Problem 8
Question
Evaluate each expression. $$\frac{6 !}{5 ! 1 !}$$
Step-by-Step Solution
Verified Answer
6
1Step 1: Evaluate Factorials
Calculate the factorials involved in the expression. For \(6!\), \(5!\), and \(1!\): \[6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720\] \[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\] \[1! = 1\]
2Step 2: Substitute Factorials into the Expression
Substitute the evaluated factorials into the original expression: \[\frac{6!}{5! 1!} = \frac{720}{120 \times 1}\]
3Step 3: Simplify the Expression
Simplify the fraction by dividing \(720\) by \(120\): \[\frac{720}{120} = 6\]
Key Concepts
Evaluate FactorialsSimplify FractionsStep by Step Solution
Evaluate Factorials
Understanding factorials is the first step in evaluating and simplifying expressions like \(\frac{6!}{5! 1!}\). A factorial, denoted by \(n!\), represents the product of all positive integers up to \(n\). For example:
\[6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720\]
Similarly:
\[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\]
And for \(1!\), it's simply:
\[1! = 1\]
Factorial notation helps in quickly understanding how numbers multiply in a sequence. This is crucial for solving combinations, permutations, and many algebraic expressions.
\[6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720\]
Similarly:
\[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\]
And for \(1!\), it's simply:
\[1! = 1\]
Factorial notation helps in quickly understanding how numbers multiply in a sequence. This is crucial for solving combinations, permutations, and many algebraic expressions.
Simplify Fractions
Once we have the values of the factorials, the next step is to simplify the expression by substituting these values back into the original fraction. The key here is to substitute each evaluated factorial properly:
\[\frac{6!}{5! 1!} = \frac{720}{120 \times 1}\]
Here:
\[\frac{720}{120} = 6\]
Always remember to check if the numbers can be further divided to simplify the fraction to its lowest form.
\[\frac{6!}{5! 1!} = \frac{720}{120 \times 1}\]
Here:
- \(6! = 720\)
- \(5! = 120\)
- \(1! = 1\)
\[\frac{720}{120} = 6\]
Always remember to check if the numbers can be further divided to simplify the fraction to its lowest form.
Step by Step Solution
Breaking down each step makes solving factorial expressions much simpler. Here is a detailed step-by-step approach to evaluate \(\frac{6!}{5! 1!}\):
Step 1: Evaluate Factorials
Calculate the factorial of each number involved:
Step 2: Substitute Factorials into the Expression
Replace the factorials in the original fraction:
\[\frac{6!}{5! 1!} = \frac{720}{120 \times 1}\]
Step 3: Simplify the Expression
Now, simplify the fraction by dividing:
\[\frac{720}{120} = 6\]
These steps help you easily follow the logic and method to solve similar problems consistently and accurately.
Step 1: Evaluate Factorials
Calculate the factorial of each number involved:
- \(6! = 720\)
- \(5! = 120\)
- \(1! = 1\)
Step 2: Substitute Factorials into the Expression
Replace the factorials in the original fraction:
\[\frac{6!}{5! 1!} = \frac{720}{120 \times 1}\]
Step 3: Simplify the Expression
Now, simplify the fraction by dividing:
\[\frac{720}{120} = 6\]
These steps help you easily follow the logic and method to solve similar problems consistently and accurately.
Other exercises in this chapter
Problem 7
List all terms of each finite sequence. \(a_{n}=n^{2}\) for \(1 \leq n \leq 8\)
View solution Problem 8
Find the sum of each series. $$\sum_{j=0}^{3}(j+1)^{2}$$
View solution Problem 8
List all terms of each finite sequence. \(a_{n}=-n^{2}\) for \(1 \leq n \leq 4\)
View solution Problem 9
Find the sum of each series. $$\sum_{j=0}^{5}(2 j-1)$$
View solution