Problem 8
Question
Find the focus, directrix, and focal diameter of the parabola, and sketch its graph. $$x^{2}=y$$
Step-by-Step Solution
Verified Answer
Focus: (0, 1/4); Directrix: y = -1/4; Focal Diameter: 1.
1Step 1: Identify the Structure of the Parabola
The equation given is \(x^2 = y\), which can be rewritten as \(y = x^2\). This represents a parabola that opens upwards, where the equation is centered at the origin \((0,0)\).
2Step 2: Determine the Parameters
In the equation of a parabola \(x^2 = 4py\), \(4p\) should equal 1 (matching \(x^2 = y\)). Therefore, \(p = \frac{1}{4}\). This parameter \(p\) provides details about the parabola's orientation and specific properties.
3Step 3: Find the Focus
The focus of a parabola \(x^2 = 4py\) that opens upwards is located at \((0,p)\). Since \(p = \frac{1}{4}\), the focus is at \((0, \frac{1}{4})\).
4Step 4: Locate the Directrix
The directrix of the parabola opening upwards is a horizontal line \(y = -p\). Therefore, the directrix is \(y = -\frac{1}{4}\).
5Step 5: Calculate the Focal Diameter
The focal diameter is the length of the line segment perpendicular to the axis of symmetry that passes through the focus and whose endpoints lie on the parabola. It equals \(4p\), so in this case it is 1.
6Step 6: Sketch the Graph
To sketch the graph of \(x^2 = y\), plot the focus at \((0, \frac{1}{4})\), draw the directrix as the line \(y = -\frac{1}{4}\), and sketch the parabola opening upwards passing through the origin.
Key Concepts
Focus and Directrix of a ParabolaEquation of a ParabolaFocal Diameter
Focus and Directrix of a Parabola
A parabola is a U-shaped curve that has unique properties, including its focus and directrix.
The focus of a parabola is a point from which distances to any point on the parabola are measured equally with a corresponding line called the directrix. Together, they define the parabola.
For our specific case, the parabola given by the equation \(x^2 = y\) has:
The focus of a parabola is a point from which distances to any point on the parabola are measured equally with a corresponding line called the directrix. Together, they define the parabola.
- The focus acts like a magnet for the parabola's points, located at a specific distance within the curve.
- The directrix is a straight line that lies outside the parabola and is equidistant from all points on it to the focus.
For our specific case, the parabola given by the equation \(x^2 = y\) has:
- Focus at point \((0, \frac{1}{4})\).
- Directrix as the line \(y = -\frac{1}{4}\).
Equation of a Parabola
The equation of a parabola is a mathematical expression that describes its position and curvature.
For vertical parabolas, the equation generally follows the form \(x^2 = 4py\).
Here, the parabola equation \(x^2 = y\) matches this format.
The value of \(p\) directly influences the parabola's orientation and how far it opens. A larger \(p\) means a wider opening.
This specific equation represents a parabola:
For vertical parabolas, the equation generally follows the form \(x^2 = 4py\).
Here, the parabola equation \(x^2 = y\) matches this format.
- The value \(4p\) in this equation usually expresses the distance to the focus and the length of the directrix line.
The value of \(p\) directly influences the parabola's orientation and how far it opens. A larger \(p\) means a wider opening.
This specific equation represents a parabola:
- Opening upwards from its vertex at the origin \((0,0)\).
- With the knowledge of \(p\), we can deduce that focus is found at \((0, \frac{1}{4})\).
- The directrix is confirmed at \(y = -\frac{1}{4}\).
Focal Diameter
The focal diameter, also known as the latus rectum, is an important measure in a parabola.
It represents the width of the parabola at its focus and is directly linked to its parameter \(p\).
For any parabola with an equation \(x^2 = 4py\), the focal diameter equals \(4p\). Consider this as the breadth of the parabola through the focus intersecting the curve on both sides.
This understanding of the focal diameter helps when sketching or analyzing the nature of the parabola.
It represents the width of the parabola at its focus and is directly linked to its parameter \(p\).
For any parabola with an equation \(x^2 = 4py\), the focal diameter equals \(4p\). Consider this as the breadth of the parabola through the focus intersecting the curve on both sides.
- This length provides insight into how "wide" the parabola is at the focus.
- The focal diameter computes as \(4 \times \frac{1}{4} = 1\).
This understanding of the focal diameter helps when sketching or analyzing the nature of the parabola.
Other exercises in this chapter
Problem 8
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\begin{array}{l}{1-22 \text { a pair of parametric equations is given. }} \\\ {\text { (a) Sketch the curve represented by the parametric equations. }} \\\ {\te
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