Problem 8
Question
20.8. The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8 . (a) What is the ideal efficiency of the engine? Use \(\gamma=1.40 .\) (b) The engine in a Dodge Viper G.2 has a slightly higher compression ratio of 9.6 . How much increase in the ideal efficiency results from this increase in the compression ratio?
Step-by-Step Solution
Verified Answer
The ideal efficiency increases by 2.6% with the higher compression ratio.
1Step 1: Understanding the Otto Cycle Efficiency Formula
The efficiency of an Otto cycle engine is given by the formula \( \eta = 1 - \frac{1}{{r^{\gamma - 1}}} \), where \( r \) is the compression ratio and \( \gamma \) is the heat capacity ratio. In this problem, \( \gamma = 1.40 \).
2Step 2: Calculating Ideal Efficiency for Mercedes-Benz
For the Mercedes-Benz SLK230 with a compression ratio of 8.8, substitute \( r = 8.8 \) and \( \gamma = 1.40 \) into the formula. Calculate:\[ \eta_{MB} = 1 - \frac{1}{{8.8^{1.40 - 1}}} \]This gives the ideal efficiency for the engine.
3Step 3: Substituting Values for Mercedes-Benz
First, calculate \( 8.8^{0.4} \). We get:\[ 8.8^{0.4} \approx 2.29 \]Now, substitute into the efficiency formula:\[ \eta_{MB} = 1 - \frac{1}{2.29} \approx 0.564 \text{ or } 56.4\% \]
4Step 4: Calculating Ideal Efficiency for Dodge Viper
For the Dodge Viper G.2 with a compression ratio of 9.6, substitute \( r = 9.6 \) and \( \gamma = 1.40 \) into the efficiency formula and calculate:\[ \eta_{DV} = 1 - \frac{1}{{9.6^{1.40 - 1}}} \]
5Step 5: Substituting Values for Dodge Viper
First, calculate \( 9.6^{0.4} \). We find:\[ 9.6^{0.4} \approx 2.44 \]Now, substitute into the efficiency formula:\[ \eta_{DV} = 1 - \frac{1}{2.44} \approx 0.590 \text{ or } 59.0\% \]
6Step 6: Calculating Increase in Efficiency
To find the increase in the ideal efficiency due to the change in compression ratio, calculate the difference:\[ \text{Increase in Efficiency} = \eta_{DV} - \eta_{MB} = 0.590 - 0.564 = 0.026 \text{ or } 2.6\% \]
7Step 7: Conclusion
The ideal efficiency of the Mercedes-Benz engine is 56.4%, and the Dodge Viper's ideal efficiency is 59.0%. The increase in ideal efficiency from the higher compression ratio is 2.6%.
Key Concepts
Compression RatioHeat Capacity RatioIdeal Efficiency CalculationThermodynamics
Compression Ratio
The compression ratio is a crucial factor in internal combustion engines that significantly affects engine efficiency and performance. It is defined as the ratio of the maximum to minimum volume in the cylinder of an engine.
- High compression ratios imply that the engine can compress the air-fuel mixture more efficiently, leading to better extraction of energy from the fuel.
- In the case of the Mercedes-Benz SLK230, the compression ratio is 8.8.
- The Dodge Viper G.2 features a slightly higher compression ratio of 9.6, contributing to its enhanced performance.
Heat Capacity Ratio
The heat capacity ratio, often represented by the Greek letter \( \gamma \), plays an integral role in determining the efficiency of an Otto cycle engine. It is the ratio of the specific heat at constant pressure (\( C_p \)) to the specific heat at constant volume (\( C_v \)).
- In thermal engines, the heat capacity ratio affects the expansion and compression of gases, thereby influencing the thermodynamic cycles.
- A typical value for the heat capacity ratio for air (which is assumed for most Otto cycle calculations) is about 1.40, as used in both the Mercedes-Benz and Dodge Viper calculations.
- The heat capacity ratio is vital because it dictates how much temperature will rise when a gas is compressed, which in turn affects efficiency.
Ideal Efficiency Calculation
Ideal efficiency in an Otto cycle engine is a theoretical calculation that indicates the maximum efficiency the engine could achieve under perfect conditions. It is derived using the formula \( \eta = 1 - \frac{1}{r^{\gamma - 1}} \).
- The term \( r \) is the compression ratio, and \( \gamma \) is the heat capacity ratio.
- For the Mercedes-Benz SLK230, the efficiency calculated with a compression ratio of 8.8 and \( \gamma = 1.40 \) results in approximately 56.4%.
- For the Dodge Viper G.2, with a higher compression ratio of 9.6, the efficiency increases to about 59.0%.
- This demonstrates the importance of both the compression ratio and the heat capacity ratio in maximizing the efficiency of an internal combustion engine.
Thermodynamics
Thermodynamics is the scientific study of heat transfer and work, particularly as it pertains to engines and machinery. In the context of the Otto cycle engine, thermodynamics explores how the energy from fuel is converted into mechanical work.
- The Otto cycle is a fundamental thermodynamic cycle that describes the operation of spark-ignition engines.
- It consists of four distinct processes: two adiabatic (no heat transfer) and two isochoric (constant volume) processes.
- Understanding thermodynamics enables the calculation of crucial metrics like engine efficiency, which can be optimized by adjusting variables like compression and heat capacity ratios.
Other exercises in this chapter
Problem 6
20.6. (a) Calculate the theoretical efficiency for an Otto cycle engine with \(\gamma=1.40\) and \(r=9.50 .\) (b) If this engine takes in \(10,000\) J of heat f
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20\. 07. What compression ratio \(r\) must an Otto cycle have to achieve an ideal efficiency of 65.0\(\%\) if \(\gamma=1.40 ?\)
View solution Problem 9
20.9. A refrigerator has a coefficient of performance of \(2.10 .\) In cach cycle it absorbs \(3.40 \times 10^{4} \mathrm{J}\) of heat from the cold reservoir.
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20.10. A room air conditioner has a coefficient of performance of 29 on a hot day, and uses 850 \(\mathrm{W}\) of electrical power. (a) How many joules of heat
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