Problem 8
Question
Find the value of each permutation. $$ P(7,2) $$
Step-by-Step Solution
Verified Answer
The value of P(7, 2) is 42.
1Step 1: Define the Permutation Formula
Permutations of n objects taken r at a time, denoted as \(P(n, r)\), can be calculated using the formula: \[ P(n, r) = \frac{n!}{(n - r)!} \]
2Step 2: Substitute Values
In the given problem, we have \(n = 7\) and \(r = 2\). Substitute these values into the formula: \[ P(7, 2) = \frac{7!}{(7 - 2)!} \]
3Step 3: Simplify the Expression
First, calculate \(7 - 2\): \[ 7 - 2 = 5 \] Now our formula becomes: \[ P(7, 2) = \frac{7!}{5!} \]
4Step 4: Calculate Factorials
Compute \(7!\) and \(5!\): \[ 7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \]
5Step 5: Divide the Factorials
Now, divide \(7!\) by \(5!\): \[ P(7, 2) = \frac{5040}{120} = 42 \]
Key Concepts
Permutation FormulaFactorialsCombinatorics
Permutation Formula
In combinatorics, permutations play a crucial role. A permutation of a set involves arranging all or part of the elements into a sequence or order. The permutation formula is very useful when you need to determine the number of ways to order a subset of items. The formula for permutations of n objects taken r at a time, denoted as \(P(n, r)\), is defined as:
\[ P(n, r) = \frac{n!}{(n - r)!} \]
Here, \(n!\) (n factorial) represents the product of all positive integers up to n, and \((n - r)!\) is the factorial of the difference between n and r. This formula accounts for all possible orderings of r objects selected from a total of n. Understanding this formula aids in solving various problems in probability and statistics, making it a fundamental concept in mathematics.
\[ P(n, r) = \frac{n!}{(n - r)!} \]
Here, \(n!\) (n factorial) represents the product of all positive integers up to n, and \((n - r)!\) is the factorial of the difference between n and r. This formula accounts for all possible orderings of r objects selected from a total of n. Understanding this formula aids in solving various problems in probability and statistics, making it a fundamental concept in mathematics.
Factorials
Factorials are a cornerstone concept in combinatorics and permutations. The factorial of a non-negative integer n, denoted \(n!\), is the product of all positive integers less than or equal to n. For example,
\(7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040\).
Factorials grow very quickly with increasing values of n. This rapid growth is why the permutation formula uses the ratio of two factorials to compute the number of arrangements efficiently. Factorials simplify complex combinatorial expressions, enabling us to solve exercises like \(P(7, 2)\) straightforwardly. In our example:
\( P(7, 2) = \frac{7!}{5!} \), where 5 is derived from \(7 - 2\). The calculation proceeds by finding the values of \(7!\) and \(5!\), making it easy to divide and simplify. Remember, factorials help handle larger calculations by breaking them down into manageable parts.
\(7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040\).
Factorials grow very quickly with increasing values of n. This rapid growth is why the permutation formula uses the ratio of two factorials to compute the number of arrangements efficiently. Factorials simplify complex combinatorial expressions, enabling us to solve exercises like \(P(7, 2)\) straightforwardly. In our example:
\( P(7, 2) = \frac{7!}{5!} \), where 5 is derived from \(7 - 2\). The calculation proceeds by finding the values of \(7!\) and \(5!\), making it easy to divide and simplify. Remember, factorials help handle larger calculations by breaking them down into manageable parts.
Combinatorics
Combinatorics is the field of mathematics concerning the study of finite or countable discrete structures. It encompasses a wide range of topics, including permutations, combinations, and the principals of counting. In the context of our exercise:
- **Permutations** involve arranging elements in a specific order.
- **Combinations** involve selecting elements without considering the order.
In combinatorics, understanding how to efficiently count these arrangements is key. The permutation formula lets us determine the number of ways to pick and arrange r objects from a set of n, as we did with \(P(7, 2)\). This method is not only handy for mathematics problems but also has practical applications in fields like computer science, statistics, and various engineering disciplines. By grasping the permutation formula and the concept of factorials, students can better tackle a broad array of combinatorial problems.
- **Permutations** involve arranging elements in a specific order.
- **Combinations** involve selecting elements without considering the order.
In combinatorics, understanding how to efficiently count these arrangements is key. The permutation formula lets us determine the number of ways to pick and arrange r objects from a set of n, as we did with \(P(7, 2)\). This method is not only handy for mathematics problems but also has practical applications in fields like computer science, statistics, and various engineering disciplines. By grasping the permutation formula and the concept of factorials, students can better tackle a broad array of combinatorial problems.
Other exercises in this chapter
Problem 7
Determine whether the following is a probability model. $$\begin{array}{cc}\text { Outcome } & \text { Probability } \\\\\hline 1 & 0.2 \\\2 & 0.3 \\\3 & 0.1 \\
View solution Problem 7
True or False If a task consists of a sequence of three choices in which there are \(p\) selections for the first choice, \(q\) selections for the second choice
View solution Problem 8
Determine whether the following is a probability model. $$\begin{array}{lc}\text { Outcome } & \text { Probability } \\\\\hline \text { Steve } & 0.4 \\\\\text
View solution Problem 8
Multiple Choice The Counting Formula states that if \(A\) and \(B\) are finite sets, then \(n(A \cup B)=\) __________. (a) \(n(A)+n(B)\) (b) \(n(A)+n(B)-n(A \ca
View solution