Problem 79
Question
What is the momentum in MeV \(/ c\) of an electron with a kinetic energy of \(2.00 \mathrm{MeV} ?\)
Step-by-Step Solution
Verified Answer
The momentum is approximately 2.457 MeV/c.
1Step 1: Understand the Kinetic Energy Formula for Relativistic Electron
In relativistic physics, the relationship between total energy \( E \), rest energy \( E_0 \), and kinetic energy \( K \) is given by: \( E = E_0 + K \), where \( E_0 = m_0c^2 \) is the rest energy of the electron. Here, \( m_0 \) is the rest mass of the electron and \( c \) is the speed of light.
2Step 2: Introduce the Relativistic Energy-Momentum Relation
The relation between energy, momentum, and mass in relativistic settings is given by: \( E^2 = (pc)^2 + (m_0c^2)^2 \). We need to find the momentum \( p \), with given kinetic energy \( K = 2.00 \text{ MeV} \).
3Step 3: Calculate the Total Energy
The rest mass energy of an electron is \( m_0c^2 = 0.511 \text{ MeV} \). With \( K = 2.00 \text{ MeV} \), the total energy \( E \) is \( E = 0.511 + 2.00 = 2.511 \text{ MeV} \).
4Step 4: Apply the Relativistic Energy-Momentum Relation
Using the equation \( E^2 = (pc)^2 + (m_0c^2)^2 \), plug in the values: \( (2.511)^2 = (pc)^2 + (0.511)^2 \).
5Step 5: Solve for Momentum (p)
Rearrange the equation to solve for \((pc)^2\) and then for \( p \): \[ (pc)^2 = (2.511)^2 - (0.511)^2. \] Calculate \((2.511)^2 = 6.3008\) and \((0.511)^2 = 0.2611\). Therefore, \((pc)^2 = 6.3008 - 0.2611 = 6.0397\). So, \( pc = \sqrt{6.0397} = 2.457 \text{ MeV} \). Thus, \( p = 2.457 \text{ MeV} / c \).
Key Concepts
Kinetic EnergyRelativistic Energy-Momentum RelationRest Energy
Kinetic Energy
Kinetic energy, often abbreviated as KE, is the energy that an object possesses due to its motion. In the context of relativistic physics, kinetic energy is part of the total energy equation for particles moving at speeds close to the speed of light. Here’s why this is important:
- The classical formula for kinetic energy (\( K = \frac{1}{2}mv^2 \)) becomes inadequate at high velocities.
- For high-speed particles, kinetic energy is calculated using the relativistic energy formula: \( E = E_0 + K \), where \( E_0 \) is the rest energy of the particle.
- This shows how energy accumulates differently at relativistic speeds compared to everyday speeds.
Relativistic Energy-Momentum Relation
The relativistic energy-momentum relation is a cornerstone of modern physics. It connects energy, momentum, and rest mass in the realm of special relativity. Understanding this relationship is crucial:
- It is expressed as: \( E^2 = (pc)^2 + (m_0 c^2)^2 \). This equation shows the interplay between momentum \( p \), speed of light \( c \), and rest mass energy \( m_0c^2 \).
- The formula unifies concepts of energy and momentum, applying to all particles no matter their speed.
- It provides a method to calculate momentum when energy is known, which is essential in understanding particle behavior in high-energy physics.
Rest Energy
Rest energy is the energy an object contains due to its rest mass, as per the famous equation \( E_0 = m_0c^2 \). Here’s what makes rest energy significant:
- It represents the "energy at rest," meaning it is the intrinsic energy a particle has even without movement.
- Rest energy is fundamental in calculations involving high-energy and relativistic particles.
- This form of energy explains how mass could theoretically be transformed into energy, essential for concepts like nuclear energy.
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