Problem 79
Question
Which of the following are formed when \(\mathrm{BCl}_{3}\) is treated with \(\mathrm{NH}_{3}\). (a) \(\mathrm{B}\left(\mathrm{NH}_{2}\right)_{3}\) (b) \(\mathrm{B}_{2}\left(\mathrm{NH}_{3}\right)_{2}\) (c) \(\mathrm{BN}\) (d) All of these
Step-by-Step Solution
Verified Answer
(a) \(\mathrm{B\left(NH_2\right)_3}\) and (c) \(\mathrm{BN}\) are formed.
1Step 1: Understanding the Reaction
When \(\mathrm{BCl}_3\) is treated with \(\mathrm{NH}_3\), \(\mathrm{BCl}_3\) acts as a Lewis acid (electron pair acceptor) and \(\mathrm{NH}_3\) acts as a Lewis base (electron pair donor). The reaction involves \(\mathrm{NH}_3\) donating a lone pair to \(\mathrm{BCl}_3\) to form an adduct.
2Step 2: Formation of Adduct
Initially, \(\mathrm{BCl}_3\) and \(\mathrm{NH}_3\) combine to form the adduct \(\mathrm{Cl}_3\mathrm{B}-\mathrm{NH}_3\). This complex can lead to further reactions, eventually leading to polymeric nitrogen-boron compounds.
3Step 3: Decomposition to Other Products
The interaction can lead to the loss of hydrogen chloride (\(\mathrm{HCl}\)), forming \(\mathrm{B\left(NH_2\right)_3}\) after elimination of \(\mathrm{HCl}\) molecules. Thermal decomposition of these adducts can sometimes yield \(\mathrm{BN}\) in a polymeric form.
4Step 4: Conclusion on Possible Products
Both \(\mathrm{B\left(NH_2\right)_3}\) and \(\mathrm{BN}\) are typically formed during the reaction process. There is no mention of \(\mathrm{B_2\left(NH_3\right)_2}\) as a common product without detailed conditions; thus it is not included in typical reaction predictions.
Key Concepts
Lewis Acids and BasesAdduct FormationPolymeric Compounds
Lewis Acids and Bases
In the realm of inorganic chemistry, the terms "Lewis acids" and "Lewis bases" are crucial to understanding molecular interactions. A Lewis acid is defined as a substance that can accept a pair of electrons. On the other hand, a Lewis base is an entity that donates electron pairs.
- Take \( \mathrm{BCl}_3 \) for example. It is a renowned Lewis acid because of its electron-deficient boron center.
- Ammonia, \( \mathrm{NH}_3 \), serves as a Lewis base since it has a lone pair of electrons available for donation.
Adduct Formation
Adduct formation is a fundamental concept in chemistry, particularly in reactions involving Lewis acids and bases. When talking about adduct formation, it refers to the creation of a complex where two or more distinct molecules come together.
- Initially, when \( \mathrm{BCl}_3 \) and \( \mathrm{NH}_3 \) react, they form an adduct by combining into \( \mathrm{Cl}_3\mathrm{B}-\mathrm{NH}_3 \).
- This complex manifests itself through the new covalent bond between boron and nitrogen, highlighting the transfer of an electron pair from nitrogen to boron.
Polymeric Compounds
Polymeric compounds, often resulting from chemical reactions involving simple molecules, have a wide array of applications. An interesting example is when the adduct \( \mathrm{Cl}_3\mathrm{B}-\mathrm{NH}_3 \) undergoes further reaction steps.
- Through the release of hydrochloric acid (\( \mathrm{HCl} \)), one possible product is \( \mathrm{B\left(NH_2\right)_3} \). This can be considered a step towards polymerization.
- At higher temperatures, these intermediates can decompose further into polymeric boron nitride (\( \mathrm{BN} \)).
Other exercises in this chapter
Problem 77
Fluorine is obtained by the interaction of \(\mathrm{K}_{2} \mathrm{MnF}_{6}\) with Lewis acid \(\mathrm{SbF}_{5}\) because of the (a) acidalysis of \(\mathrm{M
View solution Problem 78
Which of the following is used during the preparation of fluorine by Whytlaw- Gray method? (a) aqueous HF (b) molten \(\mathrm{KHF}_{2}\) (c) \(\mathrm{NH}_{4}
View solution Problem 80
Bleaching powder reacts with a few drops of concentrated \(\mathrm{HCl}\) to give (a) oxygen (b) calcium oxide (c) chlorine (d) hypochlorous acid
View solution Problem 81
When chlorine is passed over dry slaked lime at room temperature, the main reaction product is (a) \(\mathrm{CaCl}_{2}\) (b) \(\mathrm{Ca}(\mathrm{OCl})_{2}\) (
View solution