Problem 78
Question
Solve by completing the square. \(n^{2}-2 n=-3\)
Step-by-Step Solution
Verified Answer
The solutions are \( n = 3 \) and \( n = -1 \).
1Step 1: Move the constant to the right side
Add 3 to both sides of the equation to move the constant term to the right side: \[ n^2 - 2n + 3 = 0 \]
2Step 2: Prepare to complete the square
Rearrange the equation to make it easier to complete the square: \[ n^2 - 2n = 3 \]
3Step 3: Add and subtract the square of half the coefficient of n
Take half of the coefficient of \( n \) (which is -2), square it (\( (-1)^2 = 1 \)), and add it to both sides: \[ n^2 - 2n + 1 = 3 + 1 \]This simplifies to: \[ n^2 - 2n + 1 = 4 \]
4Step 4: Write the left side as a perfect square
Write the left side of the equation as a square of a binomial: \[ (n - 1)^2 = 4 \]
5Step 5: Solve for n
Take the square root of both sides: \[ n - 1 = \text{±} 2 \]Then solve for \( n \): \[ n - 1 = 2 \] or \[ n - 1 = -2 \]This gives two solutions: \[ n = 3 \] and \[ n = -1 \]
Key Concepts
solving quadratic equationsalgebraic manipulationsperfect square trinomialsquare root property
solving quadratic equations
Quadratic equations are equations of the form \text{ax}^2 + bx + c = 0\text{ where a, b\text{,} and c are constants. Solving these types of equations means finding the values of \(x\) that satisfy the equation. Completing the square is one effective method to solve quadratic equations. It involves manipulating the equation to form a perfect square trinomial on one side. This allows us to easily solve for \(x\) using the square root property.
algebraic manipulations
Algebraic manipulations are fundamental to solving quadratic equations through completing the square. Here's a breakdown:
- First, move the constant term to the right side of the equation.
- Next, take half of the coefficient of the \(x\) term, square it, and add it to both sides of the equation. This ensures we form a perfect square trinomial on the left side.
- Finally, rewrite the trinomial as a square of a binomial, which simplifies solving by using the square root property.
perfect square trinomial
A perfect square trinomial is a quadratic expression that can be written as the square of a binomial. It has the form: \text{ax}^2 + 2abx + b^2 = (ax + b)^2 .
In the exercise, we transformed \(n^2 - 2n + 1\) into \((n - 1)^2\). This was achieved by
In the exercise, we transformed \(n^2 - 2n + 1\) into \((n - 1)^2\). This was achieved by
- Taking half of the coefficient of \(n\), which is \(-2\), giving us \(-1\).
- Squaring \(-1\) to get 1, and adding this to both sides of the equation.
square root property
The square root property is a useful tool when we have an equation in the form of \((x - k)^2 = p\).
It states that:
x - k = ±√p. Applying this to our example \((n - 1)^2 = 4\text{,} we,
Take the square root of both sides: n - 1 = ±2. Simplify the equation to find: n = 3 \text{,} and, n = -1. This gives us two potential solutions for \)n$, showing the versatility and simplicity of the square root property.
It states that:
x - k = ±√p. Applying this to our example \((n - 1)^2 = 4\text{,} we,
Take the square root of both sides: n - 1 = ±2. Simplify the equation to find: n = 3 \text{,} and, n = -1. This gives us two potential solutions for \)n$, showing the versatility and simplicity of the square root property.
Other exercises in this chapter
Problem 76
Solve by completing the square. \(y^{2}-2 y=8\)
View solution Problem 77
Solve by completing the square. \(m^{2}+4 m=-44\)
View solution Problem 79
Solve by completing the square. \(r^{2}+6 r=-11\)
View solution Problem 80
Solve by completing the square. \(t^{2}-14 t=-50\)
View solution