Problem 8
Question
Fill in the blank to complete the trigonometric identity. \( \sec\left(\dfrac{\pi}{2} - u \right) \)= ________
Step-by-Step Solution
Verified Answer
The equivalent trigonometric expression for \( \sec\left(\dfrac{\pi}{2} - u \right) \) is \( \dfrac{1}{\sin(u)} \)
1Step 1: Recognize the trigonometric identity
Here, the function secant \( \sec \) is seen, which is the reciprocal of the cosine function. It's represented by \( \sec(u) = \dfrac{1}{\cos(u)} \)
2Step 2: Apply the co-function identity
According to the co-function identity, \( \cos(\dfrac{\pi}{2} - u) = \sin(u) \). This is due to the complementary nature of sine and cosine functions.
3Step 3: Substitute in the identity
Finally, substitute the co-function identity in the original identity. Since secant is the reciprocal of cosine, and cosine of \( \dfrac{\pi}{2} - u \) is equal to sine of u, the secant of \( \dfrac{\pi}{2} - u \) becomes the reciprocal of sine of u. Thus, \( \sec\left(\dfrac{\pi}{2} - u \right) = \dfrac{1}{\sin(u)} \)
Key Concepts
Co-function IdentityReciprocal Trigonometric FunctionsComplementary Angles in Trigonometry
Co-function Identity
In trigonometry, the co-function identities are a set of useful relationships between trigonometric functions evaluated at complementary angles. Complementary angles are two angles that sum up to 90 degrees or \frac{\text{\text{\pi}}}{2} radians.
For instance, sine and cosine are co-functions. This can be observed in the identity \text{\( \cos(\frac{\pi}{2} - u) = \sin(u) \)}, where the angle \text{\( u \)} and its complement \text{\( \frac{\pi}{2} - u \)} create this important relationship. Similarly, other trigonometric functions have their co-function pairs: tangent and cotangent, secant and cosecant. Knowing these pairs helps us to simplify problems and evaluate trigonometric expressions more easily.
To apply a co-function identity effectively, remember that switching between sine and cosine, or between their reciprocals, involves using complementary angles. As we saw in the exercise, converting \text{\( \sec\left(\frac{\pi}{2} - u \right) \)} involved recognizing that secant is related to cosine and using the co-function relationship.
For instance, sine and cosine are co-functions. This can be observed in the identity \text{\( \cos(\frac{\pi}{2} - u) = \sin(u) \)}, where the angle \text{\( u \)} and its complement \text{\( \frac{\pi}{2} - u \)} create this important relationship. Similarly, other trigonometric functions have their co-function pairs: tangent and cotangent, secant and cosecant. Knowing these pairs helps us to simplify problems and evaluate trigonometric expressions more easily.
To apply a co-function identity effectively, remember that switching between sine and cosine, or between their reciprocals, involves using complementary angles. As we saw in the exercise, converting \text{\( \sec\left(\frac{\pi}{2} - u \right) \)} involved recognizing that secant is related to cosine and using the co-function relationship.
Reciprocal Trigonometric Functions
In trigonometry, each primary function has a reciprocal counterpart. These reciprocal relationships are foundational and are used frequently in solving trigonometric problems. For example, the secant function is the reciprocal of the cosine function, defined as \text{\( \sec(u) = \frac{1}{\cos(u)} \)}.
The three primary trigonometric functions—sine, cosine, and tangent—have reciprocals: cosecant, secant, and cotangent, respectively. Here’s the list of these correspondences:
The three primary trigonometric functions—sine, cosine, and tangent—have reciprocals: cosecant, secant, and cotangent, respectively. Here’s the list of these correspondences:
- Sine (\text{\( \sin \)}) and Cosecant (\text{\( \csc \)})
- Cosine (\text{\( \cos \)}) and Secant (\text{\( \sec \)})
- Tangent (\text{\( \tan \)}) and Cotangent (\text{\( \cot \)})
Complementary Angles in Trigonometry
Complementary angles play a significant role in trigonometry, helping establish the fundamental co-function identities. These are pairs of angles that add up to 90 degrees or \text{\( \frac{\pi}{2} \)} radians. When dealing with trigonometric functions of complementary angles, we can use the concept that \text{\( \cos(\alpha) = \sin(\frac{\pi}{2}-\alpha) \)} and vice versa, where \(\alpha\) represents an angle.
This complementary relationship implies that the sine of one angle in a right triangle is equal to the cosine of the other non-right angle, and this property extends to all co-function pairs. Understanding complementary angles is crucial for solving right-angle problems and proves invaluable when working on more complex trigonometric equations or identities, as it allows us to transform functions into their co-function equivalents.
This complementary relationship implies that the sine of one angle in a right triangle is equal to the cosine of the other non-right angle, and this property extends to all co-function pairs. Understanding complementary angles is crucial for solving right-angle problems and proves invaluable when working on more complex trigonometric equations or identities, as it allows us to transform functions into their co-function equivalents.
Other exercises in this chapter
Problem 8
In Exercises 5-10, verify that the \( x \)-values are solutions of the equation. \( 2 \cos^2 4x - 1 = 0 \) (a) \( x = \dfrac{\pi}{16} \) (b) \( x = \dfrac{3\pi}
View solution Problem 8
In Exercises 3-8, fill in the blank to complete the trigonometric identity. \( \sec (-u) \)= ________
View solution Problem 9
In Exercises 7 - 12, find the exact value of each expression. (a) \( \sin\left(\dfrac{7\pi}{6} + \dfrac{\pi}{3}\right) \) (b) \( \sin\dfrac{7\pi}{6} - \cos \dfr
View solution Problem 9
In Exercises 5-10, verify that the \( x \)-values are solutions of the equation. \( 2 \sin^2 x - \sin x - 1 = 0 \) (a) \( x = \dfrac{\pi}{2} \) (b) \( x = \dfra
View solution