Problem 8
Question
In Exercises 7–14, verify the identity. $$ \operatorname{coth}^{2} x-\operatorname{csch}^{2} x=1 $$
Step-by-Step Solution
Verified Answer
The identity is verified by expressing \( \operatorname{coth} x\) and \(\operatorname{csch} x\) in terms of hyperbolic sine and cosine and simplifying the equation, concluding that the identity is true.
1Step 1: Express hyperbolic cotangent in terms of hyperbolic cosine and sine
According to the formula, hyperbolic cotangent is given by \( \operatorname{coth} x = \frac {\operatorname{cosh} x} {\operatorname{sinh} x}\), we can substitute this to the equation to obtain \( \left( \frac {\operatorname{cosh} x} {\operatorname{sinh} x} \right) ^2 - \operatorname{csch}^{2} x = 1\).
2Step 2: Express hyperbolic cosecant in terms of hyperbolic sine
We know that the hyperbolic cosecant is the reciprocal of the hyperbolic sine, therefore \( \operatorname{csch} x = \frac {1} {\operatorname{sinh} x}\), replacing csch in the equation yields : \( \left( \frac {\operatorname{cosh} x} {\operatorname{sinh} x} \right) ^2 - \left( \frac {1} {\operatorname{sinh} x} \right) ^2 = 1\).
3Step 3: Simplify the Equation
The equation now becomes \( \frac {\operatorname{cosh}^{2} x - 1} {\operatorname{sinh}^{2} x} = 1\). Given that \(\operatorname{cosh}^{2} x - 1 = \operatorname{sinh}^{2} x\), this simplifies to \( \frac {\operatorname{sinh}^{2} x} {\operatorname{sinh}^{2} x} = 1 \) simplifying further gives 1 = 1
4Step 4: Conclusion
Therefore, the identity \( \operatorname{coth}^{2} x - \operatorname{csch}^{2} x = 1\) is verified.
Key Concepts
Hyperbolic CotangentHyperbolic CosecantVerifying IdentitiesSimplifying Trigonometric Expressions
Hyperbolic Cotangent
The hyperbolic cotangent is an essential function in hyperbolic trigonometry. It is defined similarly to the classical trigonometric functions but uses hyperbolic functions. The hyperbolic cotangent of an angle \( x \) is given by the ratio of the hyperbolic cosine to the hyperbolic sine. Specifically, it is expressed as:
- \( \operatorname{coth} x = \frac{\operatorname{cosh} x}{\operatorname{sinh} x} \)
Hyperbolic Cosecant
The hyperbolic cosecant function supplements the suite of hyperbolic functions much like cosecant does in regular trigonometry. It is defined as the reciprocal of the hyperbolic sine. Specifically:
- \( \operatorname{csch} x = \frac{1}{\operatorname{sinh} x} \)
Verifying Identities
Verifying mathematical identities is about proving that two expressions are equivalent for all values in their domains. In the realm of hyperbolic functions, identities can be verified by using known definitions and properties of these functions.
For example, verifying the identity \( \operatorname{coth}^2 x - \operatorname{csch}^2 x = 1 \) involves expressing each hyperbolic function in its fundamental form and simplifying the expression to the point where both sides of the equation show the same value.
For example, verifying the identity \( \operatorname{coth}^2 x - \operatorname{csch}^2 x = 1 \) involves expressing each hyperbolic function in its fundamental form and simplifying the expression to the point where both sides of the equation show the same value.
- Break down complex expressions based on known hyperbolic trigonometric identities and substitutions.
- Systematically simplify and manipulate expressions using algebraic methods.
- Conclude the verification once the identity holds true for the expressions calculated.
Simplifying Trigonometric Expressions
Simplifying trigonometric expressions, especially those involving hyperbolic functions, relies heavily on familiarity with fundamental identities and properties of hyperbolic functions. The goal is often to convert an expression into a simpler or more useful form.
Here are key approaches to simplifying expressions:
Here are key approaches to simplifying expressions:
- Use definitions: Convert complex terms into basic hyperbolic functions using their definitions or reciprocal identities.
- Apply identities: Use hyperbolic identities such as \( \operatorname{cosh}^2 x - \operatorname{sinh}^2 x = 1 \) to substitute or reduce terms.
- Solve for desired form: Simplify further until the equation or expression reaches the simplest form or the desired result.
Other exercises in this chapter
Problem 7
Finding an Indefinite Integral In Exercises \(1-26,\) find the indefinite integral.. $$ \int \frac{x}{x^{2}-3} d x $$
View solution Problem 7
Show that \(f\) and \(g\) are inverse functions (a) analytically and (b) graphically. \(f(x)=\frac{1}{x}, \quad \quad \quad g(x)=\frac{1}{x}\)
View solution Problem 8
Finding an Indefinite Integral In Exercises \(1-20\) , find the indefinite integral. $$ \int \frac{1}{x \sqrt{x^{4}-4}} d x $$
View solution Problem 8
Exponential and Logarithmic Forms of Equations In Exercises \(5-8,\) write the exponential equation as a logarithmic equation or vice versa. $$ \begin{array}{l}
View solution