Problem 79
Question
In Exercises \(75-82,\) compute the discriminant. Then determine the number and type of solutions for the given equation. $$ x^{2}-2 x+1=0 $$
Step-by-Step Solution
Verified Answer
The discriminant is 0. Hence, the equation has exactly one real solution.
1Step 1: Identifying a, b, c values
For a quadratic equation in the form \(ax^{2} + bx + c = 0\), identify the coefficients \(a, b, c\). Here, \(a=1, b = -2, c = 1 \)
2Step 2: Compute the discriminant
The discriminant is given by \(b^{2}-4ac\). Subsitute \(a, b, c\) values into the discriminant formula: \((-2)^{2} - 4*1*1 = 4 - 4 = 0\). The discriminant is 0.
3Step 3: Identify the type and number of solutions
As the discriminant is 0, the quadratic equation has exactly one real solution.
Key Concepts
Quadratic Equation SolutionsDiscriminant FormulaReal and Complex Solutions
Quadratic Equation Solutions
A quadratic equation is a polynomial equation of degree two. It typically takes the form \(ax^2 + bx + c = 0\), where \(a, b,\) and \(c\) are constants. Solving a quadratic equation means finding the values of \(x\) that make the equation true. These values are called the solutions or roots of the equation. The solutions to a quadratic equation can be found using several methods:
- Factoring, if the equation can easily be factored into two binomial expressions.
- Completing the square, which involves rearranging the equation and making a perfect square trinomial.
- The quadratic formula, \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), which is derived from completing the square and works for any quadratic equation.
Discriminant Formula
The discriminant is a crucial component in determining the nature and number of solutions to a quadratic equation. Given a quadratic equation in the form \(ax^2 + bx + c = 0\), the discriminant is defined as \(\Delta = b^2 - 4ac\). Calculating the discriminant involves simply substituting the coefficients \(a, b,\) and \(c\) into this formula. The value of the discriminant tells you:
- If \(\Delta > 0\), the quadratic equation has two distinct real solutions. This occurs because the square root of a positive number is real and has two values (positive and negative).
- If \(\Delta = 0\), there is exactly one real solution. The roots are the same, hence called a repeated root.
- If \(\Delta < 0\), the equation has no real solutions but has two complex solutions. This is because the square root of a negative number involves imaginary numbers.
Real and Complex Solutions
The solutions of a quadratic equation are greatly influenced by the value of the discriminant, \(\Delta = b^2 - 4ac\). They can be either real or complex, depending on whether \(\Delta\) is positive, zero, or negative. **Real Solutions**
- When \(\Delta > 0\), the equation has two different real solutions. This means you find two distinct x-values that satisfy the equation.
- If \(\Delta = 0\), the equation has one real solution. In this case, the parabola touches the x-axis at exactly one point, indicating a repeated or double root.
- When \(\Delta < 0\), the equation does not intersect the x-axis, meaning no real x-values solve the equation. Instead, the solutions are complex (or imaginary) and come in conjugate pairs, e.g., \(a + bi\) and \(a - bi\).
Other exercises in this chapter
Problem 78
Combine the types of equations we have discussed in this section. Solve each equation. Then state whether the equation is an identity, a conditional equation, o
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Exercises \(78-80\) will help you prepare for the material covered in the next section. Factor: \(x^{2}-6 x+9\)
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Solve each absolute value inequality. $$3|x-1|+2 \geq 8$$
View solution Problem 79
Combine the types of equations we have discussed in this section. Solve each equation. Then state whether the equation is an identity, a conditional equation, o
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