Problem 79
Question
In Exercises 59–94, solve each absolute value inequality. $$ 3|x-1|+2 \geq 8 $$
Step-by-Step Solution
Verified Answer
The solution to the inequality \(3|x-1|+2 \geq 8\) is \(x \leq -1\) or \(x \geq 3\).
1Step 1: Isolate the absolute value
Subtract 2 from both sides of the inequality to isolate the absolute value on one side. This gives: \(3|x-1| \geq 6\).
2Step 2: Remove the coefficient from the absolute value
Divide both sides by 3 to remove the coefficient from the absolute value. This gives: \(|x-1| \geq 2\).
3Step 3: Create two equations
Create two inequalities, turning the absolute value into a positive and a negative instance. This results in: \(x - 1 \geq 2\) and \(x - 1 \leq -2\).
4Step 4: Solve the first inequality
Solving for \(x\) in the first inequality \(x - 1 \geq 2\), gives \(x \geq 3\).
5Step 5: Solve the second inequality
Solving for \(x\) in the second inequality \(x - 1 \leq -2\), gives \(x \leq -1\).
Key Concepts
Solving Absolute Value InequalitiesUnderstanding and Manipulating Algebraic ExpressionsFinding the Inequality Solutions
Solving Absolute Value Inequalities
To solve absolute value inequalities, the key is to isolate the absolute value expression before proceeding with other steps. An absolute value inequality involves expressions like \(|x-1|\), which represent the distance from zero on a number line, making it always non-negative. Here's the process:
- Isolate the Absolute Value: Remove any constants or coefficients outside the absolute value first. In our given problem \(3|x-1| + 2 \geq 8\), subtract 2 to begin isolating the absolute value, resulting in \(3|x-1| \geq 6\).
- Divide by the Coefficient: If there's a coefficient next to the absolute value, divide it away. Continue with \(|x-1| \geq 2\).
Understanding and Manipulating Algebraic Expressions
Algebraic expressions are key in setting up the inequalities for solving. These expressions, like \(x-1\), need manipulation so that you can properly set up for solving inequalities:
- Breaking into Two Cases: When dealing with expressions inside an absolute value, like \(|x-1| \geq 2\), you split it into two separate inequalities. This uses the definition that absolute values measure distance from zero, thus requiring a positive and negative scenario.
- Setting Up Equations: Thus, solving \(|x-1| \geq 2\) requires setting \(x-1 \geq 2\) and \(x-1 \leq -2\). This makes sure you capture the full range of possible solutions for \(x\).
Finding the Inequality Solutions
Once the absolute value is isolated and the corresponding algebraic expressions created, you proceed to find solutions to each inequality. Solving the inequalities offers clarity towards finding the range within which the variable fits:
- Solving Each Inequality: Take each separated inequality and solve individually. For \(x-1 \geq 2\), add 1 on both sides to get \(x \geq 3\). Similarly, solve \(x-1 \leq -2\), leading to \(x \leq -1\).
- Analyzing Results: The solutions \(x \geq 3\) and \(x \leq -1\) can then be combined to form the complete solution set for the original inequality. However, notice that no numbers can be simultaneously greater than or equal to 3 and less than or equal to -1, indicating a possible range or non-existent solution depending on your context.
Other exercises in this chapter
Problem 78
Exercises \(78-80\) will help you prepare for the material covered in the next section. Factor: \(2 x^{2}+7 x-4\)
View solution Problem 78
Combine the types of equations we have discussed in this section. Solve equation. Then state whether the equation is an identity, a conditional equation, or an
View solution Problem 79
Compute the discriminant. Then determine the number and type of solutions for the given equation. $$ x^{2}-2 x+1=0 $$
View solution Problem 79
Exercises \(78-80\) will help you prepare for the material covered in the next section. Factor: \(x^{2}-6 x+9\)
View solution