Problem 8
Question
In the spring of \(2003,\) SARS (Severe Acute Respiratory Syndrome) spread rapidly in several Asian countries and Canada. Table 4.9 gives the total number, \(P\), of SARS cases reported in Hong Kong \(^{17}\) by day \(t,\) where \(t=0\) is March 17,2003. (a) Find the average rate of change of \(P\) for each interval in Table 4.9 (b) In early April \(2003,\) there was fear that the disease would spread at an ever-increasing rate for a long time. What is the earliest date by which epidemiologists had evidence to indicate that the rate of new cases had begun to slow? (c) Explain why an exponential model for \(P\) is not appropriate. (d) It turns out that a logistic model fits the data well. Estimate the value of \(t\) at the inflection point. What limiting value of \(P\) does this point predict? (e) The best-fitting logistic function for this data turns out to be $$P=\frac{1760}{1+17.53 e^{-0.1408 t}}$$ What limiting value of \(P\) does this function predict? Total number of SARS cases in Hong Kong by day \(t\) (where \(t=0\) is March 17,2003) $$\begin{array}{c|c|c|c|c|c|c|c}t & P & t & P & t & P & t & P \\\\\hline 0 & 95 & 26 & 1108 & 54 & 1674 & 75 & 1739 \\\5 & 222 & 33 & 1358 & 61 & 1710 & 81 & 1750 \\\12 & 470 & 40 & 1527 & 68 & 1724 & 87 & 1755 \\\19 & 800 & 47 & 1621 & & & & \\\\\hline\end{array}$$
Step-by-Step Solution
VerifiedKey Concepts
Average Rate of Change
To calculate the average rate of change, use the formula \( R = \frac{P(t_2) - P(t_1)}{t_2 - t_1} \), where \( P(t_1) \) and \( P(t_2) \) are the values at the beginning and end of the interval, respectively. This formula essentially computes the slope of the line connecting the two points and gives us the average rate at which the number of cases changes between these two points.
- If \( R > 0 \), the quantity is increasing.
- If \( R < 0 \), the quantity is decreasing.
- If \( R = 0 \), the quantity remains constant.
Epidemiology Modeling
One popular approach in epidemiology is using the Susceptible-Infected-Recovered (SIR) model, which segments the population into three distinct groups. Modeling helps public health officials allocate resources, implement controls, and ultimately contain diseases.
By examining the average rate of change in SARS cases, we could identify critical points where the spread began to slow down. This allowed epidemiologists to assess the effectiveness of interventions and gauge the trajectory of the outbreak. Including these analyses as part of epidemiology modeling can lead to more effective responses during future outbreaks.
Logistic Growth Model
The logistic model is expressed as \( P(t) = \frac{L}{1 + ae^{-bt}} \), where \( L \) is the limiting value, \( a \) and \( b \) are constants, and \( t \) is time.
- The inflection point is significant in the logistic model, representing the moment where growth shifts from accelerating to decelerating. Mathematically, it's given by \( t = -\frac{1}{b} \log(a) \).
- The parameter \( L \) denotes carrying capacity, forecasting the maximum number of cases.
Exponential vs Logistic Models
The general form of an exponential model is \( P(t) = P_0e^{rt} \), with \( P_0 \) being the initial value and \( r \) the growth rate. This is not suitable for human scenarios like the SARS outbreak since populations face constraints.
The logistic model, \( P(t) = \frac{L}{1 + ae^{-bt}} \), contrasts by involving a carrying capacity, \( L \). This means it predicts reaching a maximum possible number, which matches real-life growth patterns where resources or conditions limit expansion.
- Exponential models are ideal for theoretical growth situations without limits.
- Logistic models are more applicable to real-world scenarios with natural saturation points.