Problem 8
Question
\(3-8=\) Test the series for convergence or divergence. $$ \sum_{n=1}^{\infty}(-1)^{n} \cos \left(\frac{\pi}{n}\right) $$
Step-by-Step Solution
Verified Answer
The series diverges because the Alternating Series Test fails.
1Step 1: Identify Series Type
The series in question is \( \sum_{n=1}^{\infty}(-1)^{n} \cos \left(\frac{\pi}{n}\right) \). Noticing \((-1)^n\), we see this is an alternating series.
2Step 2: Apply Alternating Series Test Conditions
The Alternating Series Test states a series \( \sum_{n=1}^{\infty}(-1)^n b_n \) converges if: (1) \( b_n > 0 \) for all \( n \), (2) \( b_{n+1} \leq b_n \) for all \( n \), and (3) \( \, \lim_{{n \to \infty}} \, b_n = 0 \). Here, \( b_n = \cos \left(\frac{\pi}{n}\right) \).
3Step 3: Check Positivity Condition
Examining \( \cos \left(\frac{\pi}{n}\right) \): since \( \frac{\pi}{n} \) is in the range \( (0, \pi) \) for \( n \geq 1 \), \( \cos \left(\frac{\pi}{n}\right) \) is positive. Thus, condition (1) is satisfied.
4Step 4: Verify Decreasing Sequence Condition
For condition (2), we need to check if \( \cos \left(\frac{\pi}{n+1}\right) \leq \cos \left(\frac{\pi}{n}\right) \). Given \( \cos(x) \) is a decreasing function in \((0, \pi)\), this holds true since \( \frac{\pi}{n+1} > \frac{\pi}{n} \). Thus, condition (2) is satisfied.
5Step 5: Evaluate the Limit of Terms
Lastly, we evaluate \( \, \lim_{{n \to \infty}} \, \cos \left(\frac{\pi}{n}\right) \). As \( n \) approaches infinity, \( \frac{\pi}{n} \to 0 \), and \( \cos(0) = 1 \). However, for convergence of an alternating series, this should equal zero, which is not the case here.
6Step 6: Conclusion on Convergence
Since condition (3) of the Alternating Series Test is not met (the limit does not equal zero), the series \( \sum_{n=1}^{\infty}(-1)^{n} \cos \left(\frac{\pi}{n}\right) \) diverges.
Key Concepts
ConvergenceDivergenceSeries TestAlternating Series Test
Convergence
In mathematical terms, convergence refers to the idea of whether a sequence or series approaches a specific value as its terms progress indefinitely. When we talk about a series converging, we mean that the sum of its infinite terms tends towards a finite number.
Understanding convergence is crucial when working with series because it tells us if our effort of summing infinitely many terms is worthwhile in terms of reaching a meaningful result.
Understanding convergence is crucial when working with series because it tells us if our effort of summing infinitely many terms is worthwhile in terms of reaching a meaningful result.
- Limits: The concept of limit is central to determining convergence. We check the limit of the series terms.
- Finite Sum: If the series converges, it sums to a finite value.
Divergence
Divergence, on the flip side of convergence, occurs when a sequence or series does not tend to a fixed limit or finite sum.
A divergent series will either grow indefinitely, oscillate, or behave erratically without settling to any constant.
It’s important for students to recognize convergence and divergence as two outcomes when summing an infinite series.
A divergent series will either grow indefinitely, oscillate, or behave erratically without settling to any constant.
- Behavior Pattern: A divergent series might increase indefinitely or oscillate without delivering a fixed outcome.
- Critical Understanding: Understanding divergence is essential because it tells us that the series does not yield a final, meaningful sum.
It’s important for students to recognize convergence and divergence as two outcomes when summing an infinite series.
Series Test
A series test comprises the strategies and methodologies employed to ascertain whether a series converges or diverges.
There are several tests, each with conditions that, when satisfied, provide insight into the nature of the series.
Knowing which test to apply requires understanding the form and structure of the series presented.
There are several tests, each with conditions that, when satisfied, provide insight into the nature of the series.
- D’Alembert’s Ratio Test: This is often used for series with factorials or exponential terms.
- Root Test: Helpful when terms involve power functions.
- Alternating Series Test: Specifically for series with alternating positive and negative terms.
Knowing which test to apply requires understanding the form and structure of the series presented.
Alternating Series Test
The Alternating Series Test helps determine the convergence of series featuring alternating positive and negative terms. It specifically applies when the series takes the form \[ \sum_{n=1}^{\infty}(-1)^n b_n \]where each term alternates in sign.
However, if any of these conditions are not satisfied, the series is likely divergent as shown in the original exercise.
- Positivity: Check that each term, ignoring the sign, remains positive.
- Decreasing Sequence: Ensure that the terms decrease in absolute value as the series progresses.
- Limit of Zero: Verify that the limit of the absolute terms as \( n \rightarrow \infty \) is zero.
However, if any of these conditions are not satisfied, the series is likely divergent as shown in the original exercise.
Other exercises in this chapter
Problem 8
Find the Taylor polynomial \(T_{3}(x)\) for the function \(f\) centered at the number \(a .\) Graph \(f\) and \(T_{3}\) on the same screen. $$f(x)=\tan ^{-1} x,
View solution Problem 8
Find the Maclaurin series for \(f(x)\) using the definition of a Maclaurin series. [Assume that \(f\) has a power series expansion. Do not show that \(R_{n}(x)
View solution Problem 8
Use the Integral Test to determine whether the series is convergent or divergent. $$\sum_{n=1}^{\infty} \frac{1}{\sqrt{n+4}}$$
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\(5-8=\) Find a formula for the general term \(a_{n}\) of the sequence, assuming that the pattern of the first few terms continues. $$\\{5,8,11,14,17, \ldots\\}
View solution