Problem 8
Question
A bag of sand originally weighing \(600 \mathrm{N}\) was lifted at a constant rate. As it rose, sand also leaked out at a constant rate. The sand was half gone by the time the bag had been lifted to \(6 \mathrm{m} .\) How much work was done lifting the sand this far? (Neglect the weight of the bag and lifting equipment.)
Step-by-Step Solution
Verified Answer
2700 Joules of work was done.
1Step 1: Understand the Problem
We need to find out the work done to lift a bag of sand to 6 meters, considering that the sand leaks out at a constant rate so that half of it is gone by the time it reaches that height. The work done is the integral of force across the distance.
2Step 2: Determine Initial Conditions
Initially, the weight of the sand in the bag is 600 N. By the time it reaches 6 m, it weighs 300 N because the sand is leaking linearly, reducing the weight to half of its initial value.
3Step 3: Define the Force Function
Since the sand leaks at a constant rate while the bag is lifted, the weight of the sand as a function of height, h, is a linear function. Initially, at h = 0, the force is 600 N, and at h = 6 m, the force is 300 N. We can express this linearly as: \[ F(h) = 600 - 50h \]
4Step 4: Calculate the Work Done
The work done to lift the sand can be expressed as the integral of the force over the distance, from 0 to 6 m:\[ W = \int_{0}^{6} F(h) \, dh = \int_{0}^{6} (600 - 50h) \, dh \]
5Step 5: Integrate the Force Function
Calculate the integral:\[ W = \int_{0}^{6} (600 - 50h) \, dh = \left[ 600h - 25h^2 \right]_{0}^{6} \] Substitute the boundaries:\[ W = (600 \times 6 - 25 \times 6^2) - (600 \times 0 - 25 \times 0^2) \] \[ W = 3600 - 25 \times 36 \] \[ W = 3600 - 900 \] \[ W = 2700 \text{ J} \]
6Step 6: Conclusion
The total work done in lifting the bag of sand to 6 meters, considering the constant leak, is 2700 Joules.
Key Concepts
Integration in CalculusForce as a Function of DistancePhysics Problem-Solving
Integration in Calculus
Integration in calculus is a core concept used to solve problems involving accumulated quantities, such as work done when the force applied changes over a distance. In this physics problem, we use integration to calculate the total work done while lifting a bag of sand where the weight—and thus, the force—changes as sand leaks.
Integration helps to "sum up" the effects of these continuously changing quantities. For instance, when we lift the sand, the total work needed isn't simply force times distance because the force itself is not constant. **Instead**, we express force as a function of distance and integrate over that distance.
For our exercise, the function representing force is linear, decreasing as the sand leaks out. Calculus allows us to find the precise amount of work by integrating this function over the specified distance. The integration shows how calculus transforms a seemingly complex problem into manageable calculations.
Integration helps to "sum up" the effects of these continuously changing quantities. For instance, when we lift the sand, the total work needed isn't simply force times distance because the force itself is not constant. **Instead**, we express force as a function of distance and integrate over that distance.
For our exercise, the function representing force is linear, decreasing as the sand leaks out. Calculus allows us to find the precise amount of work by integrating this function over the specified distance. The integration shows how calculus transforms a seemingly complex problem into manageable calculations.
Force as a Function of Distance
In physics, force is often not a constant and can change depending on many factors, including distance. In the problem with the leaking sand, the force exerted at any point directly depends on how much sand remains in the bag as it is lifted.
To express force as a function of height, we begin with the maximum initial force, then reduce this force linearly as height increases and sand continues to leak. In mathematical terms, this can be represented with the function:
To express force as a function of height, we begin with the maximum initial force, then reduce this force linearly as height increases and sand continues to leak. In mathematical terms, this can be represented with the function:
- At a height of 0 meters, the force is 600 N.
- At a height of 6 meters, the force drops to 300 N.
- The linear function of force: \( F(h) = 600 - 50h \).
Physics Problem-Solving
Physics problem-solving often involves breaking down the problem into comprehensible parts and applying appropriate mathematical concepts. In the case of this exercise, understanding the physical context is essential: **a bag leaking sand as it's lifted**.
By using problem-solving strategies:
By using problem-solving strategies:
- Determine what you need to find. Here, it's the total work done.
- Express the given data mathematically; we used a function for the force based on height.
- Apply calculus for dynamic problems, integrating to accumulate effects such as the variable force over a distance.
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