Problem 79
Question
Which of these is a Lewis acid? A Lewis base? (a) \(\mathrm{NH}_{3}\) (b) \(\mathrm{BeCl}_{2}\) (c) \(\mathrm{BCl}_{3}\)
Step-by-Step Solution
Verified Answer
\(\mathrm{NH}_{3}\) is a Lewis base; \(\mathrm{BeCl}_{2}\) and \(\mathrm{BCl}_{3}\) are Lewis acids.
1Step 1: Identify Lewis Acid and Lewis Base
A Lewis acid is a substance that can accept a pair of electrons, while a Lewis base is a substance that can donate a pair of electrons. We will analyze each compound to determine which category they fall into.
2Step 2: Analyze \\(\mathrm{NH}_{3}\\)
The molecule \(\mathrm{NH}_{3}\) (ammonia) has a lone pair of electrons on the nitrogen atom, which it can donate to an acceptor. Hence, \(\mathrm{NH}_{3}\) is a Lewis base.
3Step 3: Analyze \\(\mathrm{BeCl}_{2}\\)
\(\mathrm{BeCl}_{2}\), or beryllium chloride, has beryllium in a \(sp\) hybridization state and is electron-deficient, which allows it to accept a pair of electrons. Therefore, it acts as a Lewis acid.
4Step 4: Analyze \\(\mathrm{BCl}_{3}\\)
The molecule \(\mathrm{BCl}_{3}\) (boron trichloride) is also electron-deficient due to the boron atom lacking a complete octet, making it capable of accepting an electron pair. Therefore, \(\mathrm{BCl}_{3}\) is a Lewis acid.
Key Concepts
Electron Pair AcceptorElectron Pair DonorMolecular Analysis
Electron Pair Acceptor
In chemistry, an electron pair acceptor is often referred to as a Lewis acid. These substances can accept an electron pair from another substance.
A classic example of a Lewis acid is a molecule that is electron-deficient. This deficiency allows it to attract and accept an electron pair from a donor.
A classic example of a Lewis acid is a molecule that is electron-deficient. This deficiency allows it to attract and accept an electron pair from a donor.
- For instance, beryllium chloride (\( \mathrm{BeCl}_{2} \)) acts as a Lewis acid because the beryllium atom is surrounded by only four electrons, which is less than a full octet.
- Similarly, boron trichloride (\( \mathrm{BCl}_{3} \)) also functions as a Lewis acid. The boron atom in \( \mathrm{BCl}_{3} \) is also electron-deficient, motivating it to accept additional electrons to achieve stability.
Electron Pair Donor
In contrast to an electron pair acceptor, an electron pair donor is called a Lewis base. It has electrons that it can donate to another molecule, often filling the deficiency present in a Lewis acid.
These electron pairs, typically found as lone pairs on atoms, are key to their identification as donors.
These electron pairs, typically found as lone pairs on atoms, are key to their identification as donors.
- Take ammonia, \(\mathrm{NH}_{3}\), for example. The nitrogen atom in ammonia has a lone pair of electrons.
- This lone pair is readily available to be donated to a Lewis acid, which makes \(\mathrm{NH}_{3}\) a strong Lewis base.
Molecular Analysis
Molecular analysis is the thorough examination of a compound's structure to determine its potential to act as a Lewis acid or base. By understanding the arrangement of electrons, you can predict how a molecule might behave in different chemical reactions.
This process involves:
This process involves:
- Looking at electron configurations to identify instances of electron deficiency or surplus.
- Checking for lone pairs that signify potential for electron donation.
- Identifying hybridization states that signal a molecule's ability to accept electrons.
- \(\mathrm{NH}_{3}\), with its lone pairs, is identified as a Lewis base.
- Beryllium chloride, \(\mathrm{BeCl}_{2}\), and boron trichloride, \(\mathrm{BCl}_{3}\), lacking full electron shells, are recognized as Lewis acids.
Other exercises in this chapter
Problem 77
Which of these is a Lewis acid? A Lewis base? (a) \(\mathrm{Al}^{3+}\) (b) \(\mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{SCN}^{-}\)
View solution Problem 78
Which of these is a Lewis acid? A Lewis base? (a) \(\mathrm{Cr}^{3+}\) (b) \(\mathrm{SO}_{3}\) (c) \(\mathrm{CH}_{3} \mathrm{NH}_{2}\)
View solution Problem 80
Identify the Lewis acid and the Lewis base in each reaction. (a) \(\mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{SO}_{2}(\mathrm{aq}) \longrightarrow \mathrm{H}_{2} \
View solution Problem 81
Identify the Lewis acid and the Lewis base in each reaction. (a) \(\mathrm{I}_{2}(\mathrm{~s})+\mathrm{I}^{-}(\mathrm{aq}) \longrightarrow \mathrm{I}_{3}^{-}(\m
View solution