Problem 79
Question
Radiator Coolant The coolant in an automobile radiator freezes at \(-39^{\circ} \mathrm{C}\) and boils at \(110^{\circ} \mathrm{C} .\) What are these temperatures on the Fahrenheit scale?
Step-by-Step Solution
Verified Answer
Answer: The freezing point of the radiator coolant in Fahrenheit is -38.2°F, and the boiling point is 230°F.
1Step 1: Convert the freezing point to Fahrenheit
We will use the conversion formula for the freezing point of the coolant. Given °C = -39, let's find the temperature in °F.
°F = (-39 × 9/5) + 32
2Step 2: Calculate the freezing point in Fahrenheit
Now we will perform the calculations.
°F = (-39 × 9/5) + 32
°F = (-351/5) + 32
°F = -70.2 + 32
°F = -38.2
So, the freezing point of the radiator coolant in Fahrenheit is -38.2°F.
3Step 3: Convert the boiling point to Fahrenheit
We will use the conversion formula for the boiling point of the coolant. Given °C = 110, let's find the temperature in °F.
°F = (110 × 9/5) + 32
4Step 4: Calculate the boiling point in Fahrenheit
Now we will perform the calculations.
°F = (110 × 9/5) + 32
°F = (990/5) + 32
°F = 198 + 32
°F = 230
So, the boiling point of the radiator coolant in Fahrenheit is 230°F.
Key Concepts
Celsius to FahrenheitFreezing PointBoiling Point
Celsius to Fahrenheit
Temperature conversion between Celsius and Fahrenheit is a common task, especially in fields like science and engineering.
One of the most important formulas for conversion is:
Let's break it down:- Multiply the Celsius value by \( \frac{9}{5} \) (or 1.8).- Then, add 32 to this result.
This method allows you to convert any Celsius value to its equivalent in Fahrenheit easily. Used in the provided exercise, this formula translates the answer we need by using simple algebra.
One of the most important formulas for conversion is:
- \( \text{°F} = \left( \text{°C} \times \frac{9}{5} \right) + 32 \)
Let's break it down:- Multiply the Celsius value by \( \frac{9}{5} \) (or 1.8).- Then, add 32 to this result.
This method allows you to convert any Celsius value to its equivalent in Fahrenheit easily. Used in the provided exercise, this formula translates the answer we need by using simple algebra.
Freezing Point
The freezing point is the temperature at which a liquid turns into a solid.
For water, this is 0°C in Celsius and 32°F in Fahrenheit. However, different substances have different freezing points. In the example of radiator coolant, the freezing point is well below that of water, at \(-39^{\circ} \text{C}\).
For water, this is 0°C in Celsius and 32°F in Fahrenheit. However, different substances have different freezing points. In the example of radiator coolant, the freezing point is well below that of water, at \(-39^{\circ} \text{C}\).
- The formula to convert this to Fahrenheit is \( \text{°F} = \left(-39 \times \frac{9}{5} \right) + 32 \).
- After doing the math: \(-70.2 + 32 \) results in a freezing point of \(-38.2^{\circ} \text{F}\).
Boiling Point
The boiling point is the temperature at which a liquid becomes a gas.
For water, this is 100°C or 212°F, but radiator coolant is designed to withstand much higher temperatures, boiling at 110°C.
For water, this is 100°C or 212°F, but radiator coolant is designed to withstand much higher temperatures, boiling at 110°C.
- We convert this to Fahrenheit using the formula \( \text{°F} = \left(110 \times \frac{9}{5} \right) + 32 \).
- Calculating gives us a Fahrenheit boiling point of \(198 + 32\), which equals \(230^{\circ} \text{F}\).
Other exercises in this chapter
Problem 77
Can a temperature in "C ever have the same value in "F?
View solution Problem 78
What is meant by an absolute temperature scale?
View solution Problem 80
Silver and gold melt at \(962^{\circ} \mathrm{C}\) and \(1064^{\circ} \mathrm{C},\) respectively. Convert these two temperatures to the Kelvin scale.
View solution Problem 81
Critical Temperature The discovery of new "high temperature" superconducting materials in the mid-1980s spurred a race to prepare the material with the highest
View solution