Problem 8

Question

Compute the integral. \(\int \frac{1}{x^{2}+1} d x\)

Step-by-Step Solution

Verified
Answer
The solution to the integral \(\int \frac{1}{x^{2}+1} d x\) is \(tan^{-1}(x) + C\).
1Step 1: Identify the Integral Type
The integral \(\int \frac{1}{x^{2}+1} d x\) is a formulaic integral, where the denominator is \(x^2+1\). This fits the direct formula of integral \(1/(x^2+1) dx = tan^{-1}(x) + C\).
2Step 2: Apply the Formula
By applying the appropriate formula, the integral can then be evaluated to be \(tan^{-1}(x) + C\). The constant of integration, C, is added as the result of the integral of any constant is a constant itself.

Key Concepts

Definite IntegralsIndefinite IntegralsTrigonometric Integrals
Definite Integrals
A definite integral is a way to calculate the net area under a curve over a closed interval from a one-dimensional function. Unlike indefinite integrals, definite integrals have boundaries. These boundaries are typically denoted as the lower limit and the upper limit of integration. In a sense, definite integrals provide a numerical value, which represents the accumulated area between the function and the x-axis over a specified interval.

When calculating a definite integral:
  • Begin by identifying the integrand, the boundary limits, and the variable of integration.
  • Proceed to find the antiderivative, which is the indefinite integral of the function.
  • Finally, evaluate the antiderivative at the given bounds and apply the fundamental theorem of calculus, subtracting the value of the lower bound from the upper bound.
If no bounds are provided, consider working on finding the indefinite integral first and then use specific bounds if they are subsequently defined. This allows for a clearer understanding of how the area under a curve can change with specified limits.
Indefinite Integrals
Indefinite integrals represent a family of functions and are often described as the reverse of differentiation. Unlike definite integrals, indefinite integrals do not have specific boundaries. They are expressions that include an arbitrary constant, usually denoted as \(C\). This constant is crucial because differentiation eliminates constants, and integration restores them.
  • The main purpose of indefinite integrals is to recover the original function, called the antiderivative, from its derivative.
  • The general form of an indefinite integral is \(\int f(x) \, dx\).
  • The result is \(F(x) + C\), where \(F(x)\) is the antiderivative of \(f(x)\), and \(C\) is the constant of integration.
Indefinite integrals are particularly useful in solving differential equations and analyzing problems involving rates of change.
Trigonometric Integrals
Trigonometric integrals are integrals involving trigonometric functions, and they often require specific techniques or identities to solve. These integrals can be complex, but by employing trigonometric identities and formulas, you can simplify them greatly.

A common scenario involves integrals of functions similar to the original exercise presented here. For example, the integral \(\int \frac{1}{x^2 + 1} \, dx\) uses the formula for inverse trigonometric functions. This specific integral results in the arctangent function, or \(\tan^{-1}(x) + C\). The transformation is directly related to the identity \(\frac{d}{dx}(\tan^{-1}(x)) = \frac{1}{x^2 + 1}\).

When dealing with trigonometric integrals:
  • Identify and apply the relevant trigonometric identities.
  • Use substitution when needed, often utilizing direct formulas for efficiency.
  • Always remember the constant of integration if computing indefinite integrals.
Such integrals require familiarity with trigonometric properties but can be mastered with practice and knowledge of fundamental identities.