Problem 78
Question
\(\lim _{x \rightarrow 0}\left[\frac{a \sin x}{x}\right]+\left[\frac{b \tan x}{x}\right]\), where \(a, b\) are integers and [] denotes integral part, is equal to (A) \(a+b\) (B) \(a+\underline{b-1}\) (C) \(a-b\) (D) \(a-\underline{b-1}\)
Step-by-Step Solution
Verified Answer
(A) a + b
1Step 1: Understand Limit Property
For small values of \(x\), we have the limit property \(\lim_{x \to 0} \frac{\sin x}{x} = 1\) and \(\lim_{x \to 0} \frac{\tan x}{x} = 1\). This is because the sine and tangent functions are approximately equal to \(x\) when \(x\) is close to zero.
2Step 2: Apply the Limit Property
Using the limit properties from Step 1, for the given expression, we have \(\lim_{x \to 0} \frac{a \sin x}{x} = a \cdot 1 = a\) and \(\lim_{x \to 0} \frac{b \tan x}{x} = b \cdot 1 = b\).
3Step 3: Analyze the Integral Part
The expression given is in integer form, denoted by \([]\). For a limit that reaches exactly an integer, the integral part remains the integer. Hence, the integral of \(a\) is \(a\) and \(b\) is \(b\).
4Step 4: Combine the Results
Adding the integral parts gives \(a + b\). Thus, we check the answer choices: (A) \(a + b\), (B) \(a + b - 1\) underlines \(b-1\), (C) \(a - b\), (D) \(a - b + 1\). Choice (A) matches our computed value.
Key Concepts
Sine Limit PropertyTangent Limit PropertyIntegral Part of Function
Sine Limit Property
The sine limit property is a well-known concept in calculus that simplifies certain trigonometric limits. When examining the function \[ \lim_{x \to 0} \frac{\sin x}{x}, \] we find that as \(x\) approaches zero, the value approaches 1. This property becomes useful in solving problems involving limits, especially when the sine function is involved. Here's why:
- For very small \(x\), \(\sin x\) is closely approximated by \(x\).
- Thus, the division \(\frac{\sin x}{x}\) yields a result that approaches 1 as \(x\) nears zero.
Tangent Limit Property
Similar to the sine limit property, the tangent limit property is another simplifying tool in calculus. When analyzing:\[ \lim_{x \to 0} \frac{\tan x}{x}, \] an interesting thing happens. The result tends towards 1 as well. This is because:
- For small values of \(x\), \(\tan x\) is nearly equivalent to \(x\).
- This results in the expression \(\frac{\tan x}{x}\) approaching 1.
Integral Part of Function
The concept of the integral part of a function, often denoted by square brackets \([]\), refers to finding the greatest integer less than or equal to a given number. This is also known as the floor function. In mathematical notation, the integral part of \(x\) is expressed as \(\lfloor x \rfloor\). Some key points:
- The integral part is crucial in analyzing whole number results from limits and sums in calculus.
- For positive numbers, it simply "drops" any decimal portion, thereby ensuring the result is a whole number.
- In the context of limits, when the expression evaluates to exactly an integer, the integral part doesn't change.
Other exercises in this chapter
Problem 76
\(\lim _{x \rightarrow 0}\left(\frac{x-1+\cos x}{x}\right)^{1 / x}=\) (A) \(e^{1 / 2}\) (B) \(e^{-1 / 2}\) (C) \(e^{1 / 4}\) (D) None of these
View solution Problem 77
\(\lim _{x \rightarrow \infty}\left[\frac{e}{(1+1 / x)^{x}}\right]^{x}=\) (A) \(e\) (B) \(e^{-1}\) (C) \(e^{1 / 2}\) (D) \(e^{-1 / 2}\)
View solution Problem 79
\(\lim _{n \rightarrow \infty} \frac{[x]+[2 x]+[3 x]+\ldots+[n x]}{1+2+3+\ldots+n}=\) (A) \(x\) (B) \(2 x\) (C) 0 (D) None of these
View solution Problem 80
\(\lim _{n \rightarrow \infty} n^{2}\left(x^{1 / n}-x^{1 / n+1}\right), x>0\) is equal to (A) 0 (B) \(e^{x}\) (C) \(\ln x\) (D) None of these
View solution