Problem 79
Question
Complete the following multiplication and division problems in scientific notation. a. \(\left(4.8 \times 10^{5} \mathrm{km}\right) \times\left(2.0 \times 10^{3} \mathrm{km}\right)\) b. \(\left(3.33 \times 10^{-4} \mathrm{m}\right) \times\left(3.00 \times 10^{-5} \mathrm{m}\right)\) c. \(\left(1.2 \times 10^{6} \mathrm{m}\right) \times\left(1.5 \times 10^{-7} \mathrm{m}\right)\) d. \(\left(8.42 \times 10^{8} \mathrm{kL}\right) \div\left(4.21 \times 10^{3} \mathrm{kL}\right)\) e. \(\left(8.4 \times 10^{6} \mathrm{L}\right) \div\left(2.4 \times 10^{-3} \mathrm{L}\right)\) f. \(\left(3.3 \times 10^{-4} \mathrm{mL}\right) \div\left(1.1 \times 10^{-6} \mathrm{mL}\right)\)
Step-by-Step Solution
Verified Answer
a) \(9.6 \times 10^8\) km², b) \(9.99 \times 10^{-9}\) m², c) \(1.8 \times 10^{-1}\) m², d) \(2.00 \times 10^5\) kL, e) \(3.5 \times 10^9\) L, f) \(3.0 \times 10^2\) mL.
1Step 1: Multiplying Numbers
To solve part (a) \( (4.8 \times 10^5) \times (2.0 \times 10^3) \)First, multiply the decimal numbers:\(4.8 \times 2.0 = 9.6\)
2Step 2: Adding Exponents in Multiplication
Next, add the exponents of 10 when multiplying: \(5 + 3 = 8\)So, part (a) becomes: \(9.6 \times 10^8 \text{ km}^2\)
3Step 3: Multiplying Decimal Parts for Part b
For part (b), multiply the decimal parts:\(3.33 \times 3.00 = 9.99\)
4Step 4: Adding Exponents for Part b
Add the exponents in part (b):\(-4 + (-5) = -9\)So, part (b) is:\(9.99 \times 10^{-9} \text{ m}^2\)
5Step 5: Multiplying Decimal Parts for Part c
Multiply the decimal parts of the numbers in part (c):\(1.2 \times 1.5 = 1.8\)
6Step 6: Adding Exponents for Part c
Add the exponents for part (c):\(6 + (-7) = -1\)So, part (c) is:\(1.8 \times 10^{-1} \text{ m}^2\)
7Step 7: Dividing Decimal Parts for Part d
For division in part (d):\(8.42 \div 4.21 = 2.00\)
8Step 8: Subtracting Exponents in Division
Subtract the exponents for division in part (d):\(8 - 3 = 5\)So, part (d) is:\(2.00 \times 10^5 \text{ kL}\)
9Step 9: Dividing Decimal Parts for Part e
Divide the decimal numbers in part (e):\(8.4 \div 2.4 = 3.5\)
10Step 10: Subtracting Exponents for Part e
Subtract the exponents for part (e):\(6 - (-3) = 9\)So, part (e) is:\(3.5 \times 10^9 \text{ L}\)
11Step 11: Dividing Decimal Parts for Part f
Divide the decimal numbers in part (f):\(3.3 \div 1.1 = 3.0\)
12Step 12: Subtracting Exponents for Part f
Subtract exponents for part (f):\(-4 - (-6) = 2\)So, part (f) is:\(3.0 \times 10^2 \text{ mL}\)
Key Concepts
Multiplication and Division in Scientific NotationExponent RulesSignificant FiguresMetric UnitsMathematical Operations
Multiplication and Division in Scientific Notation
When dealing with large or small numbers, scientists often use scientific notation to simplify calculations. It involves expressing numbers as the product of a decimal and a power of ten, which makes multiplication and division easier. To multiply two numbers in scientific notation:
For division, divide the decimal parts and subtract the exponents. For instance, \[(8.42 \times 10^8) \div (4.21 \times 10^3)\]requires:
- Multiply the decimal parts.
- Add the exponents of the power of ten.
For division, divide the decimal parts and subtract the exponents. For instance, \[(8.42 \times 10^8) \div (4.21 \times 10^3)\]requires:
- Divide the decimal values: \[8.42 \div 4.21 = 2.00\]
- Subtract the exponents: \[8 - 3 = 5\]
Exponent Rules
Exponents play a crucial role in scientific notation, especially when performing mathematical operations like multiplication and division. There are a few key rules to remember:
- When multiplying similar bases, add their exponents: \( a^m \times a^n = a^{m+n} \).
- When dividing, subtract the exponents of the numerators and denominators: \( \frac{a^m}{a^n} = a^{m-n} \).
- Negative exponents indicate a reciprocal: \( a^{-n} = \frac{1}{a^n} \).
Significant Figures
Significant figures reflect the precision of a measurement or calculation. They include all notable digits in a number, which is crucial when handling scientific data. Here's how to determine significant figures:
- All non-zero digits are significant.
- Any zeros between significant digits are significant (e.g., \[ 1002 \]).
- Leading zeros are not significant (e.g., \[ 0.0032 \]).
- Trailing zeros are significant only if they are after a decimal point (e.g., \[ 5.00 \]).
Metric Units
Metric units form an essential part of scientific notation and measurement, providing a universally understood system of measurement. Understanding metric prefixes helps in working with diverse units. Common prefixes include:
- Kilo (\[ k \]) for \[ 10^3 \] (e.g., kilometer).
- Milli (\[ m \]) for \[ 10^{-3} \] (e.g., millimeter).
- Micro (\[ \mu \]) for \[ 10^{-6} \] (e.g., microliter).
Mathematical Operations
Mathematical operations like multiplication and division reappear across various scientific and real-world applications, frequently simplified using scientific notation. Here’s how to approach them effectively:
- Ensure that the operations follow the order: parentheses, exponents, multiplication and division (from left to right), addition and subtraction (PEMDAS/BODMAS).
- Accurately apply scientific notation rules for optimal results; this reduces complexity and error, especially in extensive calculations.
- Cross-check results to verify correctness, noting the consistency with significant figures and the appropriate use of units.
Other exercises in this chapter
Problem 76
Write the following numbers in scientific notation. a. 0.0045834 \(\mathrm{mm}\) \(\quad\) c. 438,904 \(\mathrm{s}\) b. 0.03054 \(\mathrm{g}\) \(\quad\) d. 7,00
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Write the following numbers in ordinary notation. a. \(8.348 \times 10^{6} \mathrm{km} \quad\) c. \(7.6352 \times 10^{-3} \mathrm{kg}\) b. \(3.402 \times 10^{3}
View solution Problem 80
Convert the following measurements. a. 5.70 g to milligrams \(\quad\) d. 45.3 \(\mathrm{mm}\) to meters b. 4.37 \(\mathrm{cm}\) to meters \(\quad\) e. 10 \(\mat
View solution Problem 81
Gold A troy ounce is equal to 480 grains, and 1 grain is equal to 64.8 milligrams. If the price of gold is $560 per troy ounce, what is the cost of 1 g of gold?
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