Problem 79
Question
In Exercises \(75-86\), simplify the expression. $$ \left(7 y^{2}\right)(-3 y) $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( -21y^{3} \).
1Step 1: Multiplication of Coefficients
Start by multiplying the coefficients (numbers in front of the variables) of the two operands, which are 7 and -3. This gives us -21.
2Step 2: Multiplication of Variables
Next, multiply the variable parts together. We have \(y^{2}\) from the first expression and \(y\) from the second expression. By the rule of exponents, when multiplying powers of the same base, you can add the exponents. In this case, 2 + 1 = 3. Hence, \( y^{2} \times y = y^{3} \).
3Step 3: Put it all together
Finally, combine the produced coefficient and variable to give the simplified expression. Thus, \( (7y^{2})(-3y) = -21y^{3} \).
Key Concepts
Multiplication of PolynomialsExponent RulesAlgebraic Expressions
Multiplication of Polynomials
When multiplying polynomials, each term in one polynomial is multiplied by every term in the other polynomial. Polynomials are similar to numerical expressions, but they include variables as well. In this case, we're working with the two terms \(7y^2\) and \(-3y\).
For multiplication:
For multiplication:
- Start by multiplying the coefficients: 7 and -3. The result is \(-21\).
- Multiply the variable portions, taking into account their exponents: \(y^2\) and \(y\).
- Combine these results to form a single algebraic expression.
Exponent Rules
Exponents signify how many times a number, known as the base, is multiplied by itself. Here, our key rule for simplifying polynomials is when multiplying like bases, we add the exponents.
Let's look at the \(y^2\) and \(y^1\) present in our exercise:
Let's look at the \(y^2\) and \(y^1\) present in our exercise:
- \(y^2\) means \(y \times y\).
- \(y^1\) means just \(y\).
- Add their exponents: \(2 + 1 = 3\). Thus, \(y^2 \times y = y^3\).
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations. Our focus on these allows for representing complex relationships in a simplified manner.
In this problem, consider the expression \((7y^2)(-3y)\). It is made up of:
The primary goal when working with algebraic expressions is simplification – making expressions easier to work with and understand. Grasping the relationships between the components through the use of multiplication and exponent rules simplifies our analysis and provides clear solutions.
In this problem, consider the expression \((7y^2)(-3y)\). It is made up of:
- Numeric coefficients: 7 and -3.
- Variables with exponents: \(y^2\) and \(y\).
The primary goal when working with algebraic expressions is simplification – making expressions easier to work with and understand. Grasping the relationships between the components through the use of multiplication and exponent rules simplifies our analysis and provides clear solutions.
Other exercises in this chapter
Problem 78
In Exercises 77-80, evaluate the algebraic expression for the given values of the variable(s). Distance Traveled \(r t\) (a) \(r=50, t=3.5\) (b) \(r=35, t=4\)
View solution Problem 79
In Exercises 79-84, evaluate the expression. \((-6)(-13)\)
View solution Problem 79
In Exercises 77-80, evaluate the algebraic expression for the given values of the variable(s). Volume of a Rectangular Prism lwh (a) \(l=4, w=2, h=9\) (b) \(l=1
View solution Problem 80
In Exercises 79-84, evaluate the expression. $$ |4(-6)(5)| $$
View solution