Problem 79
Question
For the following exercises, graph \(y=x^{3}\) on the given viewing window. Determine the corresponding range for each viewing window. Show each graph. $$[-0.1,0.1]$$
Step-by-Step Solution
Verified Answer
The range for the window \([-0.1, 0.1]\) is \([-0.001, 0.001]\).
1Step 1: Understand the Function
The function we are given is a cubic function, \( y = x^3 \). This function has a unique characteristic: it is symmetric about the origin and increases/decreases rapidly as \( x \) moves away from zero.
2Step 2: Determine the Viewing Window
We're working with a viewing window of \([-0.1, 0.1]\), which means we will graph the function for values of \( x \) from \(-0.1\) to \(0.1\).
3Step 3: Calculate Values in the Window Range
Evaluate \( y = x^3 \) at key points within the given range. For example, at \( x = -0.1 \), \( y = (-0.1)^3 = -0.001 \). At \( x = 0 \), \( y = 0^3 = 0 \). And at \( x = 0.1 \), \( y = (0.1)^3 = 0.001 \).
4Step 4: Determine the Range
Based on the values calculated, the range of \( y \) for \( x \) in the viewing window \([-0.1, 0.1]\) is \(-0.001 \leq y \leq 0.001\).
5Step 5: Graph the Function
Plot the calculated points to sketch the graph of \( y = x^3 \) within the window \([-0.1, 0.1]\). The curve will be very shallow, showing a slight increase from left to right, passing through the origin.
Key Concepts
Graphing FunctionsRange of a FunctionSymmetric About the Origin
Graphing Functions
Graphing functions involves visually representing mathematical relationships on a coordinate plane. When we graph a function like \( y = x^3 \), we're interested in how the variable \( y \) changes as \( x \) moves across a specified interval. Here, we focus on the interval \([-0.1, 0.1]\), an incredibly small range. This choice helps us observe that cubic functions, although typically known for steep, S-shaped curves, can appear flat when zoomed in tightly.
- Graphing begins with selecting key points; in this example, \( x = -0.1, 0, \text{ and } 0.1 \).
- We calculate the corresponding \( y \) values using the equation \( y = x^3 \).
- With these points, the graph is plotted, sketching a gentle curve that passes right through the origin due to the symmetry of cubic functions.
Range of a Function
The range of a function is the set of possible output values \( y \) it can produce. For the cubic function \( y = x^3 \), when viewed across the interval \([-0.1, 0.1]\), its range is determined by the smallest and largest \( y \) values it achieves.This involves calculating the function at critical points:
- When \( x = -0.1 \), \( y = (-0.1)^3 = -0.001 \).
- As \( x = 0 \), \( y = 0^3 = 0 \).
- For \( x = 0.1 \), \( y = (0.1)^3 = 0.001 \).
Symmetric About the Origin
A function symmetric about the origin can be rotated 180 degrees around the origin point and remain unchanged. This property is termed "odd symmetry." For cubic functions like \( y = x^3 \), this inherent symmetry is evident because for every point \((x, y)\), there is a corresponding point \((-x, -y)\).
- Odd functions satisfy the condition \( f(-x) = -f(x) \).
- For \( y = x^3 \), substituting \(-x\) gives \((-x)^3 = -x^3\), demonstrating its symmetry.
- Graphically, this reflects as a balance between the function's rising segment in the positive \( x \) direction and its falling segment in the negative \( x \) direction.
Other exercises in this chapter
Problem 79
Use the functions \(f(x)=2 x^{2}+1\) and \(g(x)=3 x+5\) to evaluate or find the composite function as indicated. $$ (g \circ g)(x) $$
View solution Problem 79
For the following exercises, use the functions \(f(x)=2 x^{2}+1\) and \(g(x)=3 x+5\) to evaluate or find the composite function as indicated. $$(g \circ g)(x)$$
View solution Problem 80
Use \(f(x)=x^{3}+1\) and \(g(x)=\sqrt[3]{x-1}\). Find \((f \circ g)(x)\) and \((g \circ f)(x)\). Compare the two answers.
View solution Problem 80
For the following exercises, use \(f(x)=x^{3}+1\) and \(g(x)=\sqrt[3]{x-1}\). Find \((f \circ g)(x)\) and \((g \circ f)(x)\) . Compare the two answers.
View solution