Problem 79
Question
The Hubble Space Telescope is in low earth orbit traveling at an average speed of 16,950 miles per hour. What distance does it travel in \(11 / 2\) hours?
Step-by-Step Solution
Verified Answer
The Hubble Space Telescope travels 93,225 miles in 5.5 hours.
1Step 1: Identify the Formula
To find the distance traveled, we need to use the formula for distance, which is given by: \[ \text{Distance} = \text{Speed} \times \text{Time} \]
2Step 2: Convert Time Fraction to Decimal
The time given is \(11/2\) hours. First, we convert this fraction to a decimal. \[ \frac{11}{2} = 5.5 \text{ hours} \]
3Step 3: Substitute Values into the Formula
Using the formula from Step 1, substitute the speed \(16,950\) miles per hour and the time \(5.5\) hours: \[ \text{Distance} = 16,950 \times 5.5 \]
4Step 4: Calculate the Distance
Perform the multiplication to find the distance:\[ 16,950 \times 5.5 = 93,225 \] So, the distance traveled is 93,225 miles.
Key Concepts
Speed and DistanceFraction to Decimal ConversionMultiplication in Algebra
Speed and Distance
The concepts of speed and distance are tightly connected in physics and everyday life. Understanding them helps in calculating how far an object travels over time. Speed is the rate at which an object covers distance. It’s usually measured in miles per hour (mph) or kilometers per hour (kph).
To find the distance an object travels, we use a simple and crucial formula:
- Distance = Speed × Time
Fraction to Decimal Conversion
Converting fractions to decimals is a useful skill across different areas of math and science. It’s especially important when dealing with equations that involve decimals such as the distance formula. Converting fractions to decimals can simplify calculations and make them more manageable.To convert a fraction like \(\frac{11}{2}\) into a decimal, divide the numerator by the denominator:
- 11 (numerator) ÷ 2 (denominator) = 5.5
Multiplication in Algebra
Multiplication in algebra often involves more than just numbers; it can include variables, constants, and coefficients. However, even when multiplying plain numbers, it's crucial to understand how this operation fits into formulas and equations.
In the given exercise, we execute multiplication to find distance:
- Distance = Speed (16,950) multiplied by Time (5.5)
- The product is 93,225
Other exercises in this chapter
Problem 79
Solve for the indicated variable. $$ \text { Solve for } y: \quad a x+b y=c $$
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Translate the following sentences into linear equations and then solve. Four added to three times a number \(n\) is \(25 .\)
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Solve and graph the solution set. In addition, present the solution set in interval notation. $$ 13 x+3 \geq-2 \text { or } 13 x+3 \leq 2 $$
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The length of a rectangle is 7 centimeters less than twice its width. If the perimeter measures 46 centimeters, then find the dimensions of the rectangle.
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