Problem 78
Question
For each of the given functions, graph \(f\) and \(f^{\prime}\) in the given viewing rectangle \(R .\) Fill in the following table. $$ \begin{array}{|l|l|l|} \hline \begin{array}{l} \text { Interval } \\ \text { where } f \\ \text { increases } \end{array} & \begin{array}{l} \text { Interval } \\ \text { where } f \\ \text { decreases } \end{array} & \begin{array}{l} \text { Point at which } f \text { has } \\ \text { a horizontal tangent } \end{array} \\ \hline & & \\ \hline \begin{array}{l} \text { Interval } \\ \text { where } f^{\prime}>0 \end{array} & \begin{array}{l} \text { Interval } \\ \text { where } f^{\prime}<0 \end{array} & \begin{array}{l} \text { Point(s) at } \\ \text { which } f^{\prime}=0 \end{array} \\ \hline & & \\ \hline \end{array} $$ Use the table to draw inferences that relate the sign of \(f^{\prime}\) to the behavior of \(f\). (These relationships will be studied in Chapter 4.) \(f(x)=x^{2} \sin (x) /\left(1+x+x^{4}\right), R=[-3,1.2] \times[-0.9,2.1]\)
Step-by-Step Solution
VerifiedKey Concepts
Derivative
In this specific case, we used the quotient rule for differentiation, which is essential when you have a division of two functions. The quotient rule states: if you have a function \( \frac{u(x)}{v(x)} \), its derivative is \( \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^2} \). By applying this rule, we isolate how each part contributes to the overall change of \( f(x) \). Calculating \( f'(x) \) for our given function involves differentiating the numerator and the denominator separately before combining them as the rule suggests.
Critical Points
When the derivative equals zero, the tangent to the curve is horizontal, indicating potential maxima or minima. Finding these points gives insight into the overall structure and behavior of the function. For complex functions like the one provided, finding these analytically may require setting complex calculations or numerical analysis using computational tools, due to the intricate nature of the derivative.
Function Behavior
The derivative provides information on the function's slope: where \( f'(x) > 0 \), the function is increasing, and where \( f'(x) < 0 \), it is decreasing. Studying how the derivative transitions from positive to negative, or vice versa, helps identify turning points and understand the overall shape of the graph. In this case, using the intervals from the original function, we can draw a detailed image of what the function does at various sections across the domain \([-3, 1.2]\).
- Increasing behavior indicates that the values of \(f(x)\) are getting larger as \(x\) increases.
- Decreasing behavior, conversely, shows that \(f(x)\) values are getting smaller.
Increasing and Decreasing Functions
To determine these intervals in the given problem, we calculate where the derivative is greater than or less than zero within the specified range \([-3, 1.2]\). Recognizing these points lets us fill out the table provided in the exercise, effectively charting where the function rises and falls. This understanding is pivotal in analyzing how outputs grow or shrink in response to changes in input, providing valuable insights into the nature of the function and predicting future behavior.