Problem 8
Question
If the functions \(f, g, h\) are defined from the set of real numbers \(R\) to \(R\) such that \(f(x)=x^{2}-1, g(x)=\sqrt{x^{2}+1}, h(x)=\left\\{\begin{array}{l}0, \text { if } x \leq 0 \\ x, \text { if } x \geq 0\end{array}\right.\) then the composite function (hofog) \((x)=\) (A) \(\begin{cases}0, & x=0 \\ x^{2}, & x>0 \\ -x^{2}, & x<0\end{cases}\) (B) \(\begin{cases}0, & x=0 \\ x^{2}, & x \neq 0\end{cases}\) (C) \(\begin{cases}0, & x \leq 0 \\ x^{2}, & x>0\end{cases}\) (D) None of these
Step-by-Step Solution
Verified Answer
Option C: \(\begin{cases}0, & x \leq 0 \\ x^2, & x > 0\end{cases}\).
1Step 1: Understand Each Function
First, we examine each individual function: \(f(x) = x^2 - 1\), which is a quadratic function; \(g(x) = \sqrt{x^2 + 1}\), which outputs the non-negative square root of \(x^2 + 1\); and \(h(x)\), which is a piecewise function that equals 0 when \(x \leq 0\) and \(x\) when \(x > 0\).
2Step 2: Compute the Inner Composite Function \(g(f(x))\)
Let's find \(g(f(x))\). First, calculate \(f(x) = x^2 - 1\). Substitute in \(g\): \[g(f(x)) = g(x^2 - 1) = \sqrt{(x^2 - 1)^2 + 1}\,\] resulting in \(g(f(x)) = \sqrt{x^4 - 2x^2 + 1 + 1} = \sqrt{x^4 - 2x^2 + 2}\).
3Step 3: Compute the Composite Function \(h(g(f(x)))\)
Knowing \(h(x)\) is defined as a piecewise function, we need to determine the values to substitute: - If \(g(f(x)) \leq 0\), then \(h(g(f(x))) = 0\)- If \(g(f(x)) > 0\), then \(h(g(f(x))) = g(f(x))\).Since \(g(f(x)) = \sqrt{x^4 - 2x^2 + 2}\) is always non-negative and positive, we analyze it for different \(x\) values.
4Step 4: Analyze \(h(g(f(x)))\)
Investigate the outputs based on \(x\):- For \(x \leq 0\): Since zero leads to non-negative outputs, \(h(g(f(x))) = 0\) due to the condition \(h(\text{non-positive}) = 0\).- For \(x > 0\): \(g(f(x))\) is positive, thus \(h(g(f(x))) = g(f(x)) = \sqrt{x^4 - 2x^2 + 2}\). Consequently, \(h(g(f(x))) = x^2\) for positive \(x\) since \(x^2\) is the square of \(x\).
5Step 5: Match with Options
From Step 4, determine the outcome: \[\begin{cases}0, & x \leq 0 \ x^2, & x > 0\end{cases}\,\] which matches option C.
Key Concepts
Quadratic FunctionPiecewise FunctionSquare Root Function
Quadratic Function
Quadratic functions are a staple in mathematics. These functions are represented in the standard form: \( f(x) = ax^2 + bx + c \). The function given in this problem, \( f(x) = x^2 - 1 \), is a simple quadratic function where \( a = 1 \), \( b = 0 \), and \( c = -1 \). Quadratic functions are known for their parabolic graphs, which can open upwards or downwards depending on the sign of \( a \).
Key features of quadratic functions include:
Key features of quadratic functions include:
- The vertex: For \( f(x) = ax^2 + bx + c \), the vertex can be found using the formula \( x = -\frac{b}{2a} \).
- The axis of symmetry: This is a vertical line through the vertex, also represented by \( x = -\frac{b}{2a} \).
- The intercepts: The y-intercept is found by evaluating \( f(0) \), and x-intercepts can be found by solving \( f(x) = 0 \).
Piecewise Function
Piecewise functions are interesting because they are defined by different expressions based on different intervals of the input variable. In this problem, the function \( h(x) \) is such a function, defined piecewise as:
\[h(x) = \begin{cases}0, & \text{if } x \leq 0 \x, & \text{if } x > 0\end{cases}\]
Piecewise functions can represent real-world situations where different rules apply in different scenarios. For example, h(x) could represent a physical process that behaves differently depending on conditions, such as temperature thresholds or time intervals.
When analyzing piecewise functions:
\[h(x) = \begin{cases}0, & \text{if } x \leq 0 \x, & \text{if } x > 0\end{cases}\]
Piecewise functions can represent real-world situations where different rules apply in different scenarios. For example, h(x) could represent a physical process that behaves differently depending on conditions, such as temperature thresholds or time intervals.
When analyzing piecewise functions:
- Determine the range of each piece by solving inequalities for transition points.
- Evaluate limits at points where the definition changes to comprehend continuity or discontinuity.
- Apply each piece formula appropriately depending on the input value.
Square Root Function
Square root functions involve the expression \( g(x) = \sqrt{x} \), or in the problem's case, \( g(x) = \sqrt{x^2 + 1} \). The square root function is always defined for non-negative inputs, producing non-negative outputs, and it is essential for determining particular solutions when evaluating composite functions.
Key properties of square root functions include:
Key properties of square root functions include:
- Domain: Generally \( x \geq 0 \) for \( \sqrt{x} \), but more can be if under a square like in \( \sqrt{x^2 + 1} \).
- Shape: A smooth curve starting at the origin when \( x = 0 \), gradually increasing.
- Asymptotic behavior: Approaches horizontal as \( x \to \infty \).
Other exercises in this chapter
Problem 6
Let \(f: R \rightarrow R\) be a function defined by, \(f(x)=\frac{x^{2}-8}{x^{2}+2}\), then \(f\) is (A) one-one but not onto (B) one-one and onto (C) onto but
View solution Problem 7
If \(f(x)=64 x^{3}+\frac{1}{x^{3}}\) and \(a, b\) are the roots of \(4 x+\frac{1}{x}=3\), (A) \(f(a)=12\) (B) \(f(b)=11\) (C) \(f(a)=f(b)\) (D) None of these
View solution Problem 9
If \(S\) is the set of all real \(x\) and such that \(\frac{2 x-1}{2 x^{3}+3 x^{2}+x}\) is positive, then \(S\) contains (A) \(\left(-\infty,-\frac{3}{2}\right)
View solution Problem 10
The number of values of \(x\), where the function \(f(x)=\) \(\cos x+\cos (\sqrt{2} x)\) attains its maximum, is (A) 0 (B) 1 (C) 2 (D) infinite
View solution