Problem 8
Question
Find an equation for the line that passes through the given points. $$ (4,5) \text { and }(2,-1) $$
Step-by-Step Solution
Verified Answer
The equation is \(y = 3x - 7\).
1Step 1: Identify Points
Our points are \((x_1, y_1) = (4, 5)\) and \((x_2, y_2) = (2, -1)\).
2Step 2: Calculate Slope
Use the slope formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Substituting the given points, we have \(m = \frac{-1 - 5}{2 - 4} = \frac{-6}{-2} = 3\).
3Step 3: Use Point-Slope Form
The point-slope form of a line's equation is \(y - y_1 = m(x - x_1)\). Using point \((4,5)\) and slope \(m = 3\), the equation becomes \(y - 5 = 3(x - 4)\).
4Step 4: Simplify to Slope-Intercept Form
Simplify the equation \(y - 5 = 3(x - 4)\) to get \(y = 3x - 12 + 5\), which simplifies to \(y = 3x - 7\).
Key Concepts
Point-Slope FormSlope-Intercept FormCalculating Slope
Point-Slope Form
The point-slope form is a way to express the equation of a straight line. This form is particularly helpful when we know a point on the line and the slope. The format of the equation is given by:
To use this form, you just need to substitute in values for \((x_1, y_1)\) and \(m\). For example, if the point is \((4, 5)\) and the slope \(m\) is discovered to be 3, the equation becomes \(y - 5 = 3(x - 4)\). Using this form helps to directly insert the slope and point into the equation, efficiently sliding into the slope-intercept form in later steps.
- \( y - y_1 = m(x - x_1) \)
- \((x_1, y_1)\) represents a specific point on the line.
- \(m\) is the slope of the line.
To use this form, you just need to substitute in values for \((x_1, y_1)\) and \(m\). For example, if the point is \((4, 5)\) and the slope \(m\) is discovered to be 3, the equation becomes \(y - 5 = 3(x - 4)\). Using this form helps to directly insert the slope and point into the equation, efficiently sliding into the slope-intercept form in later steps.
Slope-Intercept Form
The slope-intercept form of the equation of a line is one of the most common ways to write the equation, due to its simplicity and ease of use with graphs. This form provides a quick view of the line's slope and where it crosses the y-axis.
It is written as:
From a point-slope form like \(y - 5 = 3(x - 4)\), you can easily alter it into the slope-intercept form by expanding and simplifying. Distribute the 3 into the terms \((x - 4)\) to get \(y - 5 = 3x - 12\). Then, add 5 to both sides to obtain \(y = 3x - 7\). This is now in slope-intercept form and clearly shows the slope, 3, and the y-intercept, -7.
It is written as:
- \( y = mx + b \)
- \(m\) is the slope of the line.
- \(b\) is the y-intercept, which is the point where the line crosses the y-axis.
From a point-slope form like \(y - 5 = 3(x - 4)\), you can easily alter it into the slope-intercept form by expanding and simplifying. Distribute the 3 into the terms \((x - 4)\) to get \(y - 5 = 3x - 12\). Then, add 5 to both sides to obtain \(y = 3x - 7\). This is now in slope-intercept form and clearly shows the slope, 3, and the y-intercept, -7.
Calculating Slope
Calculating the slope of a line is a fundamental step when working with linear equations. The slope, often represented as \(m\), tells you how steep the line is and the direction it's going.
The formula for calculating slope using two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
For example, using points \( (4, 5) \) and \( (2, -1) \), substitute into the formula: \( m = \frac{-1 - 5}{2 - 4} = \frac{-6}{-2} = 3 \). So, the line has a slope of 3, indicating it rises by 3 units for every 1 unit it runs to the right.
The formula for calculating slope using two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
For example, using points \( (4, 5) \) and \( (2, -1) \), substitute into the formula: \( m = \frac{-1 - 5}{2 - 4} = \frac{-6}{-2} = 3 \). So, the line has a slope of 3, indicating it rises by 3 units for every 1 unit it runs to the right.
Other exercises in this chapter
Problem 8
Find the relative, or percent, change. \(W\) changes from \(0.3\) to \(0.05\)
View solution Problem 8
For the functions, find \(f(5)\). $$ f(x)=10 x-x^{2} $$
View solution Problem 9
Sketch graphs of the functions. What are their amplitudes and periods? $$y=5-\sin 2 t$$
View solution Problem 9
Determine whether or not the function is a power function. If it is a power function, write it in the form \(y=k x^{p}\) and give the values of \(k\) and \(p\).
View solution