Problem 8
Question
Find the distance from \((2,3,-1)\) to (a) the \(x y\)-plane, (b) the \(y\)-axis, and (c) the origin.
Step-by-Step Solution
Verified Answer
(a) 1, (b) √5, (c) √14
1Step 1: Understanding the Point and the Coordinate Planes
We need to find distances related to the point \((2,3,-1)\). The coordinates are labeled as \(x = 2, y = 3, z = -1\). The \(xy\) plane is defined where \(z = 0\). Thus, the distance to the plane depends only on the \(z\)-coordinate.
2Step 2: Calculating Distance to the xy-plane
The distance from a point to the \(xy\)-plane is the absolute value of the \(z\)-coordinate, since the \(xy\)-plane is \(z = 0\). For the point \((2,3,-1)\), the distance is \(|-1| = 1\).
3Step 3: Understanding the y-axis
The \(y\)-axis is defined where both \(x = 0\) and \(z = 0\). To find the distance from a point to the \(y\)-axis, compute the length of the vector formed by the \(x\) and \(z\) coordinates.
4Step 4: Calculating Distance to the y-axis
The formula for the distance to the \(y\)-axis is \( ext{Distance} = \sqrt{x^2 + z^2}\). For \((2, 3, -1)\), the distance is \(\sqrt{2^2 + (-1)^2} = \sqrt{4 + 1} = \sqrt{5}\).
5Step 5: Understanding the origin and Calculating Distance
To find the distance from a point to the origin \( (0,0,0) \), use the distance formula: \( \sqrt{x^2 + y^2 + z^2} \). For the point \((2,3,-1)\), the distance is \(\sqrt{2^2 + 3^2 + (-1)^2} = \sqrt{4 + 9 + 1} = \sqrt{14}\).
Key Concepts
Coordinate GeometryDistance FormulaVectors3D Coordinates
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that allows us to represent geometric figures using coordinates. This field combines geometry and algebra to study the position of points and lines in space.
In 3D coordinate geometry, each point is represented by three numbers:
In 3D coordinate geometry, each point is represented by three numbers:
- the x-coordinate, which shows how far the point is along the x-axis,
- the y-coordinate, which represents the point's position along the y-axis,
- the z-coordinate, indicating the point's position along the z-axis.
Distance Formula
The distance formula is a mathematical equation used to determine the distance between two points in space. This formula originates from the Pythagorean theorem, which can be applied to the 3D coordinate system.
To find the distance between two points \(x_1, y_1, z_1\) and \(x_2, y_2, z_2\), we use the formula: \[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \]
This equation helps us calculate various distances, such as the distance to the \(xy\) plane or to an axis, by setting the corresponding coordinates to zero where necessary.
For example, to find the distance from a point to the origin \( (0,0,0) \), you use: \[ \sqrt{x^2 + y^2 + z^2} \]
This method ensures accurate measurements in a three-dimensional space.
To find the distance between two points \(x_1, y_1, z_1\) and \(x_2, y_2, z_2\), we use the formula: \[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \]
This equation helps us calculate various distances, such as the distance to the \(xy\) plane or to an axis, by setting the corresponding coordinates to zero where necessary.
For example, to find the distance from a point to the origin \( (0,0,0) \), you use: \[ \sqrt{x^2 + y^2 + z^2} \]
This method ensures accurate measurements in a three-dimensional space.
Vectors
Vectors are mathematical objects that have both a magnitude and a direction. In 3D space, vectors are used to represent points or displacements from one point to another.
A vector is often depicted as \( \mathbf{v} = \langle x, y, z \rangle \), which describes movement from the origin to the point \( (x, y, z) \).
A vector is often depicted as \( \mathbf{v} = \langle x, y, z \rangle \), which describes movement from the origin to the point \( (x, y, z) \).
- Magnitude refers to the length of the vector, calculated using the distance formula.
- Direction is the way in which the vector points in space.
3D Coordinates
3D coordinates extend the concept of coordinates to include a third dimension, providing depth to our understanding of space. This enhances our ability to describe points in a more comprehensive manner.
Unlike 2D coordinates, which only deal with an x and y-axis, 3D coordinates introduce a z-axis. Adding this third dimension allows us to model and visualize spaces and shapes that are not confined to flat surfaces.
The point \( (2, 3, -1) \) serves as an example, where each number corresponds to its position relative to the x, y, and z axes.
Unlike 2D coordinates, which only deal with an x and y-axis, 3D coordinates introduce a z-axis. Adding this third dimension allows us to model and visualize spaces and shapes that are not confined to flat surfaces.
The point \( (2, 3, -1) \) serves as an example, where each number corresponds to its position relative to the x, y, and z axes.
- The x-coordinate is 2 units along the x-axis,
- the y-coordinate is 3 units along the y-axis,
- and the z-coordinate is -1 unit along the z-axis.
Other exercises in this chapter
Problem 8
Let \(\mathbf{a}=\langle\sqrt{3} / 3, \sqrt{3} / 3, \sqrt{3} / 3\rangle, \mathbf{b}=\langle 1,-1,0\rangle\), and \(\mathbf{c}=\langle-2,-2,1\rangle\). Find the
View solution Problem 8
Name and sketch the graph of each of the following equations in three-space. $$ 9 x^{2}-y^{2}+9 z^{2}-9=0 $$
View solution Problem 8
Write both the parametric equations and the symmetric equations for the line through the given point parallel to the given vector. $$(-2,2,-2),(7,-6,3)$$
View solution Problem 9
Find the area of the triangle with \((3,2,1),(2,4,6)\), and \((-1,2,5)\) as vertices.
View solution