Problem 79
Question
\(9.3 \times 10^{3} \mathrm{~kg}+4.8 \times 10^{4} \mathrm{~kg}\)
Step-by-Step Solution
Verified Answer
57300 kg or \(5.73 \times 10^{4} \mathrm{~kg}\)
1Step 1 - Identify the Given Numbers
The given numbers are in scientific notation: \(9.3 \times 10^{3} \mathrm{~kg}\) and \(4.8 \times 10^{4} \mathrm{~kg}\).
2Step 2 - Convert to Standard Notation
Convert each number to standard notation to simplify the addition. \(9.3 \times 10^{3} = 9300\) kg\(4.8 \times 10^{4} = 48000\) kg
3Step 3 - Add the Numbers
Add the converted numbers: 9300 kg + 48000 kg = 57300 kg
4Step 4 - Convert Back to Scientific Notation
Convert the result back to scientific notation if necessary. 57300 kg in scientific notation is \(5.73 \times 10^{4} \mathrm{~kg}\).
Key Concepts
Addition in Scientific NotationConverting to Standard NotationElementary Algebra
Addition in Scientific Notation
Scientific notation is a way of writing very large or very small numbers in a compact form. It consists of a number between 1 and 10, multiplied by a power of 10.
When adding numbers in scientific notation, it is important to have the same power of 10 for both numbers. If the exponents are different, you need to adjust one or both numbers.
In our exercise, we have to add:
\(9.3 \times 10^{3} \text{ kg} + 4.8 \times 10^{4} \text{ kg}\).
Since the exponents are different (3 and 4), we convert these to standard notation first for simplicity.
When adding numbers in scientific notation, it is important to have the same power of 10 for both numbers. If the exponents are different, you need to adjust one or both numbers.
In our exercise, we have to add:
\(9.3 \times 10^{3} \text{ kg} + 4.8 \times 10^{4} \text{ kg}\).
Since the exponents are different (3 and 4), we convert these to standard notation first for simplicity.
Converting to Standard Notation
Converting from scientific notation to standard notation involves expanding the number.
For example:
\(9.3 \times 10^{3} \text{ kg}\) becomes 9300 kg and \(4.8 \times 10^{4} \text{ kg}\) becomes 48000 kg.
1. Multiply the coefficient (the number in front) by 10 raised to the power given.
2. \(9.3 \times 10^{3} = 9.3 \times 1000 = 9300 \text{ kg}\).
3. \(4.8 \times 10^{4} = 4.8 \times 10000 = 48000 \text{ kg}\).
Now, it is easier to add or subtract these numbers since they are in standard form.
For example:
\(9.3 \times 10^{3} \text{ kg}\) becomes 9300 kg and \(4.8 \times 10^{4} \text{ kg}\) becomes 48000 kg.
1. Multiply the coefficient (the number in front) by 10 raised to the power given.
2. \(9.3 \times 10^{3} = 9.3 \times 1000 = 9300 \text{ kg}\).
3. \(4.8 \times 10^{4} = 4.8 \times 10000 = 48000 \text{ kg}\).
Now, it is easier to add or subtract these numbers since they are in standard form.
Elementary Algebra
Elementary algebra helps with understanding and handling mathematical expressions.
In this case, we simply add the two numbers we converted to standard notation:
\( 9300 \text{ kg} + 48000 \text{ kg} = 57300 \text{ kg} \).
Next, we convert the sum back to scientific notation if required:
In this case, we simply add the two numbers we converted to standard notation:
\( 9300 \text{ kg} + 48000 \text{ kg} = 57300 \text{ kg} \).
Next, we convert the sum back to scientific notation if required:
- First, write the number as a product of a number between 1 and 10 and an appropriate power of 10.
- \(57300 \text{ kg}\) can be written as \(5.73 \times 10^{4} \text{ kg}\).
- Here, you move the decimal point 4 places to the left, adjusting the power of 10 accordingly.
Other exercises in this chapter
Problem 79
Problem: Simplify: \(\left(24 x^{3}+8 x^{2}-2 x\right) \div(4 x)\) Incorrect Answer: \(\frac{24 x^{3}+8 x^{2}-2 x}{4 x}\) $$ \begin{aligned} &=\frac{6 \cdot 4 \
View solution Problem 79
The length of one side of a triangle is \(a \mathrm{ft}\). The other sides of the triangle are \(4 \mathrm{ft}\) longer and \(3 \mathrm{ft}\) shorter than this
View solution Problem 79
\(\left(\frac{2 p}{3 q}\right)^{2}(4 p)^{2}\)
View solution Problem 80
Problem: Use long division to simplify \(\left(x^{2}-8 x+12\right) \div(x-4)\) Incorrect Answer: $$ \begin{array}{r} x - 4 \longdiv { x ^ { 2 } - 8 x + 1 2 } \\
View solution