Problem 79
Question
Solve absolute value inequality. \(3|x-1|+2 \geq 8\)
Step-by-Step Solution
Verified Answer
\(x \leq -1\) or \(x \geq 3\)
1Step 1: Simplify the equation
First, subtract 2 from both sides of the equation to isolate the absolute value term. This results in \(3|x-1| \geq 6\). Then, divide both sides of the inequality by 3 to further isolate the absolute value term giving \(|x-1| \geq 2\). This is the inequality that needs to be solved.
2Step 2: Resolve the absolute value
Next, resolve the absolute value. If \(y = |x-1|\) then the possible scenarios are \(y=x-1\) and \(y= -(x-1)\) . Apply these scenarios to inequalities \(|x-1| \geq 2\), which results in two inequalities \(x-1 \geq 2\) and \(-(x-1) \geq 2\).
3Step 3: Solve the inequalities
Now solve each inequality separately. Adding 1 to both sides of the first inequality gives \(x \geq 3\). For the second inequality, multiply through by -1 (and reverse the inequality symbol) to give \(x-1 \leq -2\) and then, adding 1 to both sides gives \(x \leq -1\).
4Step 4: Combination of the results
The solutions to the original inequality are the combination of the solutions to the two separate inequalities. Therefore, \(x\) could be anything less than or equal to -1 or greater than or equal to 3. This is the final solution to the given absolute value inequality.
Key Concepts
Solving InequalitiesAlgebraic ExpressionsAbsolute Value Properties
Solving Inequalities
Inequalities express a relationship where two expressions may not be equal. They tell us how one expression relates to another. In math, commonly used inequality symbols include:
- \( > \) - Greater than
- \( < \) - Less than
- \( \geq \) - Greater than or equal to
- \( \leq \) - Less than or equal to
Algebraic Expressions
Algebraic expressions are powerful tools in mathematics. They consist of numbers, variables (like \(x\)), and arithmetic operations. They are used extensively to represent real-world scenarios in mathematical form.
For instance, in the inequality \(3|x-1| \geq 6\), \(3|x-1|\) is an algebraic expression where three multiplies the absolute value of \(x-1\). This expression can be rewritten and manipulated to simplify the inequality.
Understanding the structure of these expressions allows us to rearrange the terms using operations like addition, subtraction, multiplication, and division. In problem-solving, identify the like terms to combine and isolate the necessary terms to further simplify the challenge. This process helps in deriving the solution step by step. As seen, algebraic manipulations helped us bring the problem to determine conditions for \( x \), so it's less daunting.
For instance, in the inequality \(3|x-1| \geq 6\), \(3|x-1|\) is an algebraic expression where three multiplies the absolute value of \(x-1\). This expression can be rewritten and manipulated to simplify the inequality.
Understanding the structure of these expressions allows us to rearrange the terms using operations like addition, subtraction, multiplication, and division. In problem-solving, identify the like terms to combine and isolate the necessary terms to further simplify the challenge. This process helps in deriving the solution step by step. As seen, algebraic manipulations helped us bring the problem to determine conditions for \( x \), so it's less daunting.
Absolute Value Properties
Absolute value represents the distance of a number from zero on the number line, without considering direction. This means \(|x|\) is always positive or zero.
An absolute value inequality like \(|x-1| \geq 2\) sets a condition where the distance between \(x\) and 1 is at least 2. To solve it, you translate it into a range of numbers that satisfy the condition. This involves breaking the problem into two parts:
An absolute value inequality like \(|x-1| \geq 2\) sets a condition where the distance between \(x\) and 1 is at least 2. To solve it, you translate it into a range of numbers that satisfy the condition. This involves breaking the problem into two parts:
- When the expression inside the absolute value is non-negative - solve \(x - 1 \geq 2\)
- When the expression inside the absolute value is negative - solve \(-(x - 1) \geq 2\) which simplifies to \(x - 1 \leq -2\)
Other exercises in this chapter
Problem 78
Exercises \(78-80\) will help you prepare for the material covered in the next section. Factor: $$ 2 x^{2}+7 x-4 $$
View solution Problem 78
List the quadrant or quadrants satisfying each condition. $$x^{3}0$$
View solution Problem 79
combine the types of equations we have discussed in this section. Solve each equation. Then state whether the equation is an identity, a conditional equation, o
View solution Problem 79
In Exercises \(75-82\), compute the discriminant. Then determine the number and type of solutions for the given equation. $$x^{2}-2 x+1=0$$
View solution