Problem 79
Question
Equal quantities of \(0.010 \mathrm{M}\) solutions of an acid \(\mathrm{HA}\) and a base \(B\) are mixed. The \(p H\) of the resulting solution is 9.2. (a) Write the equilibrium equation and equilibriumconstant expression for the reaction between \(\mathrm{HA}\) and \(\mathrm{B}\). (b) If \(K_{a}\) for HA is \(8.0 \times 10^{-5}\), what is the value of the equilibrium constant for the reaction between HA and B? (c) What is the value of \(K_{b}\) for \(B\) ?
Step-by-Step Solution
Verified Answer
The equilibrium equation for the reaction between HA and B is: \(HA + B \rightleftharpoons A^- + HB\). The value of the equilibrium constant for the reaction between HA and B is 12.67. The value of \(K_b\) for B is \(1.25 \times 10^{-10}\).
1Step 1: Write the equilibrium equation and equilibrium constant expression for the reaction between HA and B.
The reaction between the weak acid HA and the weak base B can be represented as:
\[HA + B \rightleftharpoons A^- + HB\]
Since the weak acid HA ionizes as:
\[HA \rightleftharpoons H^+ + A^-\]
It has the acid dissociation constant \(K_a\), given by:
\[K_a = \frac{[H^+][A^-]}{[HA]}\]
Similarly, the weak base B ionizes as:
\[B + H_2O \rightleftharpoons HB^+ + OH^-\]
It has the base dissociation constant \(K_b\), given by:
\[K_b = \frac{[HB^+][OH^-]}{[B]}\]
2Step 2: Calculate the concentration of HA and A- after the reaction occurs.
The initial concentrations of HA and B are both 0.010 M. Since equal quantities of HA and B are mixed, the reaction will proceed to completion. This means that the final concentration of A- and HB will be equal to the initial concentration of HA and B:
\[[A^-] = [HB] = 0.010\text{ M}\]
Since the pH of the resulting solution is 9.2, we can find the concentration of H+:
\[[H^+] = 10^{-pH} = 10^{-9.2} = 6.31 \times 10^{-10}\text{ M}\]
3Step 3: Calculate the value of the equilibrium constant for the reaction between HA and B.
Since we have the value of \(K_a\) and the concentrations of the species involved, we can solve for the equilibrium constant expression. We can rearrange the Ka expression to find the concentration of HA:
\[[HA] = \frac{[H^+][A^-]}{K_a}\]
Plugging in the values, we get:
\[[HA] = \frac{(6.31 \times 10^{-10})(0.010)}{8.0 \times 10^{-5}} = 7.89 \times 10^{-6}\text{ M}\]
Now, we can find the equilibrium constant for the reaction between HA and B, which can be written as:
\[K_{eq} = \frac{[A^-][HB]}{[HA][B]}\]
Substituting the values, we get:
\[K_{eq} = \frac{(0.010)(0.010)}{(7.89\times 10^{-6})(0.010)} = 12.67\]
4Step 4: Find the value of Kb for B.
Since \(K_a \times K_b = K_w\) (where \(K_w\) is the ion product constant of water), we can find the value of Kb for B:
\[K_b = \frac{K_w}{K_a}\]
Since \(K_w\) is \(1.0 \times 10^{-14}\), we have:
\[K_b = \frac{1.0 \times 10^{-14}}{8.0 \times 10^{-5}} = 1.25 \times 10^{-10}\]
So, the value of Kb for B is \(1.25 \times 10^{-10}\).
Key Concepts
Acid-Base ReactionsEquilibrium ConstantpH Calculation
Acid-Base Reactions
Acid-base reactions are a fundamental concept in chemistry, where an acid and a base react in a neutralization process. When an acid, like HA (a weak acid), meets a base, such as B (a weak base), they interact to form their conjugate base and acid, respectively. This particular reaction can be represented as follows:
Understanding the behavior of weak acid-weak base reactions is crucial for predicting pH changes in solutions, as the reaction does not completely neutralize pH but rather establishes an equilibrium governed by their respective dissociation constants, \(K_a\) for the acid and \(K_b\) for the base.
- \[HA + B \rightleftharpoons A^- + HB\]
Understanding the behavior of weak acid-weak base reactions is crucial for predicting pH changes in solutions, as the reaction does not completely neutralize pH but rather establishes an equilibrium governed by their respective dissociation constants, \(K_a\) for the acid and \(K_b\) for the base.
Equilibrium Constant
The equilibrium constant is a vital concept that indicates the ratio of concentrations of products to reactants at equilibrium. For acid-base reactions, such as between HA and B, the equilibrium constant \(K_{eq}\) can be expressed as:
For weak acids and bases, the values of \(K_a\) and \(K_b\) are relatively small, indicating limited dissociation. The relationship between \(K_a\) and \(K_b\) is particularly important when calculating ionization in water (\(K_w\)), following the equation:
- \[K_{eq} = \frac{[A^-][HB]}{[HA][B]}\]
For weak acids and bases, the values of \(K_a\) and \(K_b\) are relatively small, indicating limited dissociation. The relationship between \(K_a\) and \(K_b\) is particularly important when calculating ionization in water (\(K_w\)), following the equation:
- \(K_a \times K_b = K_w \)
pH Calculation
The pH measurement is an essential part of evaluating the acidity or basicity of a solution. Simply put, pH is calculated as the negative logarithm of the hydrogen ion concentration:
Understanding pH further aids in calculating other essential chemical properties and predicting behaviors of different chemical species in solution. In equilibrium and titration experiments, these calculations help students and scientists easily estimate reaction tendencies and outcomes. It is critical to remember the logarithmic nature of the pH scale as it means a small change in pH represents a significant shift in hydrogen ion concentration.
- \[pH = -\log [H^+]\]
Understanding pH further aids in calculating other essential chemical properties and predicting behaviors of different chemical species in solution. In equilibrium and titration experiments, these calculations help students and scientists easily estimate reaction tendencies and outcomes. It is critical to remember the logarithmic nature of the pH scale as it means a small change in pH represents a significant shift in hydrogen ion concentration.
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