Problem 79
Question
Perform the indicated operations. Simplify the result, if possible. $$\left(\frac{1}{a^{3}-b^{3}} \cdot \frac{a c+a d-b c-b d}{1}\right)-\frac{c-d}{a^{2}+a b+b^{2}}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \[\frac{a c+a d-b c-b d}{a^3-b^3} - \frac{c-d}{a^2+a b+b^2}\].
1Step 1: Simplify First Fraction
We start by simplifying the first fraction. This involves dividing \((a c+a d-b c-b d)\) by 1. This just gives us \((a c+a d-b c-b d)\). So, the first fraction simplifies to \(\frac{a c+a d-b c-b d}{a^3-b^3}\).
2Step 2: Simplify Second Fraction
The second fraction is already in simplest form, so we can move to the next step.
3Step 3: Perform Subtraction
Now we just subtract our second fraction from the first. This gives us our final answer: \[\frac{a c+a d-b c-b d}{a^3-b^3} - \frac{c-d}{a^2+a b+b^2}\]
Other exercises in this chapter
Problem 79
Factor completely, or state that the polynomial is prime. $$x^{3}+2 x^{2}-4 x-8$$
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In Exercises \(75-82,\) add or subtract terms whenever possible. $$\sqrt[3]{54 x y^{3}}-y \sqrt[3]{128 x}$$
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In Exercises 67–82, find each product. $$(3 x+5 y)(3 x-5 y)$$
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