Problem 78
Question
\(\mathrm{CuSO}_{4}\) decolourizes on addition of KCN, the product is (a) \(\left[\mathrm{Cu}(\mathrm{CN})_{4}\right]^{2-}\) (b) \(\mathrm{Cu}^{2+}\) gets reduced to form \([\mathrm{Cu}(\mathrm{CN})]^{3-}\) (c) \(\mathrm{Cu}(\mathrm{CN})_{2}\) (d) \(\mathrm{CuCN}\)
Step-by-Step Solution
Verified Answer
The product is CuCN.
1Step 1: Understanding the Reaction
When \(Cu^{2+}\) from \(CuSO_4\) reacts with \(KCN\), a complex reaction occurs that leads to decolourization. This is because \(Cu^{2+}\) can form complexes with cyanide ions.
2Step 2: Determining Reduction and Complex Formation
In the presence of excess \(CN^-\), the \(Cu^{2+}\) ion from \(CuSO_4\) is reduced to \(Cu^+\). The reduction changes the oxidation state of copper from +2 to +1, and further forms a complex with cyanide ions.
3Step 3: Identifying the Complex Ion Formed
The reduced copper ion \(Cu^+\) forms a stable complex with four cyanide ions, resulting in the complex ion \([Cu(CN)_4]^{3-}\). However, taking into account stoichiometry and charge calculations, the most plausible immediate result due to decolourization is \(CuCN\).
4Step 4: Selecting the Correct Product
Based on chemical reactions and previous steps, the addition of \(KCN\) to \(CuSO_4\) in excess will produce \(CuCN\). Thus, among the given options, \(CuCN\) is the initial product responsible for the decolourization.
Key Concepts
Copper-Cyanide ComplexRedox ReactionComplex Ion Formation
Copper-Cyanide Complex
Copper compounds are known for their vibrant colors. However, when you mix copper sulfate (\(\mathrm{CuSO}_4\)) with potassium cyanide (\(\mathrm{KCN}\)), a fascinating reaction takes place that decolorizes the solution. This happens because of the formation of a copper-cyanide complex.
When copper sulfate interacts with potassium cyanide, the copper ions (\(\mathrm{Cu}^{2+}\)) are initially converted into copper(I) cyanide (\(\mathrm{CuCN}\)), which is less colorful.
Copper(I) cyanide is known to form a white precipitate, making the overall solution appear less colorful or colorless.
When copper sulfate interacts with potassium cyanide, the copper ions (\(\mathrm{Cu}^{2+}\)) are initially converted into copper(I) cyanide (\(\mathrm{CuCN}\)), which is less colorful.
Copper(I) cyanide is known to form a white precipitate, making the overall solution appear less colorful or colorless.
- The transformation occurs when copper ions try to find a stable form by bonding with cyanide ions. This leads to the formation of the less colorful \(\mathrm{CuCN}\).
- In excess cyanide conditions, further complex ions can form, such as \([\mathrm{Cu}(\mathrm{CN})_4]^{3-}\), but the primary step in the decolorization is the formation of \(\mathrm{CuCN}\).
Redox Reaction
A redox reaction is central to the process that occurs when \(\mathrm{CuSO}_4\) is added to \(\mathrm{KCN}\). In a redox reaction, one element undergoes oxidation while another undergoes reduction. In our scenario, copper plays the role of the element that is reduced.
Initially, copper is in a +2 oxidation state in \(\mathrm{CuSO}_4\).
Identifying such changes is crucial for predicting the final products of reactions similar to this one.
Initially, copper is in a +2 oxidation state in \(\mathrm{CuSO}_4\).
- The addition of cyanide ions (\(\mathrm{CN}^- \)) leads to the reduction of copper's oxidation state from +2 to +1.
- This is due to the transfer of electrons from cyanide to copper, enabling the conversion from \(\mathrm{Cu}^{2+}\) to \(\mathrm{Cu}^{+}\), resulting in the formation of \(\mathrm{CuCN}\).
Identifying such changes is crucial for predicting the final products of reactions similar to this one.
Complex Ion Formation
Complex ions are formed when a central metal ion bonds with surrounding non-metal ions or molecules, known as ligands. Cyanide ions are strong ligands that can interact with metals like copper to form complex ions.
When \(\mathrm{Cu}^{2+}\) is reduced to \(\mathrm{Cu}^{+}\), it can attract more cyanide ions to form a complex structure.
By understanding complex ion formation, students can grasp more advanced concepts in coordination chemistry and the reactions of transition metals.
When \(\mathrm{Cu}^{2+}\) is reduced to \(\mathrm{Cu}^{+}\), it can attract more cyanide ions to form a complex structure.
- Despite \(\mathrm{CuCN}\) being the initial product, in the presence of excess cyanide ions, \([\mathrm{Cu}(\mathrm{CN})_4]^{3-}\) may form as a complex ion.
- This transformation is characterized by the metal ion being surrounded by multiple cyanide ions, resulting in a more stabilized configuration.
By understanding complex ion formation, students can grasp more advanced concepts in coordination chemistry and the reactions of transition metals.
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