Problem 78
Question
For the following exercises, graph the function and its reflection about the \(y\) -axis on the same axes, and give the \(y\) -intercept. $$h(x)=6(1.75)^{-x}$$
Step-by-Step Solution
Verified Answer
The \( y \)-intercept is 6.
1Step 1: Understand the function
The given function is \( h(x) = 6(1.75)^{-x} \). This is an exponential decay function, as indicated by the negative exponent. The base of the exponent is greater than 1, and the negative exponent implies decay as \( x \) increases.
2Step 2: Reflect the function
To find the reflection of the function about the \( y \)-axis, replace \( x \) with \( -x \). The reflection function is \( h(-x) = 6(1.75)^{x} \). This changes the function to an exponential growth function.
3Step 3: Find the y-intercept of h(x)
To find the \( y \)-intercept, evaluate \( h(x) \) when \( x = 0 \). This gives \( h(0) = 6(1.75)^{0} = 6 \times 1 = 6 \). So, the \( y \)-intercept of \( h(x) \) is 6.
4Step 4: Graph the functions
Graph \( h(x) = 6(1.75)^{-x} \), which is a decreasing function starting from \( y = 6 \) at \( x = 0 \), and approaches 0 as \( x \) increases. Graph the reflection \( h(-x) = 6(1.75)^{x} \), which is an increasing function starting from \( y = 6 \) at \( x = 0 \), increasing as \( x \) increases. Both graphs should clearly show the transformation about the \( y \)-axis and pass through the \( y \)-intercept at 6.
Key Concepts
Exponential DecayReflection About the Y-AxisY-Intercept
Exponential Decay
Exponential decay refers to a situation where quantities decrease rapidly at a consistent rate. In the function \(h(x) = 6(1.75)^{-x}\), the exponent \(-x\) is negative, which is a key indicator of decay. This means as \(x\) gets larger, the value of \(h(x)\) becomes smaller. Here's why:
- When \(x\) increases, \(1.75\) raised to a larger negative power becomes a smaller fraction.
- This results in \(h(x)\) decreasing towards zero, though it never actually reaches zero.
Reflection About the Y-Axis
Reflection about the y-axis is an interesting graph transformation. It involves flipping a given function across the y-axis, changing positive \(x\) coordinates to negative, and vice versa. For \(h(x) = 6(1.75)^{-x}\), the reflection is achieved through the transformation of \(x\) to \(-x\). This results in the function \(h(-x) = 6(1.75)^{x}\). Here are some key points about the reflection:
- The original function \(h(x)\) starts high and decays as \(x\) increases, reflecting about the y-axis leads to \(h(-x)\), which rises instead of falls for increasing positive \(x\).
- Graphically, this operation means all points that were on the right of y-axis in the original function now mirror to the left, creating a symmetrical graph that shows exponential growth.
Y-Intercept
The y-intercept represents the point where a graph crosses the y-axis. Every function that can touch the y-axis has a y-intercept, calculated by evaluating the function at \(x = 0\). For \(h(x) = 6(1.75)^{-x}\), the y-intercept can be easily calculated:
- When \(x = 0\), the expression \(1.75^{-0}\) simplifies to 1.
- This leaves us with \(h(0) = 6 \times 1 = 6\).
Other exercises in this chapter
Problem 76
For the following exercises, graph the function and its reflection about the \(y\) -axis on the same axes, and give the \(y\) -intercept. $$f(x)=3\left(\frac{1}
View solution Problem 77
For the following exercises, graph the function and its reflection about the \(y\) -axis on the same axes, and give the \(y\) -intercept. $$g(x)=-2(0.25)^{x}$$
View solution Problem 79
For the following exercises, graph each set of functions on the same axes. $$f(x)=3\left(\frac{1}{4}\right)^{x}, g(x)=3(2)^{x}, \text { and } h(x)=3(4)^{x}$$
View solution Problem 80
For the following exercises, graph each set of functions on the same axes. $$f(x)=\frac{1}{4}(3)^{x}, \quad g(x)=2(3)^{x}, \text { and } h(x)=4(3)^{x}$$
View solution