Problem 79
Question
Exer. 57-80: Simplify the expression, and rationalize the denominator when appropriate. $$ \sqrt[3]{3 t^{4} v^{2}} \sqrt[3]{-9 t^{-1} v^{4}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(-3 t v^{2}\).
1Step 1: Simplify Each Radicand
Start by simplifying each cube root individually. For the first radicand, we have \( \sqrt[3]{3 t^{4} v^{2}} \), which is just \( 3 t^{4} v^{2} \). The second radicand is \( \sqrt[3]{-9 t^{-1} v^{4}} \), which is \( -9 t^{-1} v^{4} \).
2Step 2: Multiply the Radicands
Multiply the simplified expressions inside each cube root: \( (3 t^{4} v^{2}) \times (-9 t^{-1} v^{4}) = -27 t^{3} v^{6} \).
3Step 3: Simplify the Cube Root of the Product
Take the cube root of the resulting product: \( \sqrt[3]{-27 t^{3} v^{6}} \). Since \(-27 = (-3)^3\), \(t^3 = (t)^3\), and \(v^6 = (v^2)^3\), the cube root simplifies to \(-3 t v^{2}\).
4Step 4: State the Simplified Expression
Combine the results from previous steps. The expression simplifies to \(-3 t v^{2}\).
Key Concepts
Cube RootsRationalizing DenominatorsMultiplying ExpressionsPolynomial Expressions
Cube Roots
Understanding cube roots involves identifying a number that, when multiplied by itself twice, results in the original number. In mathematical terms, the cube root of a number \(a\) is a number \(b\) such that \(b^3 = a\).
Cube root simplifies handling expressions involving special powers. It's symbolized as \(\sqrt[3]{x}\). Let's break down the expression:
Cube root simplifies handling expressions involving special powers. It's symbolized as \(\sqrt[3]{x}\). Let's break down the expression:
- Given the cube root \( \sqrt[3]{3 t^4 v^2} \), you leave the expression as it is since it's already under a cube root.
- Similarly, \( \sqrt[3]{-9 t^{-1} v^4} \) remains in its cube root form in the problem.
Rationalizing Denominators
Rationalizing the denominator involves eliminating any radicals in the denominator of a fraction. While the initial problem doesn't directly involve fractions with cube roots in the denominator, this concept is crucial when cube roots appear in denominators. To rationalize denominators involving cube roots:
- You multiply both the numerator and the denominator by the appropriate factor to ensure the radical disappears from the denominator.
- For cube roots, specifically, multiply by the cube of a number to simplify and remove the radical from the denominator.
Multiplying Expressions
Multiplying expressions involves combining like terms and simplifying the product. For the expression \(\sqrt[3]{3 t^4 v^2} \times \sqrt[3]{-9 t^{-1} v^4}\), start by multiplying the contents inside the cube roots.
- The general rule is to multiply coefficients together, which in this case is \(3\times(-9) = -27\).
- Add the exponents of like bases, giving \(t^{4+(-1)}=t^3\).
- For \(v\), add the exponents: \(v^{2+4}=v^6\).
Polynomial Expressions
Polynomials are mathematical expressions that involve a sum of powers in one or more variables multiplied by coefficients. Each separate term in a polynomial is a monomial, which consists of a coefficient and variables raised to non-negative integers.
In our exercise, the expression "\(-27t^3v^6\)" from multiplication of cube root expressions behaves like a polynomial, although it is a single term.
In our exercise, the expression "\(-27t^3v^6\)" from multiplication of cube root expressions behaves like a polynomial, although it is a single term.
- When simplifying polynomials under radicals, the key is simplifying each factor's power separately.
- Once simplified from cube roots to whole numbers (like \(-3t v^2\)), it becomes easier to manage and understand.
Other exercises in this chapter
Problem 78
Exer. 57-80: Simplify the expression, and rationalize the denominator when appropriate. $$ \sqrt{5 x y^{7}} \sqrt{10 x^{3} y^{3}} $$
View solution Problem 79
Factor the polynomial. $$ 64 x^{3}-y^{6} $$
View solution Problem 80
Factor the polynomial. $$ 216 x^{9}+125 y^{3} $$
View solution Problem 80
Exer. 57-80: Simplify the expression, and rationalize the denominator when appropriate. $$ \sqrt[3]{(2 r-s)^{3}} $$
View solution