Problem 8
Question
In which of the following compounds will the bond angle be maximum? (a) \(\mathrm{NH}_{3}\) (b) \(\mathrm{NH}_{4}^{+}\) (c) \(\mathrm{PCl}_{3}\) (d) \(\mathrm{SCl}_{2}\)
Step-by-Step Solution
Verified Answer
The maximum bond angle is in 60;NH_{4}^{+}7 with 60;109.5^{3circ}7.
1Step 1: Identify the Electron Geometry
To determine the bond angle, we first need to understand the electron geometry of each compound.
- 60;NH_{3}7 is pyramidal due to one lone pair and three bonds, leading to 60;sp^37 hybridization.
- 60;NH_{4}^{+}7 is tetrahedral with no lone pairs, also having 60;sp^37 hybridization.
- 60;PCl_{3}7 is also pyramidal with one lone pair and three bonds.
- 60;SCl_{2}7 is bent, as it has two lone pairs and two bond pairs.
2Step 2: Determine the Ideal Bond Angles
Now, let's consider the theoretical bond angles for different geometries:
- Tetrahedral structures, like 60;NH_{4}^{+}7, have a bond angle of 60;109.5^{3circ}7.
- Pyramidal structures, as in 60;NH_{3}7 and 60;PCl_{3}7, typically have slightly less than 60;109.5^{3circ}7 due to lone pair repulsion, approximately 60;107^{3circ}7.
- Bent structures, like 60;SCl_{2}7, have even smaller angles, usually around 60;104.5^{3circ}7.
3Step 3: Compare Theoretical Angles
By comparing the ideal bond angles:
- 60;NH_{4}^{+}7 with 60;109.5^{3circ}7.
- 60;NH_{3}7 and 60;PCl_{3}7 both with 60;107^{3circ}7.
- 60;SCl_{2}7 with 60;104.5^{3circ}7.
It is clear that 60;NH_{4}^{+}7 has the largest bond angle.
Key Concepts
Electron GeometryHybridizationTetrahedral StructurePyramidal StructureBent Structure
Electron Geometry
Electron geometry is a foundational concept in understanding molecular shapes and bond angles. It refers to the spatial arrangement of all electron pairs (including bonding pairs and lone pairs) around the central atom in a molecule. This geometry plays a pivotal role in defining the overall molecular shape.
- For molecules with two areas of electron density, the geometry is linear.
- Three areas lead to a trigonal planar geometry.
- Four areas of electron density create a tetrahedral geometry, which is relevant in our current discussion.
Hybridization
Hybridization is the process of mixing atomic orbitals into new hybrid orbitals. This process helps in forming covalent bonds in molecules and influences molecule geometry.
In cases of sp, sp2, and sp3 hybridization, different geometries arise:
In cases of sp, sp2, and sp3 hybridization, different geometries arise:
- sp hybridization results in a linear shape.
- sp2 leads to a trigonal planar structure.
- sp3 hybridization is characteristic of tetrahedral geometry, creating angles of approximately 109.5°.
Tetrahedral Structure
A tetrahedral structure is a common molecular geometry formed when a central atom is surrounded by four bonding pairs of electrons. This arrangement allows the atoms to be equidistant from each other, minimizing electron pair repulsion, and results in bond angles of approximately 109.5°.
- In methane (\(\text{CH}_4\)), for example, the hydrogen atoms are positioned at the vertices of an imaginary tetrahedron.
- This structure is prevalent in various organic compounds.
Pyramidal Structure
A pyramidal structure is typical in molecules with one lone pair and three bonding pairs. This arrangement leads to a slight distortion from the tetrahedral ideal angle due to lone pair-bond pair repulsion.
The nitrogen in ammonia (\(\text{NH}_3\)) provides a good example of a pyramidal shape.
The nitrogen in ammonia (\(\text{NH}_3\)) provides a good example of a pyramidal shape.
- The lone pair takes up more space, pushing the three hydrogen atoms closer together.
- This decreases the H-N-H bond angle to approximately 107°, slightly less than the tetrahedral 109.5°.
Bent Structure
The bent structure occurs in molecules where there are two bond pairs and one or more lone pairs on the central atom. Due to the lone pair's greater repulsion strength, the bond angles in these structures are even smaller compared to pyramidal structures.
A classic example is sulfur dichloride (\(\text{SCl}_2\)):
A classic example is sulfur dichloride (\(\text{SCl}_2\)):
- The lone pairs push the bond pairs together, forming an angle around 104.5°.
- This smaller angle compared to the tetrahedral angle arises from lone pair-lone pair and lone pair-bond pair repulsion.
Other exercises in this chapter
Problem 6
Which of the following two are isostructural? (a) \(\mathrm{XeF}_{2}, \mathrm{IF}_{-2}^{-}\) (b) \(\mathrm{NH}_{3}, \mathrm{BF}_{3}\) (c) \(\mathrm{CO}_{3}^{2},
View solution Problem 7
Main axis of a diatomic molecule is z, molecule orbitals \(\mathrm{p}_{\mathrm{x}}\) and \(\mathrm{p}_{\mathrm{y}}\) overlap to form, which of the following orb
View solution Problem 10
In \(\mathrm{NO}_{3}^{-}\)ion, number of bond pair and lone pair of electron on nitrogen atom are? (a) 2,2 (b) 3,1 (c) 1,3 (d) 4,0
View solution Problem 11
In a regular octahedral molecule, \(\mathrm{MX}_{6}\) the number of X-M-X bonds at an angle of \(180^{\circ}\) is (a) three (b) two (c) six (d) four
View solution