Problem 8
Question
Determine the slope and the \(y\) -intercept of the line whose equation is given. $$2 y+5 x-8=0$$
Step-by-Step Solution
Verified Answer
Slope is \(-\frac{5}{2}\) and y-intercept is 4.
1Step 1: Rearrange the Equation
The given equation is \(2y + 5x - 8 = 0\). To find the slope and y-intercept, we need to write it in the slope-intercept form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Start by isolating \(2y\) by moving the other terms to the right side of the equation: \(2y = -5x + 8\).
2Step 2: Solve for y
Divide every term in the equation \(2y = -5x + 8\) by 2 to solve for \(y\):\[ y = -\frac{5}{2}x + 4 \] This is now in the form \(y = mx + b\).
3Step 3: Identify the Slope
From the equation \(y = -\frac{5}{2}x + 4\), compare it with the slope-intercept form \(y = mx + b\). The coefficient of \(x\) (\(-\frac{5}{2}\)) is the slope \(m\).
4Step 4: Identify the y-Intercept
From the rearranged equation \(y = -\frac{5}{2}x + 4\), the constant term (\(4\)) is the y-intercept \(b\).
Key Concepts
Linear EquationSlopeY-Intercept
Linear Equation
A linear equation is what we often see in math. It's simply an equation that describes a straight line on a graph. Linear equations typically look like this: \( ax + by + c = 0 \), where \( a \), \( b \), and \( c \) are constants. In the exercise, the linear equation is given as \(2y + 5x - 8 = 0\).
- Linear means that if you were to graph the equation, it would appear as a straight line.
- The equation includes variables (like \(x\) and \(y\)) and constants (like \(2\), \(5\), and \(-8\)).
Slope
In the world of mathematics, the slope is a crucial part of any linear equation. It describes how steep a line is on a graph. You might also think of it as the angle or tilt of the line. In the equation \(y = mx + b\), \(m\) represents the slope.
- A positive slope means the line goes upwards as it moves from left to right.
- A negative slope means the line goes downwards as it moves from left to right.
Y-Intercept
The y-intercept is a vital component of a linear equation. It's the point where the line crosses the y-axis on a graph. In \(y = mx + b\), \(b\) is the y-intercept.
- It is the value of \(y\) when \(x\) is 0.
- This point can tell us a lot about the line itself, such as its starting point on the vertical axis.
Other exercises in this chapter
Problem 8
the function continuous on the interval? $$\frac{1}{\sin x} \text { on }\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$$
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For the functions \(f\) and \(g\) find (a) \(f(g(1))\) (b) \(g(f(1))\) (c) \(f(g(x))\) (d) \(g(f(x))\) (e) \(f(t) g(t)\) $$f(x)=x^{2}, g(x)=x+1$$
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Solve for \(x\) using logs. $$17^{x}=2$$
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In Exercises \(4-9,\) draw a possible graph of \(f(x) .\) Assume \(f(x)\) is defined and continuous for all real \(x\). $$\lim _{x \rightarrow 3} f(x)=5 \quad \
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