Problem 8
Question
A garden hose is used to fill a bucket in \(30.0 \mathrm{~s}\). If you cover part of the hose nozzle so the speed of the water leaving the hose doubles, how long does it take to fill the bucket?
Step-by-Step Solution
Verified Answer
The bucket will fill in 15 seconds when the speed of water doubles.
1Step 1: Understanding the Problem
We need to determine how long it will take to fill a bucket when the speed of water from the hose doubles. We know that initially, the bucket takes 30 seconds to fill with a certain speed.
2Step 2: Initial Time to Fill the Bucket
The initial time given to fill the bucket is 30 seconds at speed \(v\).
3Step 3: Effect of Doubling the Speed
If the speed of water doubles, the flow rate (volume/time) also doubles because the flow rate is directly proportional to speed.
4Step 4: Calculating the New Time
Since the flow rate is doubled, the time to fill the bucket reduces by half. Therefore, divide the initial time by 2 to get the new time.
5Step 5: Final Calculation
The new time taken to fill the bucket is \(\frac{30}{2} = 15\) seconds.
Key Concepts
Flow RateSpeed and Time RelationshipDoubling Speed EffectProportional Reasoning
Flow Rate
Flow rate is a key concept in fluid dynamics that helps us understand how quickly a fluid is moving. It is often expressed as the volume of fluid that passes a particular point in a given amount of time. In the example of filling a bucket with a garden hose, the flow rate would be the amount of water exiting the hose per second.
The formula for flow rate is given by the equation: \[Q = A \times v\] where \(Q\) is the flow rate, \(A\) is the cross-sectional area of the hose opening, and \(v\) is the speed of the water. By understanding this relationship, we can determine how changes in speed, such as doubling the speed, would impact the flow rate.
The formula for flow rate is given by the equation: \[Q = A \times v\] where \(Q\) is the flow rate, \(A\) is the cross-sectional area of the hose opening, and \(v\) is the speed of the water. By understanding this relationship, we can determine how changes in speed, such as doubling the speed, would impact the flow rate.
Speed and Time Relationship
The relationship between speed and time is crucial in determining how quickly an event occurs. This is particularly true in scenarios involving fluid flow, like with our garden hose example.
In basic terms, if the speed of a fluid increases, the time taken for a given volume of that fluid to reach a destination decreases. This shift can be visualized by considering that a bucket filled by a hose pressurized to deliver water at high speed would fill faster than if the water trickled slowly. The relationship is inversely proportional, meaning as one increases, the other decreases if the volume remains constant.
In basic terms, if the speed of a fluid increases, the time taken for a given volume of that fluid to reach a destination decreases. This shift can be visualized by considering that a bucket filled by a hose pressurized to deliver water at high speed would fill faster than if the water trickled slowly. The relationship is inversely proportional, meaning as one increases, the other decreases if the volume remains constant.
Doubling Speed Effect
When you double the speed of the flow, an interesting set of changes occurs. By doubling the flow speed, you’re effectively doubling the flow rate, assuming the cross-sectional area of the flow remains unchanged.
For the garden hose, doubling the speed implies that water exits the nozzle twice as fast, leading to a bucket filling in half the time it would initially. Hence, if the original time to fill was 30 seconds, with doubled speed, it reduces to 15 seconds. This is because the flow rate—volume per time unit—has increased, thus reducing the time required to fill the bucket with the same volume of water.
For the garden hose, doubling the speed implies that water exits the nozzle twice as fast, leading to a bucket filling in half the time it would initially. Hence, if the original time to fill was 30 seconds, with doubled speed, it reduces to 15 seconds. This is because the flow rate—volume per time unit—has increased, thus reducing the time required to fill the bucket with the same volume of water.
Proportional Reasoning
Proportional reasoning is a mathematical tool that helps us understand relationships between variables like speed, time, and flow rate.
In this particular problem, the understanding that doubling the speed also doubles the flow rate is rooted in proportional reasoning. By realizing that speed and flow rate are directly proportional, we can deduce the effect on time, which is inversely proportional to flow rate. This principle not only helps in this problem but is widely applicable in many real-world situations where understanding the relationship between changing quantities is essential. By practicing proportional reasoning, students can enhance their problem-solving skills, making complex problems simpler.
In this particular problem, the understanding that doubling the speed also doubles the flow rate is rooted in proportional reasoning. By realizing that speed and flow rate are directly proportional, we can deduce the effect on time, which is inversely proportional to flow rate. This principle not only helps in this problem but is widely applicable in many real-world situations where understanding the relationship between changing quantities is essential. By practicing proportional reasoning, students can enhance their problem-solving skills, making complex problems simpler.
Other exercises in this chapter
Problem 7
The MA of a hydraulic jack is \(250 .\) What force must be applied to lift an automobile weighing \(12,000 \mathrm{~N} ?\)
View solution Problem 7
Find the water pressure (in \(\mathrm{kPa}\) ) at the \(25.0\) -m level of a water tower containing water \(50.0 \mathrm{~m}\) deep.
View solution Problem 8
The small piston of a hydraulic press has an area of \(4.00 \mathrm{in}^{2}\). If the applied force is \(10.0 \mathrm{lb}\), what must the area of the large pis
View solution Problem 9
A liquid flows through a pipe with a diameter of \(0.50 \mathrm{~m}\) at a speed of \(4.20 \mathrm{~m} / \mathrm{s}\). What is the rate of flow in \(\mathrm{L}
View solution