Problem 79
Question
In Exercises \(75-80,\) you will use a CAS to help find the absolute extrema of the given function over the specified closed interval. Perform the following steps. $$\begin{array}{l}{\text { a. Plot the function over the interval to see its general behavior there. }} \\ {\text { b. Find the interior points where } f^{\prime}=0 . \text { (In some exercises, }} \\ {\text { you may have to use the numerical equation solver to approximate }} \\ {\text { a solution.) You may want to plot } f^{\prime} \text { as well. }}\\\\{\text { c. Find the interior points where } f^{\prime} \text { does not exist. }} \\ {\text { d. Evaluate the function at all points found in parts (b) and (c) }} \\ {\text { and at the endpoints of the interval. }} \\ {\text { e. Find the function's absolute extreme values on the interval }} \\ {\text { and identify where they occur. }}\end{array}$$ $$ f(x)=\sqrt{x}+\cos x, \quad[0,2 \pi] $$
Step-by-Step Solution
VerifiedKey Concepts
Critical points
For a function \( f(x) \), finding critical points involves calculating \( f'(x) \) and solving \( f'(x) = 0 \). These solutions give us the values where the slope of the tangent to the curve is horizontal.
Critical points can be:
- Local maxima - peaks in the graph.
- Local minima - troughs in the graph.
- Points of inflection - where the curve changes concavity.
Derivative
The derivative, denoted as \( f'(x) \), is calculated to understand how the function behaves locally. It helps identify increasing or decreasing trends and critical points.
For instance, in our exercise, the derivative of the function \( f(x) = \sqrt{x} + \cos x \) is \( f'(x) = \frac{1}{2\sqrt{x}} - \sin x \). This derivative helps in finding where the slope of the function is zero (i.e., critical points) or where the slope becomes undefined.
Calculus relies heavily on derivatives for:
- Graphing function shape and slope.
- Optimizing functions by finding maxima and minima.
- Analyzing motion and changes in physics and engineering.
Absolute extrema
Unlike local extrema, which only considers nearby points, absolute extrema are the definitive highest or lowest points over the entire interval.
To find the absolute extrema:
- Calculate \( f(x) \) at critical points.
- Check values at all endpoints of the interval.
Absolute extrema are vital in applications like:
- Determining maximum profits or losses.
- Finding optimal dimensions for minimal material use in engineering.
Closed interval
Solving problems on closed intervals often means evaluating function behavior at both endpoints, alongside any critical points identified within the interval. This approach ensures the comprehensive analysis necessary to locate maximum or minimum values, ensuring the function’s absolute extrema are addressed.
Closed intervals resemble a summary of all values the function can take within the specified domain, offering:
- A complete picture of a function’s behavior.
- Precise calculations by including boundaries.
Plotting functions
In our exercise, plotting \( f(x) = \sqrt{x} + \cos x \) over the interval \([0, 2\pi]\) helps visualize how the function behaves, offering insights into where it reaches peaks or valleys.
Benefits of plotting functions include:
- Immediate visual understanding of critical and extrema points.
- Aid in identifying periodic behavior, symmetry, or asymmetry.