Problem 8
Question
Exer. 3-8: Change the polar coordinates to rectangular coordinates. $$ \left(10, \arccos \left(-\frac{1}{3}\right)\right) $$
Step-by-Step Solution
Verified Answer
The rectangular coordinates are \( \left(-\frac{10}{3}, \frac{20\sqrt{2}}{3}\right) \).
1Step 1: Identify the Components of Polar Coordinates
The polar coordinates are given as \( (r, \theta) \). For the problem \( (r, \theta) = \left(10, \arccos \left(-\frac{1}{3}\right)\right) \). This tells us that the radius \( r = 10 \) and the angle \( \theta = \arccos \left(-\frac{1}{3}\right) \).
2Step 2: Use Conversion Formulas
To convert polar coordinates to rectangular coordinates, use the formulas: \( x = r \cdot \cos(\theta) \) and \( y = r \cdot \sin(\theta) \).
3Step 3: Calculate the Rectangular Coordinate x
Substitute the values into the formula for \( x\):\[ x = 10 \cdot \cos\left(\arccos\left(-\frac{1}{3}\right)\right) \] \( \cos(\arccos(x)) = x \), so \( \cos\left(\arccos\left(-\frac{1}{3}\right)\right) = -\frac{1}{3} \). Therefore, \[ x = 10 \cdot \left(-\frac{1}{3}\right) = -\frac{10}{3} \].
4Step 4: Calculate the Rectangular Coordinate y
Since \( \sin^2(\theta) + \cos^2(\theta) = 1 \), we have:\[ \sin(\theta) = \sqrt{1 - (\cos(\theta))^2} = \sqrt{1 - \left(-\frac{1}{3}\right)^2} = \sqrt{1 - \frac{1}{9}} = \sqrt{\frac{8}{9}} = \frac{2\sqrt{2}}{3} \].\Then, calculate \( y \) using the formula: \[ y = 10 \cdot \frac{2\sqrt{2}}{3} = \frac{20\sqrt{2}}{3} \].
5Step 5: Write the Rectangular Coordinates
With the calculations completed, the rectangular coordinates are \( \left(-\frac{10}{3}, \frac{20\sqrt{2}}{3}\right) \).
Key Concepts
Polar CoordinatesRectangular CoordinatesTrigonometric FunctionsCoordinate Conversion Formulas
Polar Coordinates
Polar coordinates are a way of representing locations in a plane using a distance and an angle. They're particularly useful in situations where phenomena have circular or rotational symmetry, such as wave patterns or the paths of celestial bodies. In polar coordinates, each point on a plane is defined by two values:
- the radial distance, often denoted as \( r \), representing how far the point is from the origin
- the angular coordinate, \( \theta \), which is the angle measured from a reference direction (typically the positive x-axis)
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, describe a point in a plane using two perpendicular number lines intersecting at an origin. It forms the basis for most parts of traditional geometry. The coordinates are expressed with two values:
- \( x \) - the horizontal distance from the y-axis
- \( y \) - the vertical distance from the x-axis
Trigonometric Functions
Trigonometric functions are essential tools in the conversion between polar and rectangular coordinates. These functions describe relationships between angles and sides of triangles, particularly right triangles. The primary trigonometric functions that come into play are:
- \( \cos(\theta) \) - the cosine function, which represents the ratio of the adjacent side to the hypotenuse in a right triangle
- \( \sin(\theta) \) - the sine function, which represents the ratio of the opposite side to the hypotenuse
Coordinate Conversion Formulas
Converting between polar and rectangular coordinates involves specific mathematical formulas derived from trigonometry. The common formulas used in this transformation are:
- \( x = r \cdot \cos(\theta) \) - This formula helps calculate the rectangular x-coordinate by using the cosine of the angle.
- \( y = r \cdot \sin(\theta) \) - This one assists in finding the y-coordinate through the sine of the angle.
- The x-coordinate is found by calculating: \( x = 10 \cdot \cos\left(\arccos\left(-\frac{1}{3}\right)\right) = -\frac{10}{3} \).
- The y-coordinate requires finding the sine: \( y = 10 \cdot \frac{2\sqrt{2}}{3} = \frac{20\sqrt{2}}{3} \).
Other exercises in this chapter
Problem 7
Exer. 1-14: Find the vertices and foci of the ellipse. Sketch its graph, showing the foci. $$ 4 x^{2}+25 y^{2}=1 $$
View solution Problem 8
Exer. 1-12: Find the eccentricity, and classify the conic. Sketch the graph, and label the vertices. $$ r=\frac{4 \sec \theta}{2 \sec \theta-1} $$
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Find the vertices, the foci, and the equations of the asymptotes of the hyperbola. Sketch its graph, showing the asymptotes and the foci. $$x^{2}-2 y^{2}=8$$
View solution Problem 8
Exer. 1-12: Find the vertex, focus, and directrix of the parabola. Sketch its graph, showing the focus and the directrix. $$ (y+1)^{2}=-12(x+2) $$
View solution