Problem 8
Question
For the following exercises, use the Remainder Theorem to find the remainder. $$ \left(x^{4}+5 x^{3}-4 x-17\right) \div(x+1) $$
Step-by-Step Solution
Verified Answer
The remainder is -17.
1Step 1: Understand the Remainder Theorem
The Remainder Theorem states that the remainder of the division of a polynomial \( f(x) \) by a linear divisor \( x-a \) is the same as the value of the polynomial evaluated at \( a \). In this exercise, \( f(x) = x^4 + 5x^3 - 4x - 17 \) and we want to find the remainder when it is divided by \( x+1 \).
2Step 2: Identify \( a \) from \( x+1 \)
From the divisor \( x+1 \), set \( x+1 = 0 \) to find \( a \). Solving for \( x \), we get \( x = -1 \). This means \( a = -1 \).
3Step 3: Evaluate \( f(a) \)
Substitute \( a = -1 \) into the polynomial \( f(x) = x^4 + 5x^3 - 4x - 17 \) to find the value of the polynomial at \( a = -1 \). Calculate \( f(-1) \):\[-1^4 + 5(-1)^3 - 4(-1) - 17 = 1 - 5 + 4 - 17 = -17 \].
4Step 4: Conclude with the Remainder
Since the remainder of the division \( x^4 + 5x^3 - 4x - 17 \) by \( x+1 \) is the value of \( f(-1) \), the remainder is \(-17\).
Key Concepts
Polynomial DivisionLinear DivisorEvaluate PolynomialFinding Remainder
Polynomial Division
Polynomial division is a mathematical method used to divide a polynomial by another polynomial, usually of lower degree. This process is similar to long division with numbers. When dividing polynomials, the main aim is to simplify the expression and possibly find the quotient and remainder.
- Think of polynomial division as a method to break down complex expressions into simpler parts.
- The division process continues until the degree of the remaining polynomial is less than the divisor.
Linear Divisor
A linear divisor is a polynomial of first degree in the divisor, often written in the form of \(x-a\).
A linear divisor simplifies the division process because its structure allows for straightforward identification of the value needed in the Remainder Theorem.
A linear divisor simplifies the division process because its structure allows for straightforward identification of the value needed in the Remainder Theorem.
- Example of a linear divisor: \(x+1\).
- By rearranging \(x+1 = 0\), solve to find \(x = -1\), identifying the root for evaluation.
Evaluate Polynomial
Evaluating a polynomial involves substituting a specific value for the variable and performing the arithmetic operations to solve.
It's equivalent to replacing every \(x\) variable in the polynomial with the given value and simplifying.
It's equivalent to replacing every \(x\) variable in the polynomial with the given value and simplifying.
- For example, if \(f(x) = x^4 + 5x^3 - 4x - 17\) and \(a = -1\), replace all \(x\)s with \(-1\) to calculate \(f(-1)\).
- Arithmetic operations will reveal the polynomial's value at point \(x = -1\).
Finding Remainder
In polynomial division, particularly when working with linear divisors, the Remainder Theorem provides a quick method for finding the remainder without performing the entire division. Instead, evaluate the polynomial at the divisor's root.
The Remainder Theorem states that the remainder of dividing a polynomial \(f(x)\) by \(x-a\) is \(f(a)\).
The Remainder Theorem states that the remainder of dividing a polynomial \(f(x)\) by \(x-a\) is \(f(a)\).
- For the given problem, the polynomial is \(f(x) = x^4 + 5x^3 - 4x - 17\) and the divisor is \(x+1\), leading to \(a = -1\).
- By evaluating \(f(-1)\), we found that the remainder is -17.
Other exercises in this chapter
Problem 8
For the following exercises, write an equation describing the relationship of the given variables. \(y\) varies directly as the cube root of \(x\) and when \(x=
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For the following exercises, find the \(x\) - or t-intercepts of the polynomial functions. $$ C(t)=4 t(t-2)^{2}(t+1) $$
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