imaginary part, primarily because it is paired with \( i \).
Addition of Imaginary Numbers
The addition of imaginary numbers, specifically pure imaginary numbers, is both interesting and conceptually straightforward. Pure imaginary numbers are in the form \( bi \), where \( b \) is a non-zero real number. When you add two pure imaginary numbers, say \( bi \) and \( di \), the result is \((b+d)i\).
Here's how the addition works:
Here's how the addition works:
- Consider two pure imaginary numbers: \( a = bi \) and \( c = di \).
- When these are added: \( a + c = bi + di \).
- This simplifies to \( (b + d)i \), which is also in the form of a pure imaginary number.
Other exercises in this chapter
Problem 8
Solve each quadratic equation by using (a) the factoring method and (b) the method of completing the square. $$x(x-1)=30$$
View solution Problem 8
Solve each of the quadratic equations by factoring and applying the property, \(a b=0\) if and only if \(a=0\) or \(b=0\). If necessary, return to Chapter 3 and
View solution Problem 9
Solve each inequality and graph its solution set on a number line. $$(x+1)(x-1)(x-3)>0$$
View solution Problem 9
Solve each quadratic equation using the method that seems most appropriate to you. $$135+24 n+n^{2}=0$$
View solution