Problem 79
Question
Solve each equation. $$ x-5=0 $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \( x = 5 \).
1Step 1: Isolate the Variable
Our equation is \( x - 5 = 0 \). The goal is to solve for \( x \). First, add 5 to both sides of the equation to isolate \( x \). So we have \( x - 5 + 5 = 0 + 5 \).
2Step 2: Simplification
This simplifies to \( x = 5 \). Now \( x \) is by itself, and we have found the value of \( x \).
3Step 3: Verification
To double-check, substitute \( x = 5 \) back into the original equation: \( 5 - 5 = 0 \). Since the equation holds true, our solution \( x = 5 \) is correct.
Key Concepts
Isolation of VariablesSimplification in AlgebraVerification of Solutions
Isolation of Variables
The isolation of variables is the process of getting the variable by itself on one side of the equation. This is a critical first step in solving linear equations. By isolating the variable, we can determine its value by making everything else disappear from that side.
To isolate the variable, we perform algebraic operations that simplify the equation while keeping it balanced. Think of it as balancing a scale—what you do to one side, you must do to the other.
To isolate the variable, we perform algebraic operations that simplify the equation while keeping it balanced. Think of it as balancing a scale—what you do to one side, you must do to the other.
- Identify the term with the variable. In our example, it's the "x" in the equation x - 5 = 0.
- Decide what needs to be removed to isolate the variable. Here, the "-5" needs to go.
- Add 5 to both sides to cancel out the -5: x - 5 + 5 = 0 + 5.
- This manipulation leaves us with x = 5, nicely isolated.
Simplification in Algebra
Simplification in algebra involves reducing expressions to their most basic form. Once we've isolated the variable, it's time to simplify the equation to reveal the variable's value. Simplifying makes equations more manageable and solutions more evident.
In the given equation, once the variable is isolated (as in x = 5), our work is nearly done. But simplification doesn't just occur at the end; it can also mean tidying up all the terms during the process of solving.
In the given equation, once the variable is isolated (as in x = 5), our work is nearly done. But simplification doesn't just occur at the end; it can also mean tidying up all the terms during the process of solving.
- Evaluate changes: After adding 5 to both sides, look at what remains: x = 5.
- Ensure there's no unnecessary clutter: The equation has become simpler, free of other operations or terms.
- The outcome is a clear, direct solution statement: x = 5.
Verification of Solutions
Verification of solutions is an essential final step in solving equations. This process confirms that our solution is correct and that no mistakes have been made. By verifying, we can be confident in the accuracy of our answer.
For verification:
For verification:
- Substitute the found value back into the original equation. Here, replace x with 5 in x - 5 = 0.
- Perform the operation: 5 - 5 = 0.
- Check if both sides of the equation are equal. They are, indicating our solution is correct.
Other exercises in this chapter
Problem 78
Factor out the GCF from each polynomial. Then factor by grouping. $$ 90+15 y^{2}-18 x-3 x y^{2} $$
View solution Problem 78
Write a quadratic equation that has two solutions, 0 and -2 . Leave the polynomial in the equation in factored form.
View solution Problem 79
Factor out the GCF from each polynomial. Then factor by grouping. $$ 6 a^{2}+9 a b^{2}+6 a b+9 b^{3} $$
View solution Problem 79
Complete each sentence in your own words. If \(x^{2}+b x+c\) is factorable and \(c\) is negative, then the signs of the last-term factors of the binomials are o
View solution