Problem 8
Question
Exer. 1-34: Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. $$ (8+2 i)(7-3 i) $$
Step-by-Step Solution
Verified Answer
The expression is \(62 - 10i\).
1Step 1: Apply the distributive property
To multiply two complex numbers, apply the distributive property (also known as the FOIL method for binomials). So, calculate: \((8+2i)(7-3i)=(8)(7)+(8)(-3i)+(2i)(7)+(2i)(-3i)\). This breaks down into four separate multiplications.
2Step 2: Compute each part of the expansion
- Calculate \(8 \times 7 = 56\).- Calculate \(8 \times -3i = -24i\).- Calculate \(2i \times 7 = 14i\).- Calculate \(2i \times -3i = -6i^2\). Remember that \(i^2 = -1\), so \(-6i^2 = 6\).
3Step 3: Combine real parts and imaginary parts separately
Combine the real parts: \(56 + 6 = 62\). Combine the imaginary parts: \(-24i + 14i = -10i\).
4Step 4: Write in the form \(a + bi\)
The expression \((8+2i)(7-3i)\) simplifies to \(62 - 10i\). This matches the form \(a + bi\), where \(a = 62\) and \(b = -10\).
Key Concepts
Distributive PropertyReal NumbersImaginary Numbers
Distributive Property
Imagine the distributive property as a technique that helps you to simplify expressions, especially when we're dealing with complex numbers. It allows us to multiply a pair of binomials by distributing each part of the first binomial across each part of the second. In the case of complex numbers, like our exercise
- (8 + 2i)(7 - 3i), we distribute numbers and letters in a sequence of steps.
- First: Multiply the first terms in the binomials, 8 and 7, to get 56.
- Outside: Multiply the outer terms, 8 and -3i, resulting in -24i.
- Inside: Multiply the inside terms, 2i and 7, producing 14i.
- Last: Multiply the last terms, 2i and -3i, which gives -6i2.
Real Numbers
Real numbers consist of all the numbers we encounter in everyday life: integers, fractions, and decimals. In complex numbers, the real part is the 'a' in the expression 'a + bi'.
In our example, after applying the distributive property to (8 + 2i)(7 - 3i), we identify the real numbers that result from the multiplications:
Real numbers anchor complex number expressions, helping them fit within familiar numeric systems we use regularly.
In our example, after applying the distributive property to (8 + 2i)(7 - 3i), we identify the real numbers that result from the multiplications:
- 8 multiplied by 7, giving us 56, is clearly a real number.
- From the multiplication of imaginary parts, -6i2 becomes 6, since i2 equals -1 and hence, -6i2 becomes 6.
Real numbers anchor complex number expressions, helping them fit within familiar numeric systems we use regularly.
Imaginary Numbers
Imaginary numbers are part of the foundation for understanding complex numbers. Represented by 'bi' in a complex number setup, 'b' is the coefficient for the imaginary unit 'i'.
The imaginary unit, 'i', is defined by the property i2 = -1. This property allows us to handle expressions involving square roots of negative numbers.
For our expression (8 + 2i)(7 - 3i):
The imaginary unit, 'i', is defined by the property i2 = -1. This property allows us to handle expressions involving square roots of negative numbers.
For our expression (8 + 2i)(7 - 3i):
- The multiplication 8 times -3i gives us -24i, and 2i times 7 gives 14i.
- Combining these imaginary components involves simple arithmetic: -24i plus 14i results in -10i.
Other exercises in this chapter
Problem 8
Exer. 3-12: Express the inequality as an interval, and sketch its graph. $$ -3 \leq x
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Exer. 1-50: Solve the equation. $$ 3 x^{3}-4 x^{2}-27 x+36=0 $$
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Exer. 1-14: Solve the equation by factoring. $$ 48 x^{2}+12 x-90=0 $$
View solution Problem 9
Solve the equation. $$0.3(3+2 x)+1.2 x=3.2$$
View solution