Problem 8
Question
A pair of parametric equations is given. (a) Sketch the curve represented by the parametric equations. (b) Find a rectangular-coordinate equation for the curve by eliminating the parameter. $$x=t+1, \quad y=\frac{t}{t+1}$$
Step-by-Step Solution
Verified Answer
Curve: Plot points of \( (x, y) \) from the parametrics. Equation: \( y = \frac{x-1}{x} \).
1Step 1: Understand Parametric Equations
The given parametric equations are \( x = t + 1 \) and \( y = \frac{t}{t+1} \). These equations express both \( x \) and \( y \) in terms of the parameter \( t \). Our goal is to sketch the curve and then eliminate the parameter to find a rectangular-coordinate (Cartesian) equation.
2Step 2: Sketching the Parametric Curve
To sketch the curve, select values of \( t \) and calculate the corresponding \( x \) and \( y \) coordinates. For example:- \( t = -2 \): \( x = -1 \), \( y = \frac{-2}{-1} = 2 \)- \( t = 0 \): \( x = 1 \), \( y = 0 \)- \( t = 1 \): \( x = 2 \), \( y = \frac{1}{2} \)- \( t = 2 \): \( x = 3 \), \( y = \frac{2}{3} \)Plot these points and sketch the curve through them.
3Step 3: Solve for the Parameter t
From the equation \( x = t + 1 \), solve for \( t \):\[ t = x - 1 \]
4Step 4: Substitute to Eliminate the Parameter
Substitute \( t = x - 1 \) into the second equation \( y = \frac{t}{t+1} \):\[ y = \frac{x-1}{(x-1)+1} = \frac{x-1}{x} \]
5Step 5: Final Rectangular-Coordinate Equation
The rectangular-coordinate equation for the curve is \( y = \frac{x-1}{x} \). This equation relates \( x \) and \( y \) without the parameter \( t \).
Key Concepts
Rectangular CoordinatesEliminating the ParameterSketching Curves
Rectangular Coordinates
Rectangular coordinates, often referred to as Cartesian coordinates, provide a systematic way to locate points in a plane using two quantities, typically labeled as \(x\) and \(y\). This system is widely preferred because it offers a clear and straightforward representation of geometric shapes and curves. When you're given parametric equations like \(x = t + 1\) and \(y = \frac{t}{t+1}\), both \(x\) and \(y\) depend on a third variable, \(t\), known as the parameter. By converting these parametric equations to a single relation between \(x\) and \(y\), you obtain what is called a rectangular-coordinate equation. This process gives you a direct relationship, making it easier to plot points on a graph without needing to consider \(t\).
Understanding rectangular coordinates is crucial because it allows you to interpret equations in the way most familiar from school mathematics: as functions or relations graphed in the \(xy\)-plane. This method simplifies sketching and understanding geometric concepts.
Understanding rectangular coordinates is crucial because it allows you to interpret equations in the way most familiar from school mathematics: as functions or relations graphed in the \(xy\)-plane. This method simplifies sketching and understanding geometric concepts.
Eliminating the Parameter
To transform parametric equations into a rectangular-coordinate equation, you need to eliminate the parameter \(t\). This process involves expressing one of the parametric equations in terms of \(t\) and then substituting it into the other equation. For instance, from the given exercise, we start with the parametric equations \(x = t + 1\) and \(y = \frac{t}{t+1}\). By solving for \(t\) in terms of \(x\) using the first equation, we get:
\[ t = x - 1 \]
This substitution allows us to remove \(t\) from the system. Substituting \(t = x - 1\) into the second parametric equation, we achieve the rectangular-coordinate equation:
\[ y = \frac{x-1}{x} \]
By eliminating the parameter, we simplify the relationship to just \(x\) and \(y\), making the curve much easier to analyze and plot. Eliminating parameters is fundamental, especially when analyzing complex motion or shapes derived from parametric models.
\[ t = x - 1 \]
This substitution allows us to remove \(t\) from the system. Substituting \(t = x - 1\) into the second parametric equation, we achieve the rectangular-coordinate equation:
\[ y = \frac{x-1}{x} \]
By eliminating the parameter, we simplify the relationship to just \(x\) and \(y\), making the curve much easier to analyze and plot. Eliminating parameters is fundamental, especially when analyzing complex motion or shapes derived from parametric models.
Sketching Curves
Sketching curves from parametric equations is all about understanding how \(x\) and \(y\) change as \(t\) varies. Start by selecting several values for \(t\) and calculate corresponding \(x\) and \(y\) values. Using these points, you can begin sketching a rough outline of the curve. For example:
- When \(t = -2\), you get \(x = -1\) and \(y = 2\).
- For \(t = 0\), \(x = 1\) and \(y = 0\).
- When \(t = 1\), \(x = 2\) and \(y = \frac{1}{2}\).
- At \(t = 2\), \(x = 3\) and \(y = \frac{2}{3}\).
Other exercises in this chapter
Problem 7
Find the vertices, foci, and eccentricity of the ellipse. Determine the lengths of the major and minor axes, and sketch the graph. $$9 x^{2}+4 y^{2}=36$$
View solution Problem 7
Find the focus, directrix, and focal diameter of the parabola, and sketch its graph. $$y^{2}=4 x$$
View solution Problem 8
Determine the equation of the given conic in \(X Y\) -coordinates when the coordinate axes are rotated through the indicated angle. $$y=(x-1)^{2}, \quad \phi=45
View solution Problem 8
Find the vertex, focus, and directrix of the parabola, and sketch the graph. $$y^{2}=16 x-8$$
View solution