Problem 8
Question
\(7-14\) A pair of points is graphed. (a) Plot the points in a coordinate plane. (b) Find the distance between them. (c) Find the midpoint of the segment that joins them. $$ (-2,5),(10,0) $$
Step-by-Step Solution
Verified Answer
The distance is 13, and the midpoint is (4, 2.5).
1Step 1: Plot the Points
Start by plotting the two given points on the coordinate plane. The first point is \((-2, 5)\) and the second point is \((10, 0)\). To plot these points, move left 2 units and up 5 units for the first point, and right 10 units with no upward movement for the second point.
2Step 2: Use the Distance Formula
To find the distance between the two points, use the distance formula: \[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Substituting the given points \((-2, 5)\) and \((10, 0)\), we have:\[d = \sqrt{(10 - (-2))^2 + (0 - 5)^2}\]\[d = \sqrt{(10 + 2)^2 + (-5)^2}\]\[d = \sqrt{12^2 + 25}\]\[d = \sqrt{144 + 25}\]\[d = \sqrt{169}\]\[d = 13\]
3Step 3: Use the Midpoint Formula
Find the midpoint using the midpoint formula:\[M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)\]Substitute \((-2, 5)\) and \((10, 0)\) into the formula:\[M = \left( \frac{-2 + 10}{2}, \frac{5 + 0}{2} \right)\]\[M = \left( \frac{8}{2}, \frac{5}{2} \right)\]\[M = (4, 2.5)\]Thus, the midpoint is \((4, 2.5)\).
Key Concepts
Distance FormulaMidpoint FormulaPlotting Points on a Coordinate Plane
Distance Formula
The distance formula is a handy tool for finding the distance between two points on a coordinate plane. This formula is derived from the Pythagorean theorem and can be used to calculate the straight-line distance, often called as "Euclidean distance."
To compute the distance, you first need the coordinates of both points. Consider the points are
Let's say the coordinates given are \((-2, 5)\) and \((10, 0)\). Use the formula:
To compute the distance, you first need the coordinates of both points. Consider the points are
- First point: \( (x_1, y_1) \)
- Second point: \( (x_2, y_2) \)
Let's say the coordinates given are \((-2, 5)\) and \((10, 0)\). Use the formula:
- \(d = \sqrt{(10 - (-2))^2 + (0 - 5)^2} \)
- \(d = \sqrt{12^2 + (-5)^2} \)
- \(d = \sqrt{144 + 25} \)
- \(d = \sqrt{169} = 13 \)
Midpoint Formula
The midpoint formula helps to find the exact middle point between two given points on the coordinate plane. The midpoint formula gives you the average position of the two endpoints.
To find the midpoint, use the coordinates of the endpoints. Assume these points are:
For points \((-2, 5)\) and \((10, 0)\), calculation proceeds as follows:
To find the midpoint, use the coordinates of the endpoints. Assume these points are:
- First point: \( (x_1, y_1) \)
- Second point: \( (x_2, y_2) \)
For points \((-2, 5)\) and \((10, 0)\), calculation proceeds as follows:
- \(M = \left( \frac{-2 + 10}{2}, \frac{5 + 0}{2} \right)\)
- \(M = \left( \frac{8}{2}, \frac{5}{2} \right)\)
- \(M = (4, 2.5) \)
Plotting Points on a Coordinate Plane
Plotting points on a coordinate plane is the fundamental step in understanding how to visually represent data. The coordinate plane is a two-dimensional surface formed by the intersection of a horizontal line known as the x-axis and a vertical line called the y-axis. These axes divide the plane into four quadrants.
To plot a point, you'll need an ordered pair like this:
For \((10, 0)\), start again at the origin, move to the right 10 units on the x-axis, as there's no movement on the y-axis.
Plotting these points accurately is necessary for applying further tools like the distance and midpoint formulas. It lays the groundwork for solving problems in coordinate geometry.
To plot a point, you'll need an ordered pair like this:
- Point: \( (x, y) \)
- \(x\) is the horizontal position and \(y\) is the vertical position.
For \((10, 0)\), start again at the origin, move to the right 10 units on the x-axis, as there's no movement on the y-axis.
Plotting these points accurately is necessary for applying further tools like the distance and midpoint formulas. It lays the groundwork for solving problems in coordinate geometry.
Other exercises in this chapter
Problem 8
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